creating a function; scanf and char issues - c

Question

I am at the very initial stage of learning programming. I working with a program that uses self-made function. I don't understand my mistakes. I would be grateful for your help. Please, do me a favor and answer using methods that are commensurate with the primitive stage I am at. I am leaving comments I've written, so you can see what I am trying to achieve by this or that code line.
/* Prints a user's name */
#include <stdio.h>
#include <string.h>
// prototype
void PrintName(char name);
/* this is a hint for the C saying that this function will be later specified */
int main(void)
{
char name[50];
printf("Your name: ");
scanf ("%49s", name); /* limit the number of characters to 50 */
PrintName(name);
}
// Says hello to someone by name
void PrintName(char name)
{
printf("hello, %s\n", name);
}
I get these error messages:
function0.c: In function ‘main’:
function0.c:14: warning: passing argument 1 of ‘PrintName’ makes integer from pointer without a cast
function0.c: In function ‘PrintName’:
function0.c:21: warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘int’
function0.c:21: warning: format ‘%s’ expects type ‘char *’, but argument 2 has type ‘int’
The function PrintName is based on the previous program I took from the course (and adopted it to C):
#include <stdio.h>
#include <string.h>
int main (void)
{
char name[40];
printf ("Type a name: ");
scanf ("%39s", name);
printf ("%s", name);
printf("\n");
}
This last program works perfectly.
What mistake do I make in my original program? If I understand correctly, there is a problem with my PrintName function.
The initial program that prints a name is a modified version of CS50 program that uses CS50 library:
// Prints a user's name
#include <stdio.h>
#include <cs50.h>
// prototype
void PrintName(string name);
int main(void)
{
printf("Your name: ");
string s = GetString(); //GetString is the same as scanf; it takes input from the user
PrintName(s);
}
// Says hello to someone by name
void PrintName(string name)
{
printf("hello, %s\n", name);
}
Given "string" is "char" in C, I replace string with char in my program.
Thank you!

Answer 1

You should use char* instead of char, as an argument of your function. Char is one symbol, while char* is pointer to a string.

Answer 2

Your function PrintName is waiting for a char as parameter but you give a char[] that's why you see this :
warning: passing argument 1 of ‘PrintName’ makes integer from pointer without a cast
To give a char[] as parameter you need to change your function like this :
void PrintName(char *name);

Answer 3

Change void PrintName (char name); to void PrintName (char *name); or to void PrintName (char name[]);
Currently this function receives one character called name. You want it to receive an array of chars.

Answer 4

void PrintName(char name);
You function expects a character variable to be passed but instead you pass a char array. Thus it leads to error.
Moreover, %s in printf will expect a char * and you pass a char,thus leading to another problem.
To correct you program declare and define function with parameter as follows-
void PrintName(char *name);
or
void PrintName(char name[]);
Both will work.