I was just wondering that can we create a treeview in WPF without data binding?
You can manually declare your items in the xaml.
<TreeView x:Name="treeView" Margin="17,38,0,63" RenderTransformOrigin="0.5,0.5" HorizontalAlignment="Left" Width="238">
<TreeView.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform AngleY="0.567"/>
<RotateTransform/>
<TranslateTransform Y="0.495"/>
</TransformGroup>
</TreeView.RenderTransform>
<CheckBox Content="Item 1"/>
<CheckBox Content="Item 2"/>
</TreeView>
Related
I tried to add the wrapped the <Image with <border
I added
<Border BorderThickness="1">
And
</Border>
Then tried to wrapped the <Image like this :
<Border BorderThickness="1">
<Image x:Name="Img" HorizontalAlignment="Left" Height="233" Margin="467,54,0,0" VerticalAlignment="Top" Width="272" RenderTransformOrigin="0.5,0.5">
<Image.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform AngleY="0.704"/>
<RotateTransform/>
<TranslateTransform Y="0.614"/>
</TransformGroup>
</Image.RenderTransform>
</Image>
</Border>
But it does nothing when running the application.
In the designer on the main window I have a StackPanel and then on it the other controls also Image control.
I want to show the user that there is a Image control like pictureBox the problem is when running the program and the Image is still empty there is nothing that indicate that there is a Image control. That's why I want to draw a rectangle on the Image borders.
You need to pick a brush for your Border.
<Border BorderThickness="1" BorderBrush="Black">
<Image x:Name="Img" HorizontalAlignment="Left" Height="233" Margin="467,54,0,0" VerticalAlignment="Top" Width="272" RenderTransformOrigin="0.5,0.5">
<Image.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform AngleY="0.704"/>
<RotateTransform/>
<TranslateTransform Y="0.614"/>
</TransformGroup>
</Image.RenderTransform>
</Image>
</Border>
Actually, the method you applied is very close, since the picture will be in a border, it would be more logical to resize the border instead of resizing the picture. If you make an application like below, it will work for you.
<Border BorderThickness="2"
BorderBrush="Black"
VerticalAlignment="Center"
HorizontalAlignment="Center"
Height="128"
Width="128">
<Image HorizontalAlignment="Stretch"
VerticalAlignment="Stretch"
Stretch="Fill"
Source="/Images/antenna.png"/>
</Border>
It will be enough to have something like this in your application.
<Border BorderThickness="3" BorderBrush="Red" Height="233" Width="272">
<Image x:Name="Img" HorizontalAlignment="Left" Margin="467,54,0,0" VerticalAlignment="Top" RenderTransformOrigin="0.5,0.5">
<Image.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform AngleY="0.704"/>
<RotateTransform/>
<TranslateTransform Y="0.614"/>
</TransformGroup>
</Image.RenderTransform>
</Image>
</Border>
So I have successfully implemented a button click with a custom background. Here is the xaml:
<Button
HorizontalAlignment="Left"
Grid.Row="0"
Grid.Column="0"
Command="{Binding PreferencesClickedCmd}"
>
<Path
Data="..."
Stretch="Uniform"
Fill="#FF070707"
Width="16"
Height="16"
Margin="0,0,0,0"
RenderTransformOrigin="0.5,0.5"
>
<Path.RenderTransform>
<TransformGroup>
<TransformGroup.Children>
<RotateTransform Angle="0" />
<ScaleTransform ScaleX="1" ScaleY="1" />
</TransformGroup.Children>
</TransformGroup>
</Path.RenderTransform>
</Path>
</Button>
Now, is there a way to implement a click command with MVVM on Path object itself. What I am looking for to have only an icon portion to be clickable (with no help of button object). With button, the entire generated background rectangle can be clicked in order to trigger an event for the Path.
If you want only the filled Path area to be clickable, this will work (just swap in your own Path, transform, etc. stuff):
<Button
Command="{Binding PreferencesClickedCmd}"
>
<Button.Content>
<Path Data="M 8,0 L 0,16 L 16,0 Z" Fill="SlateBlue" />
</Button.Content>
<Button.Template>
<ControlTemplate TargetType="Button">
<ContentPresenter />
</ControlTemplate>
</Button.Template>
</Button>
The entire visual presentation of the button is replaced by just the content alone, and the parts of the button that aren't filled by the path are not clickable because they're transparent.
If you want the whole thing to be clickable, just give the template a background that's not quite transparent:
<ControlTemplate TargetType="Button">
<Grid Background="#01ffffff">
<ContentPresenter />
</Grid>
</ControlTemplate>
This is the MVVM Way of Doing Things: Button provides a Click event, and Command property, and some visual stuff; if all you want is the Click event and the Command Property, don't roll your own click event; use those parts of the Button while discarding the visual stuff.
As per Brandley suggestion, here is how I managed to implement it with minimal coding changes. I set the button size to match icon size, set the background to transparent and border width to 0:
<Button HorizontalAlignment="Left" Grid.Row="0" Grid.Column="0" Margin="5,0,0,0" Width="30" Height="30" BorderThickness="0" Background="Transparent" Command="{Binding PreferencesClickedCmd}">
<Path Data="..." Stretch="Uniform" Fill="#FF070707" Width="16" Height="16" Margin="0,0,0,0" RenderTransformOrigin="0.5,0.5">
<Path.RenderTransform>
<TransformGroup>
<TransformGroup.Children>
<RotateTransform Angle="0" />
<ScaleTransform ScaleX="1" ScaleY="1" />
</TransformGroup.Children>
</TransformGroup>
</Path.RenderTransform>
</Path>
</Button>
i am trying to make a ListBox that contains a string at right side of Item and one in left side i've tried this but those string become over each other.
<ListBox Name="ChaptersList" Height="200" Margin="10,10,10,0" VerticalAlignment="Top" SelectionChanged="ChaptersList_SelectionChanged" MouseDoubleClick="ChaptersList_MouseDoubleClick" RenderTransformOrigin="0.5,0.5" TextOptions.TextHintingMode="Animated">
<ListBox.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</ListBox.RenderTransform>
<ListBox.ItemTemplate>
<DataTemplate>
<Grid>
<Label Content="{Binding Path=Title}" VerticalAlignment="Center" Margin="5"/>
<Label Content="{Binding Path=Name}" HorizontalAlignment="Right" Margin="5"/>
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
(my first string should be multiline)
You can use Grid with two rows (where Height is set to Auto) and to text wrapping behaviour you must add ScrollViewer.HorizontalScrollBarVisibility="Disabled" property to ListBox.
<ListBox Name="ChaptersList"
Height="250" Margin="10,10,10,0" VerticalAlignment="Top" RenderTransformOrigin="0.5,0.5" TextOptions.TextHintingMode="Animated"
ScrollViewer.HorizontalScrollBarVisibility="Disabled"
>
<ListBox.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</ListBox.RenderTransform>
<ListBox.ItemTemplate>
<DataTemplate>
<Grid>
<Grid.RowDefinitions>
<RowDefinition Height="Auto" />
<RowDefinition Height="Auto" />
</Grid.RowDefinitions>
<TextBlock Grid.Row="0" Text="{Binding Path=Title}" TextWrapping="Wrap" HorizontalAlignment="Left" Margin="5"/>
<TextBlock Grid.Row="1" Text="{Binding Path=Name}" HorizontalAlignment="Right" Margin="5"/>
</Grid>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
Use StackPanel:
<ListBox Name="ChaptersList" Height="200" Margin="10,10,10,0" VerticalAlignment="Top" SelectionChanged="ChaptersList_SelectionChanged" MouseDoubleClick="ChaptersList_MouseDoubleClick" RenderTransformOrigin="0.5,0.5" TextOptions.TextHintingMode="Animated">
<ListBox.RenderTransform>
<TransformGroup>
<ScaleTransform/>
<SkewTransform/>
<RotateTransform/>
<TranslateTransform/>
</TransformGroup>
</ListBox.RenderTransform>
<ListBox.ItemTemplate>
<DataTemplate>
<StackPanel Orientation="Horizontal">
<Label Content="{Binding Path=Title}" VerticalAlignment="Center" Margin="5"/>
<Label Content="{Binding Path=Name}" HorizontalAlignment="Right" Margin="5"/>
</StackPanel>
</DataTemplate>
</ListBox.ItemTemplate>
</ListBox>
EDIT: i've found an easy solution: using Expression Blend end edit Template. it gives you a designer to adjust layouts.
i want to position the Expander button on the right side of the label. How to do this?
You can also set the FlowDirection to RightToLeft, but that may cause other problems. For example it also changes the flow direction for the content of the expander so you may need to set it back.
<Expander FlowDirection="RightToLeft">
<StackPanel FlowDirection="LeftToRight">
</StackPanel>
</Expander>
You must restyle the control's template. Here's an example: http://patconroy.wordpress.com/2008/12/18/restyling-the-wpf-expander-control/
Another way to approach this is to position the expander where you like, without any header or content in the expander itself.
Then bind the visibility of your content-control to the expanders IsExpanded property, using a BooleanToVisibilityConverter.
<StackPanel>
<StackPanel.Resources>
<BooleanToVisibilityConverter x:Key="boolToVisibility" />
</StackPanel.Resources>
<DockPanel>
<Expander DockPanel.Dock="Right" x:Name="rightAlignedExpander" />
<TextBlock Text="Expanders header" VerticalAlignment="Center" />
</DockPanel>
<Grid Visibility="{Binding IsExpanded, ElementName=rightAlignedExpander, Converter={StaticResource boolToVisibility}}">
<TextBlock Text="Expanders content"/>
</Grid>
</StackPanel>
The downside is that it will not expand when the header is clicked, but that could easily be implemented if necessary.
Personally I think this is more simple and straightforward instead of completely restyling the control's template. It also have the added benefit that it will keep any styles already applied to the expander, for example when using 3rd party themes like DevExpress or Telerik.
You can use tranform commands to flip the Controls
<Expander RenderTransformOrigin="0.5,0.5">
<Expander.RenderTransform>
<TransformGroup>
<ScaleTransform ScaleY="1" ScaleX="-1" />
<SkewTransform AngleY="0" AngleX="0" />
<RotateTransform Angle="0" />
<TranslateTransform />
</TransformGroup>
</Expander.RenderTransform>
<Expander.Header>
<Grid RenderTransformOrigin="0.5,0.5">
<Grid.RenderTransform>
<TransformGroup>
<ScaleTransform ScaleY="1" ScaleX="-1" />
<SkewTransform AngleY="0" AngleX="0" />
<RotateTransform Angle="0" />
<TranslateTransform />
</TransformGroup>
</Grid.RenderTransform>
<TextBlock>Text</TextBlock>
</Grid>
</Expander.Header>
<Grid Height="100" RenderTransformOrigin="0.5,0.5">
<Grid.RenderTransform>
<TransformGroup>
<ScaleTransform ScaleY="1" ScaleX="-1" />
<SkewTransform AngleY="0" AngleX="0" />
<RotateTransform Angle="0" />
<TranslateTransform />
</TransformGroup>
</Grid.RenderTransform>
<TextBlock>Text</TextBlock>
</Grid>
</Expander>
how "Stretch" property of Image in WPF effects Transforms ?
I found that Stretch property of image effets the transforms applied to it.
When stretch=fill, then everything is fine but if stretch=uniform, the transforms are chaged.
I not getting why this happening. Plz explain.
CODE:
<Canvas Height="200" Width="200">
<Image Height="50" Width="50" RenderTransformOrigin="0.5,0.5" Source="Image.jpg" Stretch="Fill">
<Image.RenderTransform>
<TransformGroup>
<RotateTransform Angle="200" />
<TranslateTransform X="100" Y="100"/>
</TransformGroup>
</Image.RenderTransform>
</Image>
<Rectangle Height="50" Width="50" RenderTransformOrigin="0.5,0.5" Fill="RoyalBlue" Opacity="0.5">
<Rectangle.RenderTransform>
<TransformGroup>
<RotateTransform Angle="200" />
<TranslateTransform X="100" Y="100"/>
</TransformGroup>
</Image.RenderTransform>
</Rectangle>
</Canvas>
<Canvas Height="200" Width="200">
<Image Height="50" Width="50" RenderTransformOrigin="0.5,0.5" Source="Image.jpg" Stretch="Uniform">
<Image.RenderTransform>
<TransformGroup>
<RotateTransform Angle="200" />
<TranslateTransform X="100" Y="100"/>
</TransformGroup>
</Image.RenderTransform>
</Image>
<Rectangle Height="50" Width="50" RenderTransformOrigin="0.5,0.5" Fill="RoyalBlue" Opacity="0.5">
<Rectangle.RenderTransform>
<TransformGroup>
<RotateTransform Angle="200" />
<TranslateTransform X="100" Y="100"/>
</TransformGroup>
</Rectangle.RenderTransform>
</Rectangle>
</Canvas>
From my testing, it appears that this is just a bug in the way the Visual Studio designer previews this XAML.
I've taken your code and loaded it in both Visual Studio 2010 and in Expression Blend 4. In Visual Studio's designer, I see what you're talking about. In Expression Blend, the preview is correct.
Most importantly, when I run the application, it is rendered correctly. So I think you're ok. Just pretend like its not doing that or use Expression Blend when you have to work with this control.