Hex to int conversion of input data using C program - c

Question

I am trying to convert a hexadecimal data coming from a port( stored in a buffer) into integer format using C program. Before converting from buffer, I wanted to test my code by giving some input in the program. The following is the program I am using from a online source.
#include <stdio.h>
#include <stdlib.h>
int hexToInt(char s[]) {
int hexdigit, i, inhex, n;
i=0;
if(s[i] == '0') {
++i;
if(s[i] == 'x' || s[i] == 'X'){
++i;
}
}
n = 0;
inhex = 1;
for(; inhex == 1; ++i) {
if(s[i] >= '0' && s[i] <= '9') {
hexdigit = s[i] - '0';
} else if(s[i] >= 'a' && s[i] <= 'f') {
hexdigit = s[i] - 'a' + 10;
} else if(s[i] >= 'A' && s[i] <= 'F') {
hexdigit = s[i] - 'A' + 10;
} else {
inhex = 0;
}
if(inhex == 1) {
n = 16 * n + hexdigit;
}
}
return n;
}
int main(int argc, char** argv) {
char hex[] = "93 BC";
int digit = hexToInt(hex);
printf("The Integer is %d", digit);
return 0;
}
When I run this program, it converts one input of hexadecimal into a integer. But if I had to convert an array of hex input as listed below:
00 00 00 05 00 00 00 01 93 BC C0 06 00 00 00 00 ................
00 28 17 00 FC 26 CC 62 00 00 00 07 00 00 00 01 .(...&.b........
00 00 00 D0 00 E3 37 19 00 00 00 1D 00 00 01 00 ......7.........
AB B6 CD 14 00 11 1F 3C 00 00 00 1D 00 00 00 00 .......<........
00 00 00 02 00 00 00 01 00 00 00 90 00 00 00 01 ................
00 00 05 EE 00 00 00 04 00 00 00 80 F0 92 1C 48 ...........�...H
C2 00 00 0E 0C 30 C7 C7 08 00 45 00 05 DC 32 70 .....0....E...2p
40 00 2D 06 41 C8 2D 3A 4A 01 93 BC C8 EC 01 BB #.-.A.-:J.......
C1 58 C5 8D 53 88 05 72 46 E6 80 10 00 53 DC 34
Then how I can convert it into corresponding integer values?

Answer 1

"to convert of array of hex input", modify hexToInt() to hexToInt(const char *s, char **endptr) and have it set *endptr to where the parsing stopped. If no parsing occurred, have *endptr = s.
int main(void) {
char hex[] = "93 BC";
char *p = hex;
while (*p) {
char *endptr;
int digit = hexToInt(p, &endptr);
if (p == endptr) break;
printf("The Integer is %d", digit);
p = endptr;
}
return 0;
}