Program not giving any output after taking input from user - c

Question

I was creating on a very basic program in C which takes a word from user as input and searches for how many times it appears in a text file and gives output.
The code is:
#include<stdio.h>
#include<string.h>
int main()
{
char user[20];
char word[20];
int i,pos=0,sum=0;
char c;
c='a';
printf("Enter the word you want to look for\n");
gets(user);
FILE *p;
p=fopen("D:\\trees.txt","r+");
do
{
pos=0;
fscanf(p,"%s",word);
if(c!=EOF)
{
if(strlen(word)==strlen(user))
{
for(i=0;i<strlen(user);i++)
{
if(word[i]==user[i]||word[i]==user[i]+32||word[i]==user[i]-32)
{
}
else
{
pos=1;
break;
}
}
}
else
{
pos=1;
}
if(pos=0)
{
sum++;
}
}
}
while(c!=EOF)
;printf("\nNumber of times %s appears is %d",user,sum);
fclose(p);
}
Now the program takes the input fine, but doesn't give any output.
Looks like this:
What have I done wrong?

Answer 1

Looking at the comments, your code should be something like:
#include<stdio.h>
#include<string.h>
#include <ctype.h>
int main()
{
char user[20];
char word[20];
int n, pos=0, sum=0;
unsigned int i, l;
FILE *p;
do {
printf("Enter the word you want to look for\n");
} while (gets(user)==0);
user[strlen(user)-1]= '\0'; // remove trailing \n
if ((p=fopen("D:\\trees.txt","r+"))==0) {printf("Error opening file\n"); exit(0);}
do
{
pos=0;
n= fscanf(p,"%s",word);
if (n==1)
{
if(strlen(word)==(l=strlen(user)))
{
for(i=0; i<l; i++)
{
if(!(word[i]==user[i]||word[i]==tolower(user[i])||word[i]==toupper(user[i])))
{
pos=1;
break;
}
}
}
else pos=1;
if(pos==0) sum++;
}
}
while(n==1);
printf("\nNumber of times %s appears is %d",user,sum);
fclose(p);
return(1);
}
(with some optimizations and additions)