Error with bool function - c

Question

I am a new C developer (I am used to programming in Java), and have tried create, what I thought was a simple bool function. Although I am getting an error which I don't understand how to fix:
#include <stdio.h>
#include <stdlib.h>
typedef enum { false, true } bool;
int main() {
int currentNumber, round = 1;
printf("Numbers generated will be between 1 and 20. \n");
currentNumber = rand() % 20;
bool validNumber = false;
do {
if(currentNumber != 0) {
validNumber == true;
} else {
currentNumber = rand() % 20;
}
}while(validNumber == false);
printf("You're on round" + ("%d", round));
printf("You're current number is: " + ("%d", currentNumber));
printf("Higher or Lower (H/L)?");
char userInput [20];
scanf("%s", &userInput);
if((userInput[0] == 'h') || (userInput[0] == 'H')) {
completeRound(round, 'H', currentNumber);
} else if((userInput[0] == 'l') || (userInput[0] == 'L')) {
completeRound(round, 'L', currentNumber);
}
}
void completeRound(int round, char input, int currentNumber) {
int initialVal = currentNumber, newVal;
if(input == 'H') {
newVal = rand() % 20;
bool checkResult(initialVal, newVal, input);
} else {
newVal = rand() % 20;
bool checkResult(initialVal, newVal, input);
}
}
bool checkResult(int initialVal, int finalVal, char input);
bool checkResult(int initialVal, int finalVal, char input) {
if(input == 'H') {
if(initialVal <= finalVal) {
return true;
} else {
return false;
}
}
if(input == 'L') {
if(initialVal >= finalVal) {
return true;
}else {
return false;
}
}
printf("An error has occurred! Aborting game...");
return false;
}
The error is as follows:
\main.c|39|error: conflicting types for 'checkResult'
At first, I thought that for some reason, in C you could only pass certain data types as arguments to a bool method, although I can not find a straight answer to this on Google. Other than that; I can not understand what it means by "conflicting types" (this is the first time I've debugged a C program.
The function I have used to call checkResult is as follows:

Answer 1

Before calling the function you need to write its prototype also. By default compiler is considering it as return type of int but actually it is bool.
so write bool checkResult(int initialVal, int finalVal, char input) before calling checkResult.

Answer 2

You probably have a typo in your code. The line
bool checkResult(initialVal, newVal, temp);
implicitly creates a prototype for a bool function. The types of the arguments are omitted and default to int in C versions prior to C99. This declaration is in conflict with the actual declaration, whose third parameter is of type char.
You probably meant something like this:
bool okay = checkResult(initialVal, newVal, temp);
This defines a bool variable okay and initialises it with the result of the function call. (But note that this variable is local to the current scope, so in your example you'd lose the result immediately.)
It is legal in C to declare a function inside a function body, although it is not good practice. It is more usual to declare them in headers or at the beginning of the file.
As of C99, implicit function declarations are invalid. There also isn't a default argument or function return type of int. You might consider to enforce the C99 standard (eg with -std=c99in gcc) to avoid falling into the implicit-declaration trap.

Answer 3

You have called functions before declaring them.So is the error. Because by default the return type of a c function is "int".
Add
void completeRound(int , char , int );
and
bool checkResult(int , int , char);
after your typedef (better this way than declaring them in body of the calling function).
And since checkResult() is returning a value of type bool you better assign it to a variable of type bool like
bool okay = checkResult(initialVal, newVal, temp); this.