Too many arguments to function call, What do I do? - c

Question

I am working on a problem in my textbook and I need to make a triangle angle calculator Im used to java but Im not 100% on C yet, I don't understand the logic in it.
#include <stdio.h>
static float angleB;
static float angleA;
float remainingAngle(float answer)
{
float answer= angleA+angleB;
//redefinition of answer
return 0;
}
//CANT TOUCH FROM HERE TO END
int main(int argc, const char * argv[]) {
float angleA = 30.0;
float angleB = 60.0;
float angleC = remainingAngle(angleA,angleB);
// to many arguments to function call (referring to angleC)
printf("the third angle is %.2f\n",angleC);
return 0;
} //END CANT TOUCH
I don't know what to do here.

Answer 1

In your function definition
float remainingAngle(float answer)
the function remainingAngle() accepts one parameter.
OTOH, in your function call
remainingAngle(angleA,angleB);
you're passing two arguments.
The supplied argument number and type should match with the parameter list in function definition.
That said, your code is wrong.
Point 1. Your local variables will shadow the global ones. Maybe that's not what you want. Change
float angleA = 30.0;
float angleB = 60.0;
to
angleA = 30.0;
angleB = 60.0;
Point 2. The function
float remainingAngle(float answer)
{
float answer= angleA+angleB;
//redefinition of answer
return 0;
}
is logically wrong. It should rather be
float remainingAngle(void)
{
float answer= angleA+angleB;
return answer;
}
and should be called like
float angleC = remainingAngle();
AFTER EDIT:
as per your requirement, you can do
float remainingAngle(float angleA, float angleB)
{
float answer= angleA+angleB;
return answer;
}
However, this makes the global variables useless.

Answer 2

In addition to Souravs answer you could also do the following:
float remainingAngle(float angA, float angB)
{
float answer = angA + angB;
return answer;
}
So your call will stay the same.
And for the logical side, what you do is:
You pass two arguments (value of angleA and value of angleB) to the function remainingAngle. There you do the calculation and return the result (answer).

Answer 3

The design of your function isn't good:
static float angleB;
static float angleA;
float remainingAngle(float answer)
{
float answer= angleA+angleB;
//redefinition of answer
return 0;
}
What do I do?
There's no point is passing in the answer; the answer is what you want to receive. (There's also no point in passing "space" for the answer. The anser is a float, a scalar variable. Just pass that around.) Remove the answer argument.
You redefine answer as local variable. After removing the argument of the same name, that redefinition goes away. But in that case you should return answer instead of 0. You could even do without the intermediary variable answer and return the result expression. So: Return the desired expression
The answer depends on two global variables. The function should work on two angles that you pass as arguments. Provide two angle arguments to your function and remove the global variables.
And finally, the sum of the three angles in a triangle is 180°, so your remaining angle calculation is wrong.
Putting all that together:
float remainingAngle(float a, float b)
{
return 180.0f - a - b;
}
and call it like this:
float angleC = remainingAngle(angleA, angleB);
Im used to java
I'm not too familiar with Java, but I don't think functios on scalars like this one are fundamentally different in C and Java.