Files and generating numbers ,c programming - c

Question

Task is next:
After you generate 20 random numbers and read informations from file tombula.txt which contains names of users and their 9 numbers,print the first user (his/her name) who has 3 numbers from own array equal to generated numbers.
This is my part of code where i generate numbers and read from file but I don't know how to find that first person who has 3 numbers from array equal to generated numbers,if you know how to write that please help:
#define _CRT_SECURE_NO_WARNINGS
#include<stdio.h>
#include<stdlib.h>
#include <time.h>
typedef struct
{ char name[50];
int num[8];
}someone;
void generating(int[]);
int check(int[], int);
int main(void)
{
someone *pK = NULL;
int i, j, count = 0, tip;
FILE *F;
int generated[30];
int brojac[5];
srand(time(NULL));
generating(generated);
for (int j = 0; j < 20; j++)
printf("%d ", generated[j]);
printf("\n\n\n");
F = fopen("tombula.txt", "r");
if (F == NULL)
{
printf("error!");
exit(1);
}
i = 0;
while (feof(F) == 0)
{
pK = ((someone *)realloc(pK, (i + 1)*sizeof(someone)));
fscanf(F, "%s", pK[i].name);
for (j = 0; j < 8; j++)
fscanf(F, "%d", &pK[i].num[j]);
i++;
count++;
}
i--;
count--;
for (int z = 0; z < count; z++){
printf("%s ", pK[z].name);
for (int k = 0; k < 8; k++){
printf("%d ", pK[z].num[k]);
}
printf("\n");
}
return 0;
}
void generating(int numbers[])
{
int i, tmp;
for (i = 0; i < 20; ++i)
{
tmp = rand() % 50 + 1;
if (check(numbers, tmp))
{
--i;
continue;
}
numbers[i] = tmp;
}
}
int check(int b[], int a){
int i;
int n = 8;
for (i = 0; i < 20; ++i)
{
if (b[i] == a)
return 1;
}
return 0;
}

Answer 1

1.You opened file in r mode.
2.In a loop (loop must work until EOF) read data stored in file using fscanf() .Store name into char array and number into integer array (As you defined in struct).
3.Inside loop check if the 3 numbers matches with the numbers generated and if they do print the persons name and use break to come out of loop.
4.After this close the file.