I have a duration column of type time(7) in my appointments table.
I know how to get the number of minutes in an appointment using
select durationMinutes = DateDiff(n, a.StartOn, a.EndOn)
from appointments a
but my duration column is time(7).
How do I convert the int to the duration?
You can try the DATEADD function and add the minutes to a 00:00:00 time.
DATEADD(MINUTE, #durationMinutes, '00:00:00')
declare #Time as Time(7) = '01:02:03';
select #Time as 'Time(7)', DateDiff( minute, 0, #Time ) as 'Minutes';
declare #Minutes as Int = 90;
select #Minutes as 'Minutes', Cast( DateAdd( minute, #Minutes, 0 ) as Time(7) ) as 'Time(7)';
Related
Declare #StartDate DATETIME = GetDate()
DECLARE #increase INT = 5;
DECLARE #EndDate DATETIME = (SELECT DATEADD(mi, #increase, #StartDate))
select #StartDate,#EndDate
In above query I have increased the current time by 5 min. Now What I want is if the query returns 2020-12-16 09:26:16.103 as start time and 2020-12-16 09:31:16.103 as end time the start time should automatically becomes 2020-12-16 09:25:16.103 and end end time will get increase accordingly by 5 minutes. I hope I am clear.
The answer to above question is below. Postiong so that it will help others
Declare #StartDate DATETIME = GetDate()
set #StartDate=(select dateadd(minute, datediff(minute, '1900-01-01', dateadd(second, 150, #StartDate))/5*5, 0))
DECLARE #increase INT = 5;
DECLARE #EndDate DATETIME = (SELECT DATEADD(mi, #increase, #StartDate))
select #StartDate,#EndDate
I'm wondering how to calculate the "number of hours" between two timestamps (2016-02-24 17:30:00 and another, for instance) in SQL server- but excluding Saturday and Sunday's full 48 hour period, if crossed.
This isn't quite the same as pure business hours, but sort of. The reason for this is long-winded and unnecessary.
EDIT: I can also say that the end-date will always be during the week. So really ... the "start date" can simply be transmuted to Monday midnight, if on Sat/ Sun ... then maybe a function include the total week count...
DATEDIFF(Week, date, date2) will return the number of week boundaries that are crossed between the two dates. For SQL Server, this means how many Sundays are between the dates (as opposed to the number of 7 day periods are between them). This means, that if you can indeed assume that start and end date will not be a saturday or sunday, you can subtract 48 X DATEDIFF(Week, date, date2) from your normal DATEDIFF call and that should give you what are after.
I would use the below code
declare #NumberOfHours int
declare #StartTime datetime
declare #EndTime datetime
set #StartTime = '2017-02-02 17:30:00.000'
set #EndTime = '2017-02-07 00:00:00.000'
set #NumberOfHours = DATEDIFF(HOUR,#StartTime,#EndTime)
if(datepart(WEEKDAY, #StartTime)=1)
begin
set #NumberOfHours = #NumberOfHours DATEDIFF(HH,#StartTime,#EndTime)%24
end
else if(datepart(WEEKDAY, #StartTime)=7)
begin
set #NumberOfHours = #NumberOfHours - DATEDIFF(HH,#StartTime,#EndTime)%24
set #NumberOfHours = #NumberOfHours - 24
end
else
begin
set #NumberOfHours = #NumberOfHours - datediff(ww,#StartTime,#EndTime)*48
end
print #NumberOfHours
I would use a calendar table (ex. dbo.DateDimension, ref https://www.mssqltips.com/sqlservertip/4054/creating-a-date-dimension-or-calendar-table-in-sql-server/):
CREATE TABLE dbo.DateDimension
(
DateKey INT NOT NULL PRIMARY KEY,
[Date] DATE NOT NULL,
[Day] TINYINT NOT NULL,
DaySuffix CHAR(2) NOT NULL,
[Weekday] TINYINT NOT NULL,
WeekDayName VARCHAR(10) NOT NULL,
IsWeekend BIT NOT NULL,
IsHoliday BIT NOT NULL,
...
)
and, also, following query:
SELECT SUM(
CASE
WHEN dd.[Date] = CONVERT(DATE, #StartDate) THEN DATEDIFF(MINUTE, #StarDate, DATEADD(DAY, 1, dd.[Date]))
WHEN dd.[Date] = CONVERT(DATE, #EndDate) THEN DATEDIFF(MINUTE, dd.[Date], #EndDate)
ELSE 24 * 60 -- Full day
END) / 60 AS SumOfHours
FROM dbo.DateDimension dd
WHERE dd.[Date] >= CONVERT(DATE, #StartDate) AND dd.[Date] <= CONVERT(DATE, #EndDate)
AND dd.IsWeekend = 0
Above query will compute total amount of minutes for requested period of time and then it will divide by 60 to get number of hours.
I would like to create a random date for a SQL Server update query. I found a lot examples for random days or something similar but I couldn't find something which creates a random date with random date, hours, minutes, seconds AND milliseconds.
This is what I use to create the date randomly but it always gives me 00 as hour, minute, seconds and milliseconds and I don't know how I can randomize them as well.
This is my query:
declare #FromDate date = GETDATE()-2
declare #ToDate date = GETDATE()-1
UPDATE ACCOUNTS
SET dateFinished=
dateadd(day, rand(checksum(newid())) * (1 + datediff(day, #FromDate, #ToDate)), #FromDate)
This is how I'd do it:
Work out the number of seconds between from and to
Get a random number between zero and the number of seconds
Add that random number to the FromDate
Finally randomise the number of milliseconds
DECLARE #FromDate DATETIME = DATEADD(DAY, -2, GETDATE())
DECLARE #ToDate DATETIME = DATEADD(DAY, -1, GETDATE())
DECLARE #Seconds INT = DATEDIFF(SECOND, #FromDate, #ToDate)
DECLARE #Random INT = ROUND(((#Seconds-1) * RAND()), 0)
DECLARE #Milliseconds INT = ROUND((999 * RAND()), 0)
SELECT DATEADD(MILLISECOND, #Milliseconds, DATEADD(SECOND, #Random, #FromDate))
declare #FromDate dateTIME = '2014-01-01'
declare #ToDate dateTIME = '2014-12-31'
select top 100 dateadd(day,rand(checksum(newid()))*(1+datediff(day, #FromDate, #ToDate)), #FromDate) FROM Tabled(give your table name)
SELECT dateaddDATEADD(second,
second, (rand()*60+1),
DATEADD(minute,
(rand()*60+1) ,
DATEADD(day,
(rand()*365+1),
DATEADD(year,
-1,
getdate()))) )
How do I calculate total minutes between start and end times? The Start/End times columns are nvarchar and I am declaring them as datetime. I'm not sure if that is my first step or not, I am new to SQL and to declaring.
The final goal is to take Total Minutes, subtract Lunch and Recess (both are minutes) and then multiply by 5 to get total instructional minutes for the week per school.
DECLARE #StartTime datetime, #Endtime datetime
SELECT --[School]
[GradeLevel]
,[StartTime]
,[EndTime]
,(#Endtime - #StartTime) AS 'TotalMinutes'
,[Lunch]
,[Resess]
,[Passing]
FROM [dbo].[StartEndTimes]
Current Output:
GradeLevel StartTime EndTime TotalMinutes Lunch Resess Passing
2-5 7:50 14:20 NULL 20 10 NULL
K-5 7:45 14:20 NULL 20 10 NULL
K-5 7:50 14:20 NULL 20 10 NULL
Maybe something like this is what you want?
select (datediff(minute, starttime, endtime) -lunch -recess) * 5 AS TotalInstruct
from YourTable
If you want to sum it up for all rows then try:
select sum((datediff(minute, starttime, endtime) -lunch -recess) * 5) AS TotalInstruct
from YourTable
If you want to get the number of hours per school you would have to include the schoolfield in the query and use it in the group byclause, and then the query becomes this:
select school, sum((datediff(minute, starttime, endtime) -lunch -recess) * 5) AS TotalInstruct
from YourTable
group by school
Sample SQL Fiddle for the above queries.
If all you want is to find the difference between two dates then you can use DATEDIFF function (http://msdn.microsoft.com/en-us/library/ms189794.aspx)
Example:
DECLARE #startdate datetime2
SET #startdate = '2007-05-05 12:10:09.3312722';
DECLARE #enddate datetime2 = '2007-05-04 12:10:09.3312722';
SELECT DATEDIFF(MINUTE, #enddate, #startdate);
If however your values are in string format you need to convert them prior to passing them to the DATEDIFF function.
Example:
DECLARE #starttexttime nvarchar(100)
SET #starttexttime = '7:50'
DECLARE #starttime datetime2
SET #starttime = CONVERT(datetime2, #starttexttime, 0)
DECLARE #endtexttime nvarchar(100)
SET #endtexttime = '17:50'
DECLARE #endtime datetime2
SET #endtime = CONVERT(datetime2, #endtexttime, 0)
SELECT DATEDIFF(MINUTE, #starttime, #endtime);
How can I get the total minute for sql datetime?
Let's say:
select getdate() from table
In this way, I will get everything, but I only want to get total minute. For eg,
if the time is 07:10:35, I want 430.
How to achieve that?
The value from the field is 01-01-2001 07:10:40
The result I want is 430 ((7*60)+10) only.
Here's a sample:
DECLARE #dt datetime
SET #dt = '01-01-2001 07:10:20'
SELECT DATEDIFF(MINUTE, DATEADD(DAY, DATEDIFF(DAY, 0, #dt), 0), #dt)
(DATEPART(HOUR,GETDATE()) * 60) + DATEPART(MINUTE,GETDATE())
This query will return the number of minutes past midnight.
declare #now datetime = getdate()
declare #midnight datetime = CAST( FLOOR( CAST( #now AS FLOAT ) ) AS DATETIME )
select datediff(mi, #midnight,#now)
The code
CAST( FLOOR( CAST( "yourDateTimeHere" AS FLOAT ) ) AS DATETIME )
converts any datetime to midnight. Use the datediff with the "mi" function to get the number of minutes past midnight.
Use books online for more date and time math