function call from struct array [closed] - c

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I have a struct array that has the format:
struct command functions[] = {
{"1", function1},
{"2", function2},
etc....
}
In a function run(char* function), I check if the parameter is equivalent to one of the strings stored in the struct array. If it is, I want to call the corresponding function. For example, if "1" is passed in, I call function1().
How would this be accomplished?
So far, I have
run(char* function) {
for (int i = 0; i < num_functions; i++) {
if(*function == functions[i]) {
return (*function)();
}
}
}
With the following errors:
error: invalid operands to binary == (have int and struct command)
error: called object *function is not a function

Answer 1

There are several issues with your code that seem to be causing an error, but unfortunately you haven't posted enough for me to completely fix them.
In the line if(*function == function[i]) you are using function[i] when you probably want to be using functions[i] (with an "s")
In the same line, you are comparing a char against a struct command. You probably want to access the member of the struct that contains the string shown in your first code snippet.
You are (presumably) comparing a single character against a string. You should do this using strcmp.
You are not calling the function, you're calling a char, which just won't work.
At a guess, I think you want something like this:
run(char* function_name) {
for (int i = 0; i < num_functions; i++) {
struct_command function = functions[i];
if(strcmp(function_name, function.name) == 0) {
return function.exec();
}
}
}
This assumes that the members in your struct command are named name and exec.