Check if array contains part of a string in Swift? - arrays

Question

I have an array containing a number of strings. I have used contains() (see below) to check if a certain string exists in the array however I would like to check if part of a string is in the array?
itemsArray = ["Google, Goodbye, Go, Hello"]
searchToSearch = "go"
if contains(itemsArray, stringToSearch) {
NSLog("Term Exists")
}
else {
NSLog("Can't find term")
}
The above code simply checks if a value is present within the array in its entirety however I would like to find "Google, Google and Go"

Answer 1

Try like this.
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchToSearch = "go"
let filteredStrings = itemsArray.filter({(item: String) -> Bool in
var stringMatch = item.lowercaseString.rangeOfString(searchToSearch.lowercaseString)
return stringMatch != nil ? true : false
})
filteredStrings will contain the list of strings having matched sub strings.
In Swift Array struct provides filter method, which will filter a provided array based on filtering text criteria.

Answer 2

First of all, you have defined an array with a single string.
What you probably want is
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
Then you can use contains(array, predicate) and rangeOfString() – optionally with
.CaseInsensitiveSearch – to check each string in the array
if it contains the search string:
let itemExists = contains(itemsArray) {
$0.rangeOfString(searchToSearch, options: .CaseInsensitiveSearch) != nil
}
println(itemExists) // true
Or, if you want an array with the matching items instead of a yes/no
result:
let matchingTerms = filter(itemsArray) {
$0.rangeOfString(searchToSearch, options: .CaseInsensitiveSearch) != nil
}
println(matchingTerms) // [Google, Goodbye, Go]
Update for Swift 3:
let itemExists = itemsArray.contains(where: {
$0.range(of: searchToSearch, options: .caseInsensitive) != nil
})
print(itemExists)
let matchingTerms = itemsArray.filter({
$0.range(of: searchToSearch, options: .caseInsensitive) != nil
})
print(matchingTerms)

Answer 3

Try like this.
Swift 3.0
import UIKit
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
var filterdItemsArray = [String]()
func filterContentForSearchText(searchText: String) {
filterdItemsArray = itemsArray.filter { item in
return item.lowercased().contains(searchText.lowercased())
}
}
filterContentForSearchText(searchText: "Go")
print(filterdItemsArray)
Output
["Google", "Goodbye", "Go"]

Answer 4

In Swift 5 with better readability :
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchString = "Googled"
let result = itemsArray.contains(where: searchString.contains)
print(result) //prints true in the above case.

Answer 5

MARK:- Swift 5, Swift 4
//MARK:- You will find the array when its filter in "filteredStrings" variable you can check it by count if count > 0 its means you have find the results
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchToSearch = "go"
let filteredStrings = itemsArray.filter({(item: String) -> Bool in
let stringMatch = item.lowercased().range(of: searchToSearch.lowercased())
return stringMatch != nil ? true : false
})
print(filteredStrings)
if (filteredStrings as NSArray).count > 0
{
//Record found
//MARK:- You can also print the result and can do any kind of work with them
}
else
{
//Record Not found
}

Answer 6

func filterContentForSearchText(_ searchText: String) {
filteredString = itemsArray.filter({( item : String) -> Bool in
return item.lowercased().contains(searchText.lowercased())
})
}

Answer 7

In Swift 4:
let itemsArray = ["Google", "Goodbye", "Go", "Hello"]
let searchString = "Go"
let filterArray = itemsArray.filter({ { $0.range(of: searchString, options: .caseInsensitive) != nil}
})
print(filterArray)

Answer 8

I had the same problem recently, didn't like most of these answers,
solved it like this:
let keywords = ["doctor", "hospital"] //your array
func keywordsContain(text: String) -> Bool { // text: your search text
return keywords.contains { (key) -> Bool in
key.lowercased().contains(text.lowercased())
}
}
This will also correctly trigger searches like "doc", which many of the above answers do not and is best practice.
contains() is more performant than first() != nil
source: https://www.avanderlee.com/swift/performance-collections/

Answer 9

If you are just checking if an item exists in a specific array, try this:
var a = [1,2,3,4,5]
if a.contains(4) {
print("Yes, it does contain number 4")
}
else {
print("No, it doesn't")
}