Scope of a variable and function name - c

Question

This is my code:
#include <stdlib.h>
#include <stdio.h>
int sum(int,int);
int sum(int x, int size) {
int sum = 0;
printf("%p\n", &x);
printf("%p\n", &size);
printf("%p\n", &sum);
sum(x,size);
return 0;
}
int main() {
sum(2,4);
return 0;
}
And the error I am getting is:
hello.c:11:5: error: called object type 'int' is not a function or function pointer
sum(x,size);
~~~^

Answer 1

You changed the meaning of sum here:
int sum = 0;
From now on, in the scope in which it was declared, sum is an int, and this becomes nonsense:
sum(x,size); /* Wat? sum is an int!!! */
Don't do that, and your code will compile. Once it compiles, you can worry about stopping the recursion.

Answer 2

If you define two separate identifiers of same name for different entities in the same name space, they might overlap. C11 standard, chapter §6.2.1 states,
If an identifier designates two different entities in the same name
space, the scopes might overlap....
Refer Footnote: Why in this scenario, both sums are in same name space
So, once you re-define the identifier with some other type,
....If so, the scope of one entity (the inner scope) will end
strictly before the scope of the other entity (the outer scope). Within the inner scope, the identifier designates the entity declared in the inner scope; the entity declared in the outer scope is hidden (and not visible) within the inner scope.
That means, essentially, in your case, inside function sum(), when you're defining int sum, basically you're shadowing the function sum. After the re-definition, sum is an identifier of type int, in that function scope. Thus, inside the function sum(), you cannot make a call to sum() as that is an int type now.
However, FWIW, the call to sum() in main() (or, rather, outside sum() itself) should be valid, as at that point, int sum will be out of scope.
Solution: Change the int sum variable name to something else.
Thanks to #pmg for the correction
EDIT:
As mentioned in the other answer by #juanchopanza, after changing the shadowing variable name, your program will compile and once you run it, you'll face infinite recursion due to the unconditional call to sum() inside sum() itself. You need to add some break condition to end (return from) the recursion.
FootNote:
Referring to C11, chapter §6.2.3, name spaces, we can say, there are separate name spaces for various categories of identifiers, e.g. 1) label names 2) the tags of structures, unions, and enumerations, 3) the members of structures or unions and 4) all other identifiers.
So, in this particular case, the function sum() and the int sum definition will reside in the same name space, for the sum() function scope

Answer 3

The scope matters
Function name sum here has a global scope.
Variable sum is local and has local scope.
The conflict is because inside sum() you call sum(). Now inside function sum() you have 2 objects of same name and of different type hence the error.
If you had something like
int sum()
{
int sum = 0;
sum = 10;
printf("%d\n",sum);
}
Then your code would have been fine. Since variable sum is local to function sum() and it is the only object within function sum() with that name.
Instead of worrying about this better to rename the variable and make sure variable name and function name is different

Answer 4

You need to change int sum = 0 to int y = 0, also your program will break as you dont stop recursion at sum(x,sum)

Answer 5

Simply change variable sum name inside sum function to total
#include <stdlib.h>
#include <stdio.h>
int sum(int,int);
int sum(int x, int size) {
int total = 0;
printf("%p\n", &x);
printf("%p\n", &size);
printf("%p\n", &total);
sum(x,size);
return 0;
}
int main() {
sum(2,4);
return 0;
}

Answer 6

Variable and function is of same name thats why it is de-referencing function and variable same time thats the cause of error