Remove specified char from strings in C - c

I am making a program that will search in an array of strings, and for each string, it will search for a specified char. If it finds that char, remove it. In this example I want to remove the character 'r'.
Here is the code:
void convertStrings(char **line) {
for (int str = 0; str < MAX_LINE_LENGTH; ++str) {
for (int ch = 0; ch < MAX_STR_LENGTH; ++ch) {
if (line[str][ch] == 'r') {
removeChar(line[str], 'r');
}
}
}
}
void removeChar(char *str, char c) {
int i = 0;
int j = 0;
while (str[i]) {
if (str[i] != c) {
str[j++] = str[i];
}
i++;
}
str[j]=0;
}
I am not sure if the algorithm for the removal of chars is correct, however the main mistake is elsewhere. More specifically, I get a segmentation fault in the line:
if (line[str][ch] == 'r') {
Why am I getting a seg fault? Also, is the algorithm for removeChar correct?
Here is my main function:
int main() {
char line[3][10] = {"pep", "rol", "rak"};
printf("%s\n", line[1]);
convertStrings(line);
printf("%s\n", line[1]);
return 0;
}
Thanks in advance.

This code works on my compiler :
#include<stdio.h>
#include<conio.h>
#define MAX_LINE_LENGTH 1024
#define MAX_STR_LENGTH 4
void removeChar(char *str, char c) {
int i = 0;
int j = 0;
while (str[i]) {
if (str[i] != c) {
str[j++] = str[i];
}
i++;
}
str[j]=0;
}
void convertStrings(char line[][MAX_STR_LENGTH]) { //change 1
for (int str = 0; str < MAX_LINE_LENGTH; ++str) {
for (int ch = 0; ch < MAX_STR_LENGTH; ++ch) {
if (line[str][ch] == 'r') {
removeChar(line[str], 'r');
}
}
}
}
int main() {
char line[3][MAX_STR_LENGTH] = {"pep", "rol", "rak"}; //change 2
printf("%s\n", line[1]);
convertStrings(line);
printf("%s\n", line[1]);
getch();
return 0;
}

It's because line[str][ch] doesn't exist for all the value you give to str and/or ch.
You should check the value of MAX_LINE_LENGTH and MAX_STR_LENGTH and be sure that they are right.

The seg fault may be because you are using the constants "MAX_LINE_LENGTH" and "MAX_STR_LENGTH" however there may have the line length or string length. I would use the length of the array for the variable str in the first for loop instead of "MAX_LINE_LENGTH" and the length of array[str] instead of "MAX_STR_LENGTH". Unless each array you are searching has "MAX_LINE_LENGTH" and each string has "MAX_LINE_LENGTH" you will get a set fault. Hope this helps!
EDIT: you can find the length of the array by dividing the size of the array and the size of the type of the element.
sizeof(array)/sizeof(array[0])
finding the size of the char pointer is basically the same process.

You are getting a segfault either because array line contains fewer than MAX_LINE_LENGTH string pointers, or because at least one of the pointed-to strings contains fewer than MAX_STR_LENGTH characters; more likely the latter.
Instead of assuming a fixed number of strings of fixed length, you would be better off passing the actual number of strings as an argument. Alternatively, you could add NULL as sentinel value at the end of the list.
Moreover, there is no reason whatever to assume that each string is a fixed length. Look for the terminating character ('\0') to recognize when you've reached the end. For example:
void convertStrings(char **line) {
for (char **l = line; *l != NULL; l += 1) {
for (int ch = 0; (*l)[ch]; ch += 1) {
if ((*l)[ch] == 'r') {
removeChar(*l, 'r');
}
}
}
}
Your removeChar() function looks ok.
Do note, however, that there are library functions that could help with this (e.g. strchr()), and that there are various efficiency improvements possible (such as passing to removeChar() only the string tail, starting at the first appearance of the character to remove).

You have the array
char line[3][10] = {"pep", "rol", "rak"};
When you pass it to a function, it gets converted into a pointer of type char(*)[10]. So change
void convertStrings(char **line) {
to
void convertStrings(char (*line)[10]) {
or
void convertStrings(char line[][10]) {
An array of arrays (2D array) cannot be converted to a pointer to a pointer(in this case, char**)
Another problem is that you mention that MAX_LINE_LENGTH is 1024 and MAX_STR_LENGTH is 4. This is wrong as the loop would iterate and you access invalid memory locations. You should make MAX_LINE_LENGTH as 3 and MAX_STR_LENGTH as 4 as there are 3 strings, each with 4 characters.
You can also pass these variables as parameters to the function convertStrings. Change add two more parameters in the declartion of convertStrings:
void convertStrings(char (*line)[10], int MAX_LINE_LENGTH, int MAX_STR_LENGTH) {
or
void convertStrings(char line[][10], int MAX_LINE_LENGTH, int MAX_STR_LENGTH) {
and call the function from main using
convertStrings(line, sizeof(line)/sizeof(*line), sizeof(*line)/sizeof(**line)); // `/sizeof(**line)` is 1 and is not needed
A better way would be to use
void convertStrings(int MAX_LINE_LENGTH, int MAX_STR_LENGTH, char line[][MAX_STR_LENGTH]) {
or
void convertStrings(int MAX_LINE_LENGTH, int MAX_STR_LENGTH, char (*line)[MAX_STR_LENGTH]) {
and call the function using
convertStrings(sizeof(line)/sizeof(*line), sizeof(*line)/sizeof(**line), line); // `/sizeof(**line)` is 1 and is not needed
so that you can avoid using the magic number 10 in your function.
You would've certainly got some warnings from your compiler. Pay attention to them. If you did not get warnings, crank up the warnings in your compiler and include warning flags ( like -Wall in GCC ).
BTW, You can look into the strchr function from string.h to find if a character exists in a string.

Why do you check if you encounter the 'r' character twice? (in both function)
checking once would be enough.
A function to detect the char, and a function to delete it?
I would have done it this way :
#include <string.h>
#include <stdio.h>
void convertStrings(char *line);
void removeChar(char *str);
int main(int argc, char *argv[]) {
if (argc == 2)
{
printf("%s\n", argv[1]);
convertStrings(argv[1]);
printf("%s\n", argv[1]);
}
return (0);
}
void convertStrings(char *line)
{
for (int i = 0; line[i] != '\0'; i++)
{
if (line[i] == 'r') removeChar(&(line[i]));
}
}
void removeChar(char *str)
{
int i;
i = 0;
while (str[i] != '\0')
{
str[i] = str[i + 1];
i++;
}
}
But here is another one solution with only one function :
void convertStringsbis(char *line)
{
int delta;
int i;
i = 0;
delta = 0;
while (line[i++ + delta] != '\0')
{
if (line[i + delta] == 'r')
delta++;
line[i] = line[i + delta];
}
}

Related

How to change one string to another with different sizes

I have a task to do. I have to work with strings. I will show you the input and output, because I think that will be clear what the task is.
Input: "aaa bbuvvvvo"
Output: "a$3 b$2uv$4o"
If there is the same symbols, I have to leave that symbol and then put dollar sign '$' and an integer of how many same signs was there. I am stuck on the spot, where I have to change string without losing any information.
I will leave my code here, it might help.
#include <stdio.h>
#include <string.h>
#define CAPACITY 255
#define MAX_NUMBER 10
void Output(char readFile[], char outputFile[], char string[]);
void changeString(char string[], char newString[]);
int main() {
char readFile[CAPACITY];
char outputFile[CAPACITY];
char string[CAPACITY];
// Input file's name
printf("Iveskite teksto failo varda: ");
scanf("%s", &readFile);
// Output file's name
printf("Iveskite teksto faila i kuri bus isvedamas atsakymas: ");
scanf("%s", &outputFile);
Output(readFile, outputFile, string);
return 0;
}
// Scanning file
void Output(char readFile[], char outputFile[], char string[])
{
char newString[CAPACITY];
FILE *input, *output;
input = fopen(readFile, "r");
while(fscanf(input, "%s", string) != EOF)
{
changeString(string, newString);
printf("%s\n", newString);
}
}
// Changing string to wanted string
void changeString(char string[], char newString[])
{
char number[MAX_NUMBER];
int symbols = 0;
int j;
for(int i = 0; string[i] != '\0'; ++i)
{
int temp = i;
newString[i] = string[i];
if(newString[i] == string[i + 1])
{
j = i;
while(string[j] == string[i])
{
++symbols;
++j;
}
// Changing int to char
sprintf(number, "%d", symbols);
newString[i + 1] = '$';
i += 2;
newString[i] = number[0];
symbols = 0;
}
}
}
I have tried to do that with function called changeString, but I get the wrong output all the time. Also the input I am getting is from .txt file.
EDIT: When I compiling this program right now, I get a$3 b$2v$4vo that output.
For starters this declaration in main
char string[CAPACITY];
does not make sense.
You should declare variables in scopes where they are used.
The variable string is used in the function Output where it is should be declared.
The function changeString should be declared like
void changeString( const char string[], char newString[]);
because the source string is not changed within the function.
Your function has several bugs.
For example it does not build a string in the array newString because it does not append the stored sequence in the array with the terminating zero character '\0'.
Secondly this increasing of the variable i
i += 2;
in general is invalid. You need to add to the variable i the number of repeated characters in the source string.
Or the number of repeated characters change greater than or equal to 10. In this case this statement
newString[i] = number[0];
will not produce correct result.
The function can be defined the following way as shown in the demonstration program below.
#include <stdio.h>
#define CAPACITY 255
void changeString( const char string[], char newString[] )
{
while ( *string )
{
*newString++ = *string;
size_t n = 1;
while (*++string == *( newString - 1 ) ) ++n;
if (n != 1)
{
*newString++ = '$';
int count = sprintf( newString, "%zu", n );
newString += count;
}
}
*newString = '\0';
}
int main( void )
{
char string[CAPACITY] = "aaa bbuvvvvo";
char newString[CAPACITY];
changeString( string, newString );
puts( newString );
}
The program output is
a$3 b$2uv$4o

Function to reverse the input string.Display the reversed string but just with pointer no brackets[],no libraries..function will change in memory

int *i;
ters_cevir(){
char *term=i;
char *som=i;
char som1;
while (*term != '\0') { term++; }
while (*som != '\0') {
som1=som*;
*term=som;
term--;
som++;
}
}
int main() {
char *isim=malloc(sizeof(char));
i=&isim;
printf("Reverse words=");
scanf("%s",isim);
printf("Kelimenizin tersi:\n ");
ters_cevir(); // When I call this, it must make the reverse one that make from memory
while (*isim != '\0') {
printf("%c",*isim);
isim++;
sayac++;
}
return 0;
}
Hi I have modified your code. Please see below also see my comments:-
void ters_cevir(char *isim){
char *term=isim;
//char *som=isim;
//char som1;
while (*isim != '\0') { isim++; }
while (*term != '\0') {
//som1=som*;
*--isim=*term++//isim was pointing to the null character so we are pre decrement that pointer and post decrement term
//here we are coping the string in reverse order in isim
//term--;
//som++;
}
}
int main() {
char *isim=malloc(50);//you need enough space to store a string. you have just allocated only one byte which was not enough
//i=&isim;
printf("Reverse words=");
scanf("%s",isim);
printf("Kelimenizin tersi:\n ");
ters_cevir(isim); // now it will work fine. Here you are passing the address of isim
while (*isim != '\0') {
printf("%c",*isim);
isim++;
sayac++;
}
return 0;
}
Your code does not compile because of syntax errors such as som1=som*;
You should pass the string as an argument to ters_cevir(); instead of a global variable i with an incorrect type int *.
After fixing these problems, ters_cevir() will still not achieve the expected result because it overwrites the string from the end with characters from the start, with an off by one error.
You could correct this by swapping characters at *som and *term, but be careful to stop when som >= term otherwise you will reverse the string twice.
Futhermore, the code in main is completely broken.
Here is a corrected version:
#include <stdio.h>
char *reverse(char *str) {
char *term = str;
char *som = str;
char c;
while (*term != '\0') { term++; }
while (som < term) {
term--;
c = *som;
*som = *term;
*term = c;
som++;
}
return str;
}
int main() {
char buf[128];
printf("String to reverse: ");
if (scanf("%127[^\n]", buf) == 1) {
printf("Reversed string: %s\n", reverse(buf));
}
return 0;
}

removing a char from a string in c by index

how can I remove a certain char from a string in c without using any library
functions? the function i wrote seems to have a run time error and i can not figure out why.
void remove_char(char* s,int index)
{
while(s[index+1] != 0)
{
s[index] = s[index + 1];
index++;
}
s[index] = 0;
}
I was also wondering if there is a way to remove a char in a complexity of 1?
Without seeing how you are calling your function, knowing the exact failure mode is difficult. Calling it with char string[] = "this is a string";, it worked fine. But as the comments suggest, some other forms of input strings may cause a problem.
I have used the following implementation with no problems. It removes all occurrences of a specified character:
int RemoveCharFromString(char *orig, char c, char *newStr)
{
if(!orig) return -1;
if(!newStr) return -1;
int i=0, j=0;
while (*(orig+i) != '\0')
{
if (*(orig+i) != c)
{
*(newStr+j) = *(orig+i);
j++;
i++;
}
else i++;
}
*(newStr+j) = '\0';
return 0;
}
Or, as you requested, this one removes a character at a specified index:
int RemoveCharFromStringByIndex(char *orig, int index, char *newStr)
{
if(!orig) return -1;
if(!newStr) return -1;
int i=0, j=0;
while (*(orig+i) != '\0')
{
if (i != index)
{
*(newStr+j) = *(orig+i);
j++;
i++;
}
else i++;
}
*(newStr+j) = '\0';
return 0;
}
Notice, in this implementation newStr is created by caller and must include space enough to contain the result.
You can certainly adapt these in any way you need to. An improvement would be to change the prototype to:
char * RemoveCharFromString(char *orig, char c);
Or
char * RemoveCharFromStringByIndex(char *orig, int index)
But that will be something you can do, if you wish it so.
I always like this for removing a specific char from a string:
int RemoveCharFromString(const char *src, char *dst, char c)
{
const char *s;
char *d;
if ((char *)0 != src && (char *)0 != dst) {
for (d = dst, s = src; (*d = *s); s++) {
if (c != *d)
d++;
}
return 0;
}
return 1;
}
Only increment the destination pointer if it's not equal to the character being skipped. Sometimes you see this using the passed arguments src and dst directly, but way back when some compilers would produce more efficient code with separate pointers. The "const" simply allows you to pass a constant string as the source without producing a compiler error.

Updating string until period is found in C

In this function I am going to be receiving char * words such as
person.vet.blah
and
word.friends.joe
I want to extract the first word. So for the first one I want to extract
person
and the second one I want to extract
word
How can I correctly do this? Here is my code:
char *separate_name(char *machine_name)
{
//iterate until you find period. then return
char absolute_name[1000];
int i;
for (i =0; i < strlen(machine_name); i++)
{
if (machine_name[i] == '.')
absolute_name[i] = machine_name[i];
}
return absolute_name;
}
This is just segfaulting. Any ideas what I should be doing? machine_name is going to be the "person.vet.blah" and then return absolute_name which would be "person"
Fixing your code
As others have pointed out, you can't use absolute_name outside of the function in which it was defined. This is because you're when you return the variable from your function, all that is being returned is a pointer to the beginning of the array. Outside the function, the array itself no longer exists, so the pointer is invalid and you get a segfault if you try and dereference it.
You can get around this by using malloc. Don't forget to free the memory you have allocated when you are done using it.
By the way, as well as changing your loop to a while, I also fixed the check (you were checking machine_name[i] == '.', the opposite to what you wanted).
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *separate_name(char *machine_name)
{
// allocate memory on the heap
char *absolute_name = malloc(strlen(machine_name)+1);
int i = 0;
while (i < strlen(machine_name) && machine_name[i] != '.') {
absolute_name[i] = machine_name[i];
++i;
}
absolute_name[i] = '\0';
return absolute_name;
}
int main()
{
char name1[] = "person.vet.blah";
char *first1 = separate_name(name1);
if (first1 != NULL) {
printf("%s\n", first1);
free(first1);
}
char name2[] = "word.friends.joe";
char *first2 = separate_name(name2);
if (first2 != NULL) {
printf("%s\n", first2);
free(first2);
}
return 0;
}
A better alternative
strtok is the perfect tool for the job:
#include <stdio.h>
#include <string.h>
char *separate_name(char *machine_name)
{
return strtok(machine_name, ".");
}
int main()
{
char name1[] = "person.vet.blah";
char *first1 = separate_name(name1);
if (first1 != NULL) printf("%s\n", first1);
char name2[] = "word.friends.joe";
char *first2 = separate_name(name2);
if (first2 != NULL) printf("%s\n", first2);
return 0;
}
As pointed out in the comments (thanks #John), strtok modifies the string that is passed to it (it replaces the delimiter . by the \0 null byte to mark the end of the string). This isn't a problem here but is something to be aware of.
Output using either program:
person
word
#include <stdio.h>
char *separate_name(const char *machine_name){
static char absolute_name[1000];
int i;
for (i =0; i < sizeof(absolute_name)-1 ; i++){
if(machine_name[i] == '.' || machine_name[i] == '\0'){
absolute_name[i] = '\0';
break;
} else {
absolute_name[i] = machine_name[i];
}
}
return absolute_name;
}
int main(void){
printf("%s\n", separate_name("person.vet.blah"));
printf("%s\n", separate_name("word.friends.joe"));
return 0;
}

Returning a string to a variable length character array

I have a program that reverses a string from an input of a variable length character array. The function returns a variable length character array and is printed. When I print the output, I do get the reversed string, but there are garbage characters appended to it in my console print.
Is this a "legal" operation in terms of returning to buffers? Can someone please critique my code and suggest a better alternative if it is not the right approach?
Thanks.
#include <stdio.h>
#include <stdlib.h>
char *reverse_string(char *input_string);
char *reverse_string(char *input_string)
{
int i=0;
int j=0;
char *return_string;
char filled_buffer[16];
while (input_string[i]!='\0')
i++;
while (i!=0)
{
filled_buffer[j]=input_string[i-1];
i--;
j++;
}
return_string=filled_buffer;
printf("%s", return_string);
return return_string;
}
int main (void)
{
char *returned_string;
returned_string=reverse_string("tasdflkj");
printf("%s", returned_string);
return 1;
}
This is my output from Xcode - jklfdsat\347\322̲\227\377\231\235
No, it isn't safe to return a pointer to a local string in a function. C won't stop you doing it (though sometimes the compiler will warn you if you ask it to; in this case, the local variable return_string prevents it giving the warning unless you change the code to return filled_buffer;). But it is not safe. Basically, the space gets reused by other functions, and so they merrily trample on what was once a neatly formatted string.
Can you explain this comment in more detail — "No, it isn't safe..."
The local variables (as opposed to string constants) go out of scope when the function returns. Returning a pointer to an out-of-scope variable is undefined behaviour, which is something to be avoided at all costs. When you invoke undefined behaviour, anything can happen — including the program appearing to work — and there are no grounds for complaint, even if the program reformats your hard drive. Further, it is not guaranteed that the same thing will happen on different machines, or even with different versions of the same compiler on your current machine.
Either pass the output buffer to the function, or have the function use malloc() to allocate memory which can be returned to and freed by the calling function.
Pass output buffer to function
#include <stdio.h>
#include <string.h>
int reverse_string(char *input_string, char *buffer, size_t bufsiz);
int reverse_string(char *input_string, char *buffer, size_t bufsiz)
{
size_t j = 0;
size_t i = strlen(input_string);
if (i >= bufsiz)
return -1;
buffer[i] = '\0';
while (i != 0)
{
buffer[j] = input_string[i-1];
i--;
j++;
}
printf("%s\n", buffer);
return 0;
}
int main (void)
{
char buffer[16];
if (reverse_string("tasdflkj", buffer, sizeof(buffer)) == 0)
printf("%s\n", buffer);
return 0;
}
Memory allocation
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
char *reverse_string(char *input_string);
char *reverse_string(char *input_string)
{
size_t j = 0;
size_t i = strlen(input_string) + 1;
char *string = malloc(i);
if (string != 0)
{
string[--i] = '\0';
while (i != 0)
{
string[j] = input_string[i-1];
i--;
j++;
}
printf("%s\n", string);
}
return string;
}
int main (void)
{
char *buffer = reverse_string("tasdflkj");
if (buffer != 0)
{
printf("%s\n", buffer);
free(buffer);
}
return 0;
}
Note that the sample code includes a newline at the end of each format string; it makes it easier to tell where the ends of the strings are.
This is an alternative main() which shows that the allocated memory returned is OK even after multiple calls to the reverse_string() function (which was modified to take a const char * instead of a plain char * argument, but was otherwise unchanged).
int main (void)
{
const char *strings[4] =
{
"tasdflkj",
"amanaplanacanalpanama",
"tajikistan",
"ablewasiereisawelba",
};
char *reverse[4];
for (int i = 0; i < 4; i++)
{
reverse[i] = reverse_string(strings[i]);
if (reverse[i] != 0)
printf("[%s] reversed [%s]\n", strings[i], reverse[i]);
}
for (int i = 0; i < 4; i++)
{
printf("Still valid: %s\n", reverse[i]);
free(reverse[i]);
}
return 0;
}
Also (as pwny pointed out in his answer before I added this note to mine), you need to make sure your string is null terminated. It still isn't safe to return a pointer to the local string, even though you might not immediately spot the problem with your sample code. This accounts for the garbage at the end of your output.
First, returning a pointer to a local like that isn't safe. The idiom is to receive a pointer to a large enough buffer as a parameter to the function and fill it with the result.
The garbage is probably because you're not null-terminating your result string. Make sure you append '\0' at the end.
EDIT: This is one way you could write your function using idiomatic C.
//buffer must be >= string_length + 1
void reverse_string(char *input_string, char* buffer, size_t string_length)
{
int i = string_length;
int j = 0;
while (i != 0)
{
buffer[j] = input_string[i-1];
i--;
j++;
}
buffer[j] = '\0'; //null-terminate the string
printf("%s", buffer);
}
Then, you call it somewhat like:
#define MAX_LENGTH 16
int main()
{
char* foo = "foo";
size_t length = strlen(foo);
char buffer[MAX_LENGTH];
if(length < MAX_LENGTH)
{
reverse_string(foo, buffer, length);
printf("%s", buffer);
}
else
{
printf("Error, string to reverse is too long");
}
}

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