Using 2d arrays to store strings in C - c

Question

I want to make a program that handles strings in 2d arrays in the following manner:
Each row represents one name only, while columns holds separate characters of each name.
Like so:
0 1 2 3 4 5
0 K e v i n \0
1 J o h n \0
2 L u c y \0
Now, the way I understand arrays is that they work as pointers for the first element. So when I read the string using the readstring(name) function even though I used a 1D array, it should work as a pointer to the 2D array and store each string as I showed above, right?
The following code is supposed to ask for three names then print them all, but it only prints the last name and some gibberish, what did I do wrong?
#include <stdio.h>
#include <stdlib.h>
void readstring(char name[]);
void get_data(char name[][15]);
void show_data(char name[][15]);
int main()
{
char name[3][15];
get_data(name);
show_data(name);
return 0;
}
void get_data(char name[][15]){
int i=0;
for(i=0;i<3;i++){
printf("\nEnter name: ");
readstring(name);
}
}
void show_data(char name[][15]){
int i;
for(i=0;i<3;i++){
printf("%s",name[i]);
}
}
void readstring(char str[]){
int i=0;
while((str[i++]=getchar())!='\n' && i<15);
str[i]='\0';
}
The output shows like this:
http://i58.tinypic.com/e7i048.jpg

Answer 1

The problem is here:
readstring(name);
Change it to:
readstring(name[i]);
The problem is that name is a 2 - d array, or , an array of strings. Therefore, to access one string in the array of strings, you need to use an index for that particular string.
In fact, the calling function readstring() expects a string as an argument.