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I'm trying to create a while loop in C, it says that build is successful, however it doesn't print out anything. I don't really see whats wrong, it doesn't show anything in the console.
int main()
{
int w = 0;
while (w >=100){
printf("w = %i" , w);
w++;
}
return 0;
}
You define w=0 and in the next line you write "while w is greater or equal than 100", which cannot work.
Try
while (w <= 100)
Related
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#include<studio.h>
int main()
{
int a=5,i;
i!=a>10;
printf("i=%d",i);
return 0;
}
This code should print i=1 but it is printing i=0 Why is it so?
That's because you don't do anything to i.
Your "i!=a>10" evaluates to false, but the result is not stored into a variable.
As it is mentioned in the comments, you need something like this:
int a = 5;
int i = !(a > 10);
The != is mostly used in if-clauses, like
if (a != 0) {...}
I hope this helps. ;)
It's not printing because:
the variable i is not initialized
the second statement should be changed and be a variable int i = !(a > 10)
Returning a value and printing it are different things, but that's not the point of the question.
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I have a problem that this code doesn't end with output.
I appreciate if help me.
#include <stdio.h>
int main(){
int number,counter=0;
scanf("%d",&number);
while (number!=0){
number=number/10;
counter++;
}
printf("the number has %d digits",&counter);
return 0;
}
You should remove "&" from your printf statement.
& is for scanning not printing
the correct form is :
printf("the number has %d digits",counter);
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Closed 4 years ago.
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I am trying to use side effect operator in my expression which does not have just a variable. My program was compiled successfully but I got a runtime error "Segmentation fault"
Here is my code:
int main()
{
int x = 1;
printf(1 + (x++));
return 0;
}
C requires you to format the string, this way it knows what it should print. What you have in your example is nothing but memory addresses, which makes the C compiler confused.
int main()
{
int x = 1;
printf("%d\n", (1 + (x++)));
return 0;
}
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How many times the while loop is executed in the below prog if short int is of 2 bytes?
main()
{
int j = 1;
while(j <= 255);
{
printf("%d",j);
j++;
}
return 0;
}
i think it should be 255 times but its not correct. Can anyone tell me why?
You have a semicolon at the end of your while-line. The while loop, consisting of the statement ;, executes "infinitely" many times.
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Closed 9 years ago.
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I want to compare if two arrays are equal. I know i have to loop through both arrays and see if they match. But how do i determine the longest array to use as an end to the loop.
EDIT
if (intToRoman(roman_integer, result))
{
for(int i = 0; i < ???; i++ )
}
for example,
roman_integer[] = "MMM"
result[] = "MMMDCCLXXX"
use strlen function to find the length of greatest string, like
int greatestlength=arrlength(a);
if(greatestlength<arrlength(b))
{
greatestlength=arrlength(b);
}
use strlen inside of arrlength or directly or write your own code in arrlength whatever you want