How to hide console cursor in c? - c

Question

I have a simple C program that represents a loading screen within the console, but I can't get the cursor to hide. I tried cranking up the speed of the sleep function so that the cursor timer would be reset and the cursor would be gone but that doesn't work.
Any tips on how to hide the cursor?
Code:
#include <stdio.h>
#include <stdlib.h>
const int TIME = 1;
int main(int argc,char *argv[]){
int i;
while (1){
printf("loading");
for (i=0;i<3;i++){
sleep(TIME);
printf(".");
}
sleep(TIME);
printf("\r");
system("Cls");
sleep(TIME);
}
}

Answer 1

To extend on Bishal's answer:
To hide the cursor:
printf("\e[?25l");
To re-enable the cursor:
printf("\e[?25h");
Source

Answer 2

Add to your program the following function
#include <windows.h>
void hidecursor()
{
HANDLE consoleHandle = GetStdHandle(STD_OUTPUT_HANDLE);
CONSOLE_CURSOR_INFO info;
info.dwSize = 100;
info.bVisible = FALSE;
SetConsoleCursorInfo(consoleHandle, &info);
}
and call it in your main.
And read more in the MSDN

Answer 3

printf("\e[?25l");
This should work ! It is taken from ANSI codesheet where the characters are not just what they are seen. They act like some form of commands.

Answer 4

Here a solution that works both in Windows and Linux:
#include <iostream>
#ifdef _WIN32
#define WIN32_LEAN_AND_MEAN
#define VC_EXTRALEAN
#include <Windows.h>
#endif // _WIN32
using namespace std;
void show_console_cursor(const bool show) {
#if defined(_WIN32)
static const HANDLE handle = GetStdHandle(STD_OUTPUT_HANDLE);
CONSOLE_CURSOR_INFO cci;
GetConsoleCursorInfo(handle, &cci);
cci.bVisible = show; // show/hide cursor
SetConsoleCursorInfo(handle, &cci);
#elif defined(__linux__)
cout << (show ? "\033[?25h" : "\033[?25l"); // show/hide cursor
#endif // Windows/Linux
}