Prevent incompatible function casts in C? - c

Sometimes it is useful to cast function callbacks without.
For example, we may have a function to duplicate some data:
struct MyStruct *my_dupe_fn(const struct MyStruct *s)
But pass it as a generic callback:
typedef void *(*MyGenericCopyCallback)(void *key);
Eg: ensure_key_in_set(my_set, my_key, (MyGenericCopyCallback)my_dupe_fn);
Since the difference between const struct MyStruct * and void * is not going to cause problems in this case, it won't cause any bugs (at least in the function call its self).
However, if later on an arguments added to my_dupe_fn, this could cause a bug which wouldn't give a compiler warning.
Is there a way to cast a function, but still show warnings if the arguments or return values are different sizes?
Obligatory disclaimer: of course C isn't *safe*, but ways to prevent potential bugs in a widely used language are still useful.

You say "won't cause any bugs", however it causes undefined behaviour to call a function through a function pointer with incompatible return types or parameter types, even in your example code.
If you want to rely on undefined behaviour then that's your risk to take. Relying on UB has a tendency to cause bugs sooner or later. A better idea would be to re-design the callback interface to not rely on undefined behaviour. For example, only use functions of the correct type as the callback function.
In your example this might be:
typedef void *MyCallback(void *key); // style: avoid pointer typedefs
struct MyStruct *my_dupe_fn(const struct MyStruct *s)
{ ... }
void *my_dupe_fn_callback(void *s)
{
return my_dupe_fn(s);
}
void generic_algorithm(MyCallback *callback)
{
// ....
ensure_key_in_set(my_set, my_key, callback);
// ....
}
// elsewhere
generic_algorithm(my_dupe_fn_callback);
Note the lack of casts. Managing a style policy of not using any function casts is simpler than a policy of allowing certain types.

If you are using gcc and are not afraid of using helpful extensions, you might have a look at plan9-extensions. In combination with anonymous struct fields (standard since C99) as the first field, they allow to build a type-hierarchy with static functions, etc. Avoids tons of casts in my code and makes it much more readable.
Not sure, but according to the gcc documentation, the MS-compiler supports some (all?) these features, too. No warranty for that, however.

That later error is coming from two pieces of code that say the same thing getting out of sync -- the first where you define the type of my_dupe_fn, and the second where you cast the generic callback pointer back to its original type.
This is where DRY (do not repeat yourself) comes in. The whole point is to only say something once, so that you can't later come back and change only one instance.
In this case, you'd want to typedef the type of a pointer to my_dupe_fn, preferably very close to where you declare the function itself, to help ensure that the typedef always changes along with the function signiture itself.
The compiler is never going to catch this for you as long as it thinks that it is just dealing with a generic void pointer.

Unfortunately you typically have to forgo some of this compile-time safety if you're using C. You might get a warning at best, but if you have a design that is uniformly casting function pointers this way, you're likely to ignore or outright disable them. Instead you want to place your emphasis on achieving safe coding standards. What you can't guarantee by force, you can encourage strongly by policy.
I would suggest, if you can afford it, to start by casting arguments and return values rather than whole function pointers. A flexible representation is like so:
typedef void* GenericFunction(int argc, void** args);
This emulates the ability to have variadic callbacks, and you can uniformly do runtime safety checks in debug builds, e.g., to make sure that the number of arguments matches the assumptions:
void* MyCallback(int argc, void** args)
{
assert(argc == 2);
...
return 0;
}
If you need more safety than this for the individual arguments being passed and can afford a typically-small cost of an extra pointer per argument with a slightly bulky structured solution, you can do something like this:
struct Variant
{
void* ptr;
const char* type_name;
};
struct Variant to_variant(void* ptr, const char* type_name)
{
struct Variant new_var;
new_var.ptr = ptr;
new_var.type_name = type_name;
return new_var;
}
void* from_variant(struct Variant* var, const char* type_name)
{
assert(strcmp(var->type_name, type_name) == 0 && "Type mismatch!");
return var->ptr;
}
void* pop_variant(struct Variant** args, const char* type_name)
{
struct Variant* var = *args;
assert(var->ptr && "Trying to pop off the end of the argument stack!");
assert(strcmp(var->type_name, type_name) == 0 && "Type mismatch!");
++*args;
return var->ptr;
}
With macros like so:
#define TO_VARIANT(val, type) to_variant(&val, #type);
#define FROM_VARIANT(var, type) *(type*)from_variant(&var, #type);
#define POP_VARIANT(args, type) *(type*)pop_variant(&args, #type);
typedef struct Variant* GenericFunction(struct Variant* args);
Example callback:
struct Variant* MyCallback(struct Variant* args)
{
// `args` is null-terminated.
int arg1 = POP_VARIANT(args, int);
float arg2 = POP_VARIANT(args, float);
...
return 0;
}
A side benefit is what you can see in your debugger when you trace into MyCallback through those type_name fields.
This kind of thing can be useful if your codebase supports callbacks into dynamically-typed scripting languages, since scripting languages should not be doing type casts in their code (typically they're meant to be a bit on the safer side). The type names can then be used to automatically convert the arguments into the scripting language's native types dynamically using those type_name fields.

Related

C function that returns a pointer to an array correct syntax?

In C you can declare a variable that points to an array like this:
int int_arr[4] = {1,2,3,4};
int (*ptr_to_arr)[4] = &int_arr;
Although practically it is the same as just declaring a pointer to int:
int *ptr_to_arr2 = int_arr;
But syntactically it is something different.
Now, how would a function look like, that returns such a pointer to an array (of int e.g.) ?
A declaration of int is int foo;.
A declaration of an array of 4 int is int foo[4];.
A declaration of a pointer to an array of 4 int is int (*foo)[4];.
A declaration of a function returning a pointer to an array of 4 int is int (*foo())[4];. The () may be filled in with parameter declarations.
As already mentioned, the correct syntax is int (*foo(void))[4]; And as you can tell, it is very hard to read.
Questionable solutions:
Use the syntax as C would have you write it. This is in my opinion something you should avoid, since it's incredibly hard to read, to the point where it is completely useless. This should simply be outlawed in your coding standard, just like any sensible coding standard enforces function pointers to be used with a typedef.
Oh so we just typedef this just like when using function pointers? One might get tempted to hide all this goo behind a typedef indeed, but that's problematic as well. And this is since both arrays and pointers are fundamental "building blocks" in C, with a specific syntax that the programmer expects to see whenever dealing with them. And the absensce of that syntax suggests an object that can be addressed, "lvalue accessed" and copied like any other variable. Hiding them behind typedef might in the end create even more confusion than the original syntax.
Take this example:
typedef int(*arr)[4];
...
arr a = create(); // calls malloc etc
...
// somewhere later, lets make a hard copy! (or so we thought)
arr b = a;
...
cleanup(a);
...
print(b); // mysterious crash here
So this "hide behind typedef" system heavily relies on us naming types somethingptr to indicate that it is a pointer. Or lets say... LPWORD... and there it is, "Hungarian notation", the heavily criticized type system of the Windows API.
A slightly more sensible work-around is to return the array through one of the parameters. This isn't exactly pretty either, but at least somewhat easier to read since the strange syntax is centralized to one parameter:
void foo (int(**result)[4])
{
...
*result = &arr;
}
That is: a pointer to a pointer-to-array of int[4].
If one is prepared to throw type safety out the window, then of course void* foo (void) solves all of these problems... but creates new ones. Very easy to read, but now the problem is type safety and uncertainty regarding what the function actually returns. Not good either.
So what to do then, if these versions are all problematic? There are a few perfectly sensible approaches.
Good solutions:
Leave allocation to the caller. This is by far the best method, if you have the option. Your function would become void foo (int arr[4]); which is readable and type safe both.
Old school C. Just return a pointer to the first item in the array and pass the size along separately. This may or may not be acceptable from case to case.
Wrap it in a struct. For example this could be a sensible implementation of some generic array type:
typedef struct
{
size_t size;
int arr[];
} array_t;
array_t* alloc (size_t items)
{
array_t* result = malloc(sizeof *result + sizeof(int[items]));
return result;
}
The typedef keyword can make things a lot clearer/simpler in this case:
int int_arr[4] = { 1,2,3,4 };
typedef int(*arrptr)[4]; // Define a pointer to an array of 4 ints ...
arrptr func(void) // ... and use that for the function return type
{
return &int_arr;
}
Note: As pointed out in the comments and in Lundin's excellent answer, using a typedef to hide/bury a pointer is a practice that is frowned-upon by (most of) the professional C programming community – and for very good reasons. There is a good discussion about it here.
However, although, in your case, you aren't defining an actual function pointer (which is an exception to the 'rule' that most programmers will accept), you are defining a complicated (i.e. difficult to read) function return type. The discussion at the end of the linked post delves into the "too complicated" issue, which is what I would use to justify use of a typedef in a case like yours. But, if you should choose this road, then do so with caution.

Opaque types allocatable on stack in C

When designing a C interface, it is common to let into the public interface (.h) only what needs to be known by the user program.
Hence for example, the inner components of structures should remain hidden if the user program does not need to know them. This is indeed good practice, as the content and behavior of the struct could change in the future, without affecting the interface.
A great way to achieve that objective is to use incomplete types.
typedef struct foo opaqueType;
Now an interface using only pointers to opaqueType can be built, without the user program ever needing to know the inner working of struct foo.
But sometimes, it can be required to allocate such structure statically, typically on stack, for performance and memory fragmentation issues. Obviously, with above construction, opaqueType is incomplete, so its size is unknown, so it cannot be statically allocated.
A work around is to allocate a "shell type", such as :
typedef struct { int faketable[8]; } opaqueType;
Above construction enforces a size and an alignment, but doesn't go farther into describing what the structure really contains. So it matches the objective of keeping the type "opaque".
It mostly works. But in one circumstance (GCC 4.4), the compiler complains that it breaks strict-aliasing, and it generates buggy binary.
Now, I've read a ton of things about strict aliasing, so I guess I understand now what it means.
The question is : is there a way to define an opaque type which can nonetheless be allocated on stack, and without breaking strict aliasing rule ?
Note that I've attempted the union method described in this excellent article but it still generates the same warning.
Note also that visual, clang and gcc 4.6 and later don't complain and work fine with this construction.
[Edit] Information complement :
According to tests, the problem only happens in the following circumstances :
Private and public type different. I'm casting the public type to private inside the .c file. It doesn't matter apparently if they are part of the same union. It doesn't matter if the public type contains char.
If all operations on private type are just reads, there's no problem. Only writes cause problems.
I also suspect that only functions which are automatically inlined get into trouble.
Problem only happens on gcc 4.4 at -O3 setting. -O2 is fine.
Finally, my target is C90. Maybe C99 if there really is no choice.
You can force the alignment with max_align_t and you can avoid the strict aliasing issues using an array of char since char is explicitly allowed to alias any other type.
Something along the lines of:
#include <stdint.h>
struct opaque
{
union
{
max_align_t a;
char b[32]; // or whatever size you need.
} u;
};
If you want to support compiler that do not have the max_align_t, or if you know the alignment requirements of the real type, then you can use any other type for the a union member.
UPDATE: If you are targetting C11, then you may also use alignas():
#include <stdint.h>
#include <stdalign.h>
struct opaque
{
alignas(max_align_t) char b[32];
};
Of course, you can replace the max_align_t with whatever type you think appropriate. Or even an integer.
UPDATE #2:
Then, the use of this type in the library would be something along the lines of:
void public_function(struct opaque *po)
{
struct private *pp = (struct private *)po->b;
//use pp->...
}
This way, since you are type-punning a pointer to char you are not breaking the strict aliasing rules.
What you desire is some kind of equivalent of the C++ private access control in C. As you know, no such equivalent exists. The approach you give is approximately what I would do. However, I would make the opaqueType opaque to the inner components implementing the type, so I would be forced to cast it to the real type within the inner components. The forced cast should not generate the warning you are mentioning.
Although cumbersome to use, you can define an interface that provides "stack allocated" memory to an opaque type without exposing a sized structure. The idea is that the implementation code is in charge of the stack allocation, and the user passes in a callback function to get a pointer to the allocated type.
typedef struct opaqueType_raii_callback opqaueType_raii_callback;
struct opaqueType_raii_callback {
void (*func)(opqaueType_raii_callback *, opqaueType *);
};
extern void opaqueType_raii (opaqueType_raii_callback *);
extern void opaqueType_raii_v (opaqueType_raii_callback *, size_t);
void opaqueType_raii (opaqueType_raii_callback *cb) {
opaqueType_raii_v(cb, 1);
}
void opqaueType_raii_v (opaqueType_raii_callback *cb, size_t n) {
opaqueType x[n];
cb->func(cb, x);
}
The definitions above look a bit esoteric, but it is the way I normally implement a callback interface.
struct foo_callback_data {
opaqueType_raii_callback cb;
int my_data;
/* other data ... */
};
void foo_callback_function (opaqueType_raii_callback *cb, opaqueType *x) {
struct foo_callback_data *data = (void *)cb;
/* use x ... */
}
void foo () {
struct foo_callback_data data;
data.cb.func = foo_callback_function;
opaqueType_raii(&data.cb);
}
For me this seems to be something which just shouldn't be done.
The point of having an opaque pointer is to hide the implementation details. The type and alignment of memory where the actual structure is allocated, or whether the library manages additional data beyond what's pointed to are also implementation details.
Of course not that you couldn't document that one or another thing was possible, but the C language uses this approach (strict aliasing), which you can only more or less hack around by Rodrigo's answer (using max_align_t). By the rule you can't know by the interface what kind of constraints the particular compiler would impose on the actual structure within the implementation (for some esoteric microcontrollers, even the type of memory may matter), so I don't think this can be done reliably in a truly cross platform manner.

Elegant way to emulate 'this' pointer when doing OOP in C?

I want to do some object-oriented style programming in C using polymorphism, where my interface class contains a pointer to a table of functions. Example something like:
/* Implement polymorphism in C, Linux kernel-style */
struct statement {
const struct statement_ops *ops;
struct list_head list; /* when on master input list */
void *private; /* pointer to type-specific data */
};
struct statement_ops {
int (*analyse)(void *private, int pc);
int (*get_binary_size)(void *private);
};
void user(void)
{
struct statement *s = make_a_statement();
if (s->ops->analyse(s->private, foo))
blah blah;
}
I'd like to be able to write something without explicitly passing s->private into every "method". Any ideas? Some macro tricks maybe?
If this is part of the public interface, you can add accessor functions. A hidden benefit is that you can do sanity checks and other work in the accessor. (Note I called the "this" pointer "o", as in "object". I prefer it that way for consistency.)
int statement_analyse (struct statement *o, int pc)
{
assert(pc >= 0);
int ret = o->ops->analyse(o->private, pc);
assert(ret >= 0);
return ret;
}
You can now call this without the explicit passing of "private".
void user(void)
{
struct statement *s = make_a_statement();
if (statement_analyse(s, foo))
blah blah;
}
While it may seem that this provides no benefit, because you still have to implement the accessors, assuming that you want a well defined and robust interface, the accessor functions are the only sane place to put the assertions and the interface documentation. In fact, if you write good assertions, the assertions themselves help document the interface. And once you add sanity checks in the accessors, you don't have to add them in the actual methods they call.
Of course, this approach only makes sense when the function called via the function pointer will be something provided by the user, or in some other way can be different things. If there's a single analyse() method that will always do the same thing, you can simply implement a statement_analyse() that directly does what it needs to do.
Small note: when doing OOP, I prefer to typedef the structs and give them CamelCase names. I use this convention as a way of telling that the struct is opaque and should only be accessed via its public interface. It also looks nicer, though that is subjective. I also prefer having the user allocate the memory for the struct itself, as opposed to the constructor malloc'ing it. That avoids having to handle malloc failure, and makes the program a little bit more efficient.
typedef struct {
...
} Statement;
void Statement_Init (Statement *o);
int Statement_Analyse (Statement *o, int pc);
Unfortunately, writing your methods to allow the passing of a self or this object is the only way to achieve this in C.
You can use macro tricks to hide part of it, but at that point it's not really C any more.
As the other answers say, there is no way to do this without calling the function with the appropriate pointer, but (as Williham Totland suggests) you could use macros to streamline the calls (requires a compiler with variadic macro support):
// macro_call.c
#define C_ARGS(stmnt, func, ...) (stmnt)->ops->func((stmnt)->private, ...)
#define C_NOARGS(stmnt, func) (stmnt)->ops->func((stmnt)->private)
C_ARGS(s, analyse, 1);
C_ARGS(s, lots_of_args, 1, 2, 3, 4);
C_NOARGS(s, no_args);
(The C is for "call".)
Doing the preprocessing on that (via gcc -E macro_call.c) gives:
(s)->ops->analyse((s)->private, 1);
(s)->ops->lots_of_args((s)->private, 1, 2, 3, 4);
(s)->ops->no_args((s)->private);
This is similar to the accessor function version: the macro version is slightly more flexible in some ways, but it is also less safe and could lead to subtle errors and mistakes.
There are two macros because passing no extra arguments to C_ARGS would result in s->ops->func(s->private, ), I think it is possible to fix this, but it is awkward and would require significantly more code (empty __VA_ARGS__ are notoriously hard to deal with).

How to check if a void* pointer can be safely cast to something else?

Let's say I have this function, which is part of some gui toolkit:
typedef struct _My_Struct My_Struct;
/* struct ... */
void paint_handler( void* data )
{
if ( IS_MY_STRUCT(data) ) /* <-- can I do something like this? */
{
My_Struct* str = (My_Struct*) data;
}
}
/* in main() */
My_Struct s;
signal_connect( SIGNAL_PAINT, &paint_handler, (void*) &s ); /* sent s as a void* */
Since the paint_handler will also be called by the GUI toolkit's main loop with other arguments, I cannot always be sure that the parameter I am receiving will always be a pointer to s.
Can I do something like IS_MY_STRUCT in the paint_handler function to check that the parameter I am receiving can be safely cast back to My_Struct* ?
Your void pointer looses all its type information, so by that alone, you cannot check if it can be cast safely. It's up to the programmer to know if a void* can be cast safely to a type.
Unfortunately there is no function to check what the pointer was before it appears in that context (void).
The one solution I can think of is if you place an int _struct_id as the first member of all of your structs. This id member can then be safely checked regardless of the type but this will fail if you pass pointers that don't implement this member (or int, char, ... pointers).
The best you could do would be to look at what data points to to see if it has telltale signs of being what you want, although a) it wouldn't be anywhere close to a guarantee and b) might be dangerous, as you don't know how big the thing data actually points to is. I suppose it isn't any more dangerous than just casting it and using it, but (as has been suggested) a redesign would be better.
If you are creating the type that is being used, you could include as part of the type some kind of identifying information that would help you rule out some void pointers as not being of the type you are looking for. While you would run the chance that some random area of memory would contain the same data or signature as what you are looking for, at least you would know when something was not the type you were looking for.
This approach would require that the struct was initialized in such a way that the signature members, used to determine if the memory area is not valid, is initialized to the signature value.
An example:
typedef struct {
ULONG ulSignature1;
// .. data elements that you want to have
ULONG ulSignature2;
} MySignedStruct;
#define MYSIGNEDSTRUCT_01 0x1F2E3D4C
#define MYSIGNEDSTRUCT_02 0xF1E2D3C4
#define IS_MY_STRUCT(sAdr) ( (((MySignedStruct *)sAdr)->ulSignature1 == MYSIGNEDSTRUCT_01 ) && (((MySignedStruct *)sAdr)->ulSignature1 == MYSIGNEDSTRUCT_02))
This is kind of a rough approach however it can help. Naturally using a macro like IS_MY_STRUCT() where the argument is used twice can be problematic if the argument has a side effect so you would have to be careful of something like IS_MY_STRUCT(xStruct++) where xStruct is a pointer to a MySignedStruct.
There really isn't in c. void pointers are typeless, and should only ever be casted when you truly know what they point to.
Perhaps you should instead reconsider your design; rewrite your code so that no inspection is necessary. This is the same reason google disallows RTTI in its style guide.
I know the question is 3 years old but here I go,
How about using a simple global enum to distinguish where the function is called from. then you can switch between what type to cast the void pointer to.

What does ... mean in an argument list in C?

I came across the following function signature and I wondered if this (the ellipsis, or "...") is some kind of polymorphism?
#include <fcntl.h>
int fcntl(int fd, int cmd, ... );
Thanks in advance.
It's a variable argument list.
That is a variadic function. See stdarg.h for more details.
The ... means that you can pass any number of arguments to this function, as other commenters have already mentioned. Since the optional arguments are not typed, the compiler cannot check the types and you can technically pass in any argument of any type.
So does this mean you can use this to implement some kind of polymorphic function? (I.e., a function that performs some operation based on the type of its arguments.)
No.
The reason you cannot do this, is because you cannot at runtime inspect the types of the arguments passed in. The function reading in the variable argument list is expected to already know the types of the optional arguments it is going to receive.
In case of a function that really is supposed to be able to take any number of arguments of any type (i.e., printf), the types of the arguments are passed in via the format string. This means that the caller has to specify the types it is going to pass in at every invocation, removing the benefit of polymorphic functions (that the caller doesn't have to know the types either).
Compare:
// Ideal invocation
x = multiply(number_a, number_b)
y = multiply(matrix_a, matrix_b)
// Standard C invocation
x = multiply_number(number_a, number_b)
y = multiply_matrix(matrix_a, matrix_b)
// Simulated "polymorphism" with varargs
x = multiply(T_NUMBER, number_a, number_b)
y = multiply(T_MATRIX, matrix_a, matrix_b)
You have to specify the type before the varargs function can do the right thing, so this gains you nothing.
No, that's the "ellipsis" you're seeing there, assuming you're referring to the ... part of the declaration.
Basically it says that this function takes an unknown number of arguments after the first two that are specified there.
The function has to be written in such a way that it knows what to expect, otherwise strange results will ensue.
For other functions that support this, look at the printf function and its variants.
Does C support polymorphism?
No, it doesn't.
However there are several libraries, such as Python C API, that implements a rough variant of polymorphism using structs and pointers. Beware that compiler cannot perform appropriate type checking in most cases.
The tecnhique is simple:
typedef struct {
char * (*to_string)();
} Type;
#define OBJ_HEADER Type *ob_type
typedef struct {
OBJ_HEADER;
} Object;
typedef struct {
OBJ_HEADER;
long ival;
} Integer;
typedef struct {
OBJ_HEADER;
char *name;
char *surname;
} Person;
Integer and Person get a Type object with appropriate function pointers (e.g. to functions like integer_to_string and person_to_string).
Now just declare a function accepting an Object *:
void print(Object *obj) {
printf("%s", obj->type->to_string());
}
now you can call this function with both an Integer and a Person:
Integer *i = make_int(10);
print((Object *) i);
Person *p = make_person("dfa");
print((Object *) p);
EDIT
alternatively you can declare i and p as Object *; of course make_int and make_person will allocate space for Integer and Person and do the appropriate cast:
Object *
make_integer(long i) {
Integer *ob = malloc(sizeof(Integer));
ob->ob_type = &integer_type;
ob->ival = i;
return (Object *) ob;
}
NB: I cannot compile these examples rigth now, please doublecheck them.
I came across the following function signature and I wondered if this (the ellipsis, or "...") is some kind of polymorphism?
yes, it is a primitive form of polymorphism. With only one function signature you are able to pass various structures. However the compiler cannot help you with detecting type errors.
Adding to what's been said: C supports polymorphism through other means. For example, take the standard library qsort function which sorts data of arbitrary type.
It is able to do so by means of untyped (void) pointers to the data. It also needs to know the size of the data to sort (provided via sizeof) and the logic that compares the objects' order. This is accomplished by passing a function pointer to the qsort function.
This is a prime example of runtime polymorphism.
There are other ways to implement object-oriented behaviour (in particular, virtual function calls) by managing the virtual function tables manually. This can be done by storing function pointers in structures and passing them around. Many APIs do so, e.g. the WinAPI, which even uses advanced aspects of object orientation, e.g. base class call dispatch (DefWindowProc, to simulate calling the virtual method of the base class).
I assume you are referring to the ellipsis (...)? If so this indicates that 0 or more parameters will follow. It is called varargs, defined in stdarg.h
http://msdn.microsoft.com/en-us/library/kb57fad8.aspx
printf uses this functionality. Without it you wouldn't be able to keep adding parameters to the end of the function.
C supports a crude form of Polymorphism. I.e. a type being able to appear and behave as another type. It works in a similar was as in C++ under the hood (relying on memory being aligned) but you have to help the compiler out by casting. E.g. you can define a struct:
typedef struct {
char forename[20];
char surname[20];
} Person;
And then another struct:
typedef struct {
char forename[20];
char surname[20];
float salary;
char managername[20];
} Employee;
Then
int main (int argc, int *argv)
{
Employee Ben;
setpersonname((Person *) &Ben);
}
void setpersonname(Person *person)
{
strcpy(person->forename,"Ben");
}
The above example shows Employee being used as a Person.
No, it is a function that is taking variable number of arguments.
That is not technically polymorphism. fcntl takes variable number of arguments & that is the reason for the ... similar to printf function.
C neither supports function overloading - which is a type of ad-hoc polymorphism based on compile-time types - nor multiple dispatch (ie overloading based on runtime types).
To simulate function overloading in C, you have to create multiple differently named functions. The functions' names often contain the type information, eg fputc() for characters and fputs() for strings.
Multiple dispatch can be implemented by using variadic macros. Again, it's the programmer's job to provide the type information, but this time via an extra argument, which will be evaluated at runtime - in contrast to the compile-time function name in case of the approach given above. The printf() family of functions might not be the best example for multiple dispatch, but I can't think of a better one right now.
Other approaches to multiple dispatch using pointers instead of variadic functions or wrapping values in structures to provide type annotations exist.
The printf declaration in the standard library is
int printf(const char*, ...);
Think about that.
You can write code that supports Polymorphic behavior in C, but the ... (ellipsis) is not going to be much help. That is for variable arguments to a function.
If you want polymorphic behavior you can use, unions and structures to construct a data structure that has a "type" section and variable fields depending on type. You can also include tables of function pointers in the structures. Poof! You've invented C++.
Yes C Do support the polymorphism
the Code which we write in the C++ using virtual to implement the polymorphism
if first converted to a C code by Compiler (one can find details here).
It's well known that virtual functionality in C++ is implemented using function pointers.

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