I am using vtiger 6.1.0 version.I want to fetch the user details from the database in the vtiger.
My code:
require_once('include/database/PearDatabase.php');
$db = PearDatabase::getInstance();
$query8 = "SELECT id from vtiger_users where is_admin=?";
$result8 =$db->pquery($query8, array("on"));
echo $num_rows = $db->num_rows($result8);
for($i=0; $i<$num_rows; $i++) {
echo $row = $db->query_result_rowdata($result8, $i,'id');
}
While using this code, the total number of rows is printed, but each id can not be fetched, showing some internal server error. Please help me!
You can pass only two argument in query_result_rowdata function.
Please see function in include/database/PearDatabase.php file.
function raw_query_result_rowdata(&$result, $row=0) {
if (!is_object($result))
throw new Exception("result is not an object");
$result->Move($row);
$rowdata = $this->change_key_case($result->FetchRow());
return $rowdata;
}
So please use like that, it work for me.
$index = 0;
foreach($listViewEntries as $recordId => $record) {
$rawData = $db->query_result_rowdata($listResult, $index++);
}
Related
CURRENT ISSUE: I am making one plugin for listing users with there user role in WP_LIST_TABLE table.
This is my query
$this->items = $wpdb->get_results($wpdb->prepare("SELECT {$wpdb->users}.*, {$wpdb->usermeta}.meta_value as roles FROM {$wpdb->users}
LEFT JOIN {$wpdb->usermeta} ON {$wpdb->users}.ID = {$wpdb- >usermeta}.user_id
WHERE {$wpdb->usermeta}.meta_key = '{$wpdb->get_blog_prefix()}capabilities'
ORDER BY {$wpdb->users}.display_name", $per_page, $paged), ARRAY_A);
It display out like This
[roles] => a:1:{s:13:"administrator";b:1;}
How to Unserialize this data. and I want to display the First name too using this query please help me
Finally this helps me.
$input = unserialize($item['roles']);
$result = array();
foreach($input as $key => $value){
$result[] = $key;
}
$userRole = implode(",", $result);
return $userRole;
Try below code:
foreach($this->items as $value){
echo $value->COLUMN_NAME ."<br>";
}
Please change the COLUMN_NAME to whichever column you want to display. If there's a column named e_name, then write "$value->e_name".
Its tried and tested. It works for me. Let me know if it works for you!
I am in need of desperate help. I am newbie to laravel and programming.
I have a sales controller which fetch multiple records from form using jquery and select.
Sales Store controller looks like:
for ($i=0; $i < count($request['product_id']); ++$i)
{
$sales= new Sale;
$sales->product_id = $request['product_id'][$i];
$sales->qty= $request['qty'][$i];
$sales->user_id = Auth::user()->id;
$sales->save();
$product = new Product;
$product->where('id', '=', $request['product_id'][$i])->decrement('stock', $request['qty'][$i]);
}
this code is working perfectly fine.
Now the scenario is that I want to fetch these last created specific records to send it somehow to other page or as an invoice. Any help will be greatly appreciated on how to achieve this? Thanks.
Make a new array to hold the sales and product data and redirect to your desired url with that data.
$data = array();
for ($i=0; $i < count($request['product_id']); ++$i)
{
$sales= new Sale;
$sales->product_id = $request['product_id'][$i];
$sales->qty= $request['qty'][$i];
$sales->user_id = Auth::user()->id;
$sales->save();
$product = new Product;
$product->where('id', '=', $request['product_id'][$i])->decrement('stock', $request['qty'][$i]);
$data[]['sales'] = $sales;
$data[]['product'] = $product;
}
return redirect("/your desired url")->with('data', $data);
For your second question in the comment, In your controller function of your desired url do this -
$data = [];
if ($request->session()->has('data')) {
$data = $request->session()->get('data');
}
return view('your view', compact('data'));
And then in your view -
#foreach($data as $d)
{{$d['sales']}} //here $d['sales'] is your sales object
{{$d['product']}} //here $d['product'] is your product object
#endforeach
You can do
$sales = Sale::latest()->take(count($request['product_id']))->get();
latest() will just order all the sales by the date of creation in descending order.
if count($request['product_id']) is 5, take() will fetch the first 5 sales.
I am fetching video ids from database with random order in limit of 30 and but want to show videos with date of publish in desc in cake php 3. Please assist
In fact, your question is very vague and you don't provide any code, that's why you are down-voted. Next time, try to show you tried something, because even if you did, this is a two-lines-long question.
I understood that :
You want to get 30 random videos from a certain database;
You want to sort them by publish date (desc).
So, try :
// Retrieve all ids
$ids = $this->Videos->find('list')->toArray();
$ids = array_keys($ids);
// Select 30 random ids from the ids list
$total = count($ids);
$count = 30 <= $total ? 30 : $total;
$selectedIds = [];
for($i = 0; $i < $count; $i++) {
$newId = -1;
do {
$newId = rand(0, $total - 1);
} while(!in_array($newId, selectedIds));
$selectedIds[] = $newId;
}
// Now you got your ids in an array
$videos = $this->Videos->find('all')
->where(['id' => $selectedIds])
->order(['publish_date' => 'DESC'])
->limit(30);
Is there anyway to have cake do a multi-row insert in a single query without writing raw SQL to do this? The saveMany and saveAssociated options will only save multiple rows in a single transaction, but that transaction contains multiple insert statements so these methods are clearly not a solution to write heavy applications.
Thanks for reading.
Yes
Though it's not a common practice to do so in app-land code, and doing so removes the possibility to use almost any application logic (validation rules, behaviors, events etc.). You can see an example of doing this in the way fixtures are loaded:
$db = ConnectionManager::getDataSource('default');
$table = "stuffs";
$fields = array('id', 'name');
$values = array(
array(1, 'one'),
array(2, 'two'),
...
);
$result = $db->insertMulti($table, $fields, $values);
You may also find this repository useful (either directly or as a basis for your code) which loads fixture files into your app database - using multi-inserts.
Yes, Big_Data is good idea for inserting bulk. But as AD7six note, it still use basic value quoting and does not return insert ids. And base on your ideas, i wrote small script to inserting bulk in a single query, using default CakePHP quoting and returning ids of inserted records.
$count = count($records);
$dbSource = $this->getDataSource();
$table = $dbSource->fullTableName($this->table);
$fields = $dbSource->prepareFields($this, array('fields' => array_keys($records[0])));
$values = array();
foreach ($records as $index => $record) {
if (!is_array($record) || !$record) {
return null;
}
foreach ($record as $column => $value) {
$values[$index][$column] = $dbSource->value($value, $this->getColumnType($column));
}
$values[$index] = '(' . implode(',', $values[$index]) . ')';
}
$query = 'INSERT INTO %s (%s) VALUES %s;';
$query = sprintf($query, $table, implode(',', $fields), implode(',', $values));
if (!$dbSource->execute($query)) {
return false;
}
$lastInsertId = $dbSource->getConnection()->lastInsertId();
$insertIds = array();
for ($i = 0; $i < $count; $i++) {
$insertIds[] = $lastInsertId + $i;
}
return $insertIds;
Someone pointed me towards the Big Data Behavior https://github.com/jmillerdesign/CakePHP_Big_Data
If you are using CakePHP 3.0 you can check the answer to this question: How to use insert in query builder insert multiple records?
If you are using CakePHP 2 you will have to use raw SQL like this:
$sql = "INSERT INTO `people` (`name`,`title`) VALUES ";
foreach($people as $person){
list($name,$title) = $person;
$sql.= "('$name','$title'),";
}
$this->query(substr($sql,0,-1));
Source: Inserting Multiple Rows with CakePHP 3
yes you can use like below
The getDataSource() method is static in CakePHP 2.x, so you should be able to use:
$db = ConnectionManager::getDataSource('default');
$db->rawQuery($some_sql);
here i am posting method to do. you have to create some SQL statement manually to insert multiple row in one time.
Please let me know if i can help you more.
I have I problem that I hope someone can help me with. I thought this code was right, but it will not work. Below is my code, it is a function for my CakePHP 2.2.2 site, the main aim of the code is to produce a menu system from database results. The problem is with my foreach loop, it will not loop. All $Key does is return the value of 2 (three records within the table at this time). So When I display / echo / debug $Menu, the only result I get is the last result stored within the database.
I know the SQL command is right, if that is debuged / echoed then all three results are displayed. The idea of this loop was to get it to count the results, so that I could run a check on a selected field. Where I am going wrong?
function MenuSystem() {
$this->loadModel('Menu');
$MenuSQL = $this->Menu->find('all', array('conditions' => array('active' => true)));
foreach ($MenuSQL as $Key=>$Value) {
$MenuSystem = $MenuSQL[$Key];
$this->Menu = $MenuSystem;
}
}
Many Thanks,
Glenn.
UPDATE :::
Below is my function, now my foreach loop now works, don't know what I was doing wrong, but I know think its working. You can see the print_r command that I am using for testing, if I use that, then all links from my database are printed / echoed on the screen and all works. But if I try and call the $this->Menu from another controller, then only the last record is echoed on the screen. I have moved the $this->Menu outside of the foreach loop, but it made no difference, with it inside the loop or outside, it still only echoes the last record and not all three. So what I am doing wrong?
function MenuSystem() {
$this->loadModel('Menu');
$SiteBase = '/projects/cake/';
$MenuSQL = $this->Menu->find('all', array('conditions' => array('active' => true)));
foreach ($MenuSQL as $key => $Value) {
$MenuAccessLevel = $MenuSQL[$key]['Menu']['roles_id'];
if ($MenuAccessLevel == 1) {
$Path = $MenuSQL[$key]['Menu']['path'];
$Title = $MenuSQL[$key]['Menu']['title'];
$MenuSys = "<a href=\" " . $SiteBase . $Path . " \">" . $Title ."";
} else {
print ("Admin");
}
//print_r($MenuSys);
} //End of Foreach Loop
$this->Menu = $MenuSys;
} //End of function MenuSystem
So When I display / echo / debug $Menu, the only result I get is the last result stored within the database.
You're setting the value of $this->Menu within the foreach, so when the foreach is complete it will take the last value iterated over.
If you want to find the number of records matching a condition, try:
$menuCount = $this->Menu->find('count', array(
'conditions'=>array('active'=>true)
));
$this->set(compact('menuCount'));
Edit: also, by setting the value of $this->Menu within the foreach, you're overwriting the Menu model variable. This is not a good idea.
Edit2: to get the counts of rows as grouped by some value, try:
$this->Menu->virtualFields = array('count' => 'count(*)');
$counts = $this->Menu->find('all', array(
'group'=>'Role',
'fields'=>array('Role', 'count'),
));
This generates SQL to have the results grouped by the Role column. Returned fields are the name of the role, and the number of rows having that value.
If you wanted to do it with a foreach loop instead, it might look like:
$menus = $this->Menu->find('all', array('fields'=>array('id', 'Role')));
$counts = array('user'=>0, 'admin'=>0);
foreach ($menus as $menu) {
$role = $menu['Menu']['Role'];
$counts[$role] += 1;
}