Segmentation Fault with strlen - c

Question

I am getting a segmentation fault error. When I comment out "wordlength = strlen(token);" it runs fine. I don't know why it the seg fault happens when I assign a strlen(token) just fine to an int a few lines before this one. I would appreciate any help possible.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define char_max 60
int main(int argc, char *argv[])
{
FILE *fp = fopen(argv[2],"r");
char **wordlist;
int row = 1;
int i;
char temp[100];
char *token;
int wordlength;
int lengthcounter;
wordlist = (char**)malloc(row*sizeof(char*));
for(i = 0; i < row; i++)
{
wordlist[i] = (char*)malloc(char_max*sizeof(char*));
}
while(fgets(temp, sizeof(temp), fp) != NULL)
{
lengthcounter = 0;
wordlength = 0;
token = strtok(temp, " ");
strcat(wordlist[row-1], token);
printf("%s\n", wordlist[row-1]);
lengthcounter = strlen(token);
while(token != NULL)
{
token = strtok(NULL, " ");
wordlength = strlen(token);
/*lengthcounter += wordlength;*/
}
printf("The lengthcounter is %d\n", lengthcounter);
}
free(wordlist);
fclose(fp);
return 0;
}

Answer 1

while(token != NULL)
{
token = strtok(NULL, " ");
wordlength = strlen(token);
/*lengthcounter += wordlength;*/
}
What happens in the last iteration of the loop when token is NULL? You pass it to strlen anyway.
Also, this is almost certainly wrong:
wordlist[i] = (char*)malloc(char_max*sizeof(char*));
You're allocating space for pointers, not characters. So why sizeof(char*)? Also, don't cast the return value of malloc. This is C, not C++.