MPI Sendrecv with MPI_ANY_SOURCE - c

Question

Is it possible to do an MPI_Sendrecv exchange where one side does not know the rank of the other? If not, what is the best way to do that (my next guess would just be a pair of sends and recvs)?
For example in C if I want to exchange integers between rank 0 and some other rank would this type of thing work?:
MPI_Status stat;
if(rank){
int someval = 0;
MPI_Sendrecv(&someval, 1, MPI_INT, 0, 1, &recvbuf, 1, MPI_INT, 0, MPI_ANY_TAG, MPI_COMM_WORLD, &stat);
}else{
int someotherval = 1;
MPI_Sendrecv(&someotherval, 1, MPI_INT, MPI_ANY_SOURCE, someotherval, &recvbuf, 1, MPI_INT, MPI_ANY_SOURCE, MPI_ANY_TAG, MPI_COMM_WORLD, &stat);
}
EDIT:
Looks like it is not possible. I whipped up the following as a sort of wrapper to add the functionality that I need.
void slave_sendrecv(const void *sendbuf, int sendcount, MPI_Datatype sendtype,
int dest, int sendtag, void *recvbuf, int recvcount,
MPI_Datatype recvtype, int source, int recvtag, MPI_Status *status){
MPI_Send(sendbuf, sendcount, sendtype, dest, sendtag, MPI_COMM_WORLD);
MPI_Recv(recvbuf, recvcount, recvtype, source, recvtag, MPI_COMM_WORLD, status);
}
void anon_sendrecv(const void *sendbuf, int sendcount, MPI_Datatype sendtype,
int sendtag, void *recvbuf, int recvcount,
MPI_Datatype recvtype, int recvtag, MPI_Status *status){
int anon_rank;
MPI_Recv(recvbuf, recvcount, recvtype, MPI_ANY_SOURCE, recvtag, MPI_COMM_WORLD, status);
anon_rank = status -> MPI_SOURCE;
MPI_Send(sendbuf, sendcount, sendtype, anon_rank, sendtag, MPI_COMM_WORLD);
}
EDIT 2: Based on Patrick's answer it looks like the slave_sendrecv function above is not needed, you can just use regular MPI_Sendrecv on the end that knows who it's sending to.

Answer 1

Short answer: No.
The standard does not allow the use of MPI_ANY_SOURCE as the destination rank dest in any send procedure. This make sense, since you can not send a message without knowing the destination.
The standard however does permit you to pair a MPI_Sendrecv with regular MPI_Send/MPI_Recv:
A message sent by a send-receive operation can be received by a regular receive operation
or probed by a probe operation; a send-receive operation can receive a message sent
by a regular send operation.
In your case, process 0 will have to first receive, and then answer:
MPI_Status stat;
if(rank){
int someval = 0;
MPI_Sendrecv(&someval, 1, MPI_INT, 0, 1, &recvbuf, 1, MPI_INT, 0, MPI_ANY_TAG, MPI_COMM_WORLD, &stat);
}else{
int someotherval = 1;
MPI_Recv(&recvbuf, 1, MPI_INT, MPI_ANY_SOURCE, MPI_ANY_TAG, MPI_COMM_WORLD, &stat);
// answer to process `stat.MPI_SOURCE` using `someotherval` as tag
MPI_Send(&someotherval, 1, MPI_INT, stat.MPI_SOURCE, someotherval, MPI_COMM_WORLD);
}