Linked List inside Linked List - c

Question

I'm trying to use nested linked lists, but I can't seem to access the inner part of the linked list.
#include <stdio.h>
#include <conio.h>
#include <stdlib.h>
int option;
struct nodeAddr
{
int idAddress;
char address[50];
struct nodeAddr *nextAddr;
}*headAddr,*tailAddr,*newAddr,*helpAddr;
struct nodePrs
{
int idPersonel;
char personel[50];
struct nodeAddr *headAddr,*tailAddr,*newAddr,*helpAddr ;
struct nodePrs *nextPrs;
}*headPrs,*tailPrs,*newPrs,*helpPrs;
void signUp()
{
clrscr();
printf("\t============================\n");
printf("\t= Sign Up New Personel =\n");
printf("\t============================\n\n");
newPrs=(nodePrs*)malloc(sizeof(struct nodePrs));
newPrs->newAddr=(nodeAddr*)malloc(sizeof(struct nodeAddr));
printf("Name : ");
scanf("%s",newPrs->personel);
printf("Address : ");
scanf("%s",newPrs->newAddr->address);
newPrs->nextPrs = NULL;
newPrs->newAddr->nextAddr = NULL;
if (headPrs==NULL)
{
headPrs = newPrs;
headPrs->headAddr = newPrs->newAddr;
}
else
{
tailPrs->nextPrs=newPrs;
}
tailPrs=newPrs;
tailPrs->tailAddr=newPrs->newAddr;
}
void printList()
{
helpPrs = headPrs;
nodePrs *temp = headPrs;
if (headPrs==NULL)
printf("Empty");
else
{
printf("the Outputs:\n");
while(helpPrs!=NULL)
{
printf("%s", helpPrs->personel);
printf(" ");
helpPrs->helpAddr = temp->headAddr;
while (helpPrs->helpAddr !=NULL)
{
printf("%s", helpPrs->helpAddr->address);
printf(" ");
helpPrs->helpAddr = helpPrs->helpAddr->nextAddr;
}
helpPrs = helpPrs->nextPrs;
temp=temp->nextPrs;
printf("\n");
}
}
}
void main()
{
do
{
clrscr();
printf("\t==================================\n");
printf("\t= Linked list inside Linked List =\n");
printf("\t==================================\n\n");
printf("1. Sign\n");
printf("2. Show\n");
printf("3. Exit\n\n");
printf("Input (1-3) : ");
scanf("%d",&option);
if (option == 1)
{
signUp();
}
else if (option == 2)
{
printList();
getch();
}
else if(option>2 || option <1)
{
printf("Wrong choice!!!");
}
} while(option!=5);
getch();
}
The problem is in the printList() function. It only prints the first list. After that, it can't show its address of the second entry and so on.