Calloc/Malloc error - c

Question

I am trying to write a program, but every time I try allocating memory, the 4th member of other array loses its meaning. Here is my code:
At first I read file with integer type numbers: In example. 1 2 3 1 2 3 1 2 3
int* reading (int* numbers, char* arg2[])
int* fuction(int* numbers);
int main(int arg1, char *arg2[] ){
if(arg1 != 2){return 0;}
int *numbers;
numbers = reading(numbers, arg2);
numbers = function(numbers);
return 0;
}
int* reading (int* numbers, char* arg2[]){
FILE *in=fopen(arg2[1], "r");
if (in == NULL) {
fprintf(stderr, "Can't open file !\n");
exit(1);
}
int data, length = 1;
numbers = (int*)malloc(3*sizeof(int));
while (fscanf(in, "%d", &data) != EOF){
numbers[length] = data;
length++;
numbers = realloc(numbers, length+1);
}
numbers[0] = length;
numbers[0]--;
return numbers;
}
int* fuction(int* numbers){
int sum = 0;
int i = 0;
int* places;
places = (int*)malloc(1*sizeof(int));
places[0] = 0;
for(i = 1; i <= numbers[0]; i++){ sum += numbers[i];}
if((((numbers[0]) % 3) > 0) || ((sum % ((numbers[0])/3)) > 0)){return places;}
sum = sum / ((numbers[0])/3);
int* newNumbers;
for(i = 1;i<=numbers[0];i++){printf("%d ", numbers[i]);}
printf("\n");
Here in cmd I see: 1 2 3 1 2 3 1 2 3
newNumbers = calloc(numbers[0]+1,sizeof(int) );
for(i = 1;i<=numbers[0];i++){printf("%d ", numbers[i]);}
printf("\n");
But after allocating memory for newNumbers(I tried both - malloc and calloc), I see result like this: 1 2 3 102506522 2 3 1 2 3
places = realloc(places, numbers[0]+1);
for(i = 1;i<=numbers[0];i++){printf("%d ", numbers[i]);}
printf("\n");
Here result stays the same: 1 2 3 102506522 2 3 1 2 3
}
Writing like this:
places = realloc(places, numbers[0]+1);
newNumbers = calloc(numbers[0]+1,sizeof(int) );
I mean allocating memory for "places" at first,
does not solve my problem as well. After:
newNumbers = calloc(numbers[0]+1,sizeof(int) );
I lose numbers[4]- meaning.
I can't understand why it is happening. Maybe someone could help me and give me an advice, how could I correct it.