Writing GRXML code - vxml

Question

I have to write GRXML code that allows me to enter a username with any number of digits, ending with #. I have written this, but it doesn't work:
<grammar version='1.0'
mode='dtmf'
root='RefSaisieClient'>
<rule id="RefSaisieClient">
<item repeat="1-">
<one-of>
<item>0</item>
<item>1</item>
<item>2</item>
<item>3</item>
<item>4</item>
<item>5</item>
<item>6</item>
<item>7</item>
<item>8</item>
<item>9</item>
</one-of>
</item>
<item>#</item>
</rule>
</grammar>

Answer 1

# is generally the default termination character and shouldn't be included in your grammar. Try removing it and see if that fixes your issue.
You can also try using two rules, for example:
<rule id="RefSaisieClient">
<item repeat="1-">
<ruleref uri="#AllowableDigits"/>
</item>
</rule>
<rule id="AllowableDigits" scope="public">
<item>
<one-of>
<item> 1 </item>
<item> 2 </item>
<item> 3 </item>
<item> 4 </item>
<item> 5 </item>
<item> 6 </item>
<item> 7 </item>
<item> 8 </item>
<item> 9 </item>
<item> 0 </item>
</one-of>
</item>
</rule>