Shift array down by one in vba - arrays

Question

I am having some trouble getting a function I have been writing to work properly. I need it to take an array that is sized 1 to x, and transfer it to a new array which is sized 0 to x-1. I would think it would work just like this:
Private Function ShiftDownArray(theArray() As String) As String()
Dim a As Integer
ReDim ShiftDownArray(LBound(theArray) - 1 To UBound(theArray) - 1)
For a = LBound(theArray) To UBound(theArray)
ShiftDownArray(a - 1) = theArray(a)
Next a
End Function
But I get a compile error: Function call on left-hand side of assignment must return Variant or Object. The documentation on this error essentially says delete that line to make it work, which doesn't point me in the right direction. I have tried changing the type to variant, but it starts a chain reaction of needing to change array type from string to variant, and it leads to issues in other parts of my program.
Is there any way to approach this that will allow me to retain the string array type? Thanks

Answer 1

You can pass arrays of most types as a Variant between methods and procedures in VBA
Private Function ShiftDownArray(ByRef theArray As Variant) As Variant
Dim i As Integer
ReDim x(0 To UBound(theArray) - 1) As Variant
For i = 0 To UBound(x)
x(i) = theArray(i + 1)
Next i
ShiftDownArray = x
End Function
But more importantly - why would you want to do this anyway? You can just -/+ 1 to the index in the original array?

Answer 2

Is this what you are looking for:
Public Sub ShiftArrayTest()
'Make an 1-bound array
Dim arr1() As String, N As Long, i As Long
N = 10
ReDim arr1(1 To N)
For i = 1 To N
arr1(i) = CStr(i)
Next i
'Now for the shift
Dim arr2() As String
arr2 = ShiftArray(arr1)
End Sub
Public Function ShiftArray(ByRef theArray() As String) As String()
'Now for the shift
Dim i1 As Long, N As Long, i As Long, res() As String
i1 = LBound(theArray): N = UBound(theArray) - i1 + 1
ReDim res(0 To N - 1)
For i = 0 To N - 1
res(i) = theArray(i1 + i)
Next i
ShiftArray = res
End Function
What I am doing here is taking any array and converting it into a 0-bound array.

Answer 3

The Error is most probably in this line: 'ReDim ShiftDownArray(LBound(theArray) - 1 To UBound(theArray) - 1)'
It looks like you're recursively calling itself, which seems odd given there isn't a base case.
See the following example as provided by this website. The gist of it is that it will skip the first element and copy everything over 'to the left'.
Function Array_Shift(arr As Variant) As Variant
' http://www.php.net/manual/en/function.array-shift.php
Dim tempArray As Variant
Dim i As Long
tempArray = arr
' shift elements one position up
' by skipping the first element of the source array
For i = LBound(tempArray) To UBound(tempArray) - 1
tempArray(i) = tempArray(i + 1)
Next i
' remove last element
' which is now empty
ReDim Preserve tempArray(LBound(tempArray) To UBound(tempArray) - 1)
Array_Shift = tempArray
End Function

Answer 4

The trouble is not with passing an array of strings as a parameter - you can pass arrays of any type, as far as I'm aware. However, assigning a value to ShiftDownArray(a - 1) is ambiguous as you could be accessing the a-1th element of the array or passing a - 1 as a parameter to the ShiftDownArray() function.
The Function call on left-hand side of assignment must return Variant or Object. error message hints to this. You are calling the ShiftDownArray() function rather than accessing the array. The compiler knows you are going to assign something to the value returned by the function (because it is followed by an =) but doesn't know the type as it hasn't yet evaluated theArray(a). To ensure that the assignment can complete regardless of the type of theArray(a), the compiler tries to make sure that ShiftDownArray() returns a Variant or Object to which anything can be assigned.
To avoid this error you can create a temporary array which can be accessed in the conventional manner and assign that array to ShiftDownArray to return from the function.
The following code shows this:
Private Function ShiftDownArray(theArray() As String) As String()
ReDim tempArray(LBound(theArray) - 1 To UBound(theArray) - 1) As String
Dim i As Integer
For i = LBound(tempArray) To UBound(tempArray)
tempArray(i) = theArray(i + 1)
Next i
ShiftDownArray = tempArray
End Function