I am doing the following SELECT statement to see how many Reps each of my Manufacturers have in my database, this is working nicely:
SELECT ManufacturerId, COUNT(*) AS RepCount
FROM ManufacturerSalesReps WHERE IsDeleted=0
GROUP BY ManufacturerID
ORDER BY COUNT(*)
So this gives me the ManufacturerId and the number of reps but what i really need is the number of manufacturers at different rep counts. So I want to GROUP the results from the above SELECT by RepCount.
How do I accomplish this?
I cannot think of something else, but:
SELECT T.RepCount, COUNT(*) AS ManufacturerCount
FROM (
SELECT ManufacturerId, COUNT(*) AS RepCount
FROM ManufacturerSalesReps
WHERE IsDeleted=0
GROUP BY ManufacturerID
) AS T
GROUP BY T.RepCount
ORDER BY COUNT(*)
Either this is correct or totally dumb.
With windowing functions
SELECT ManufacturerId, COUNT(*),
count(ManufacturerId) over (partition by COUNT(*)) num_man AS RepCount
FROM ManufacturerSalesReps WHERE IsDeleted=0
GROUP BY ManufacturerID
ORDER BY 2
Related
I am trying to get available balance on last(max) date. I am trying to write below query but it is showing error.
select ACCOUNT_ID,AVAIL_BALANCE,OPEN_DATE,MAX(LAST_ACTIVITY_DATE)
from ACCOUNT
group by CUST_ID;
Column 'ACCOUNT.ACCOUNT_ID' is invalid in the select list because it
is not contained in either an aggregate function or the GROUP BY
clause.
I am new to sql. Can anyone let me know where I am wrong in this query?
Any column not having a calculation/function on it must be in the GROUP BY clause.
select ACCOUNT_ID,AVAIL_BALANCE,OPEN_DATE,MAX(LAST_ACTIVITY_DATE)
from ACCOUNT
group by ACCOUNT_ID,AVAIL_BALANCE,OPEN_DATE;
If you're wanting the most recent row for each customer, think ROW_NUMBER(), not GROUP BY:
;With Numbered as (
select *,ROW_NUMBER() OVER (
PARTITION BY CUST_ID
ORDER BY LAST_ACTIVITY_DATE desc) rn
from Account
)
select ACCOUNT_ID,AVAIL_BALANCE,OPEN_DATE,LAST_ACTIVITY_DATE
from Numbered
where rn=1
I think you want to select one records having max(LAST_ACTIVITY_DATE) for each CUST_ID.
For this you can use TOP 1 WITH TIES like following.
SELECT TOP 1 WITH TIES account_id,
avail_balance,
open_date,
last_activity_date
FROM account
ORDER BY Row_number()
OVER (
partition BY cust_id
ORDER BY last_activity_date DESC)
Issue with your query is, you can't select non aggregated column in select if you don't specify those columns in group by
If you want to get the max activity date for a customer then your query should be as below
select CUST_ID, MAX(LAST_ACTIVITY_DATE)
from ACCOUNT
group by CUST_ID;
You can't select any other column which is not in the group by clause. The error message also giving the same message.
with query(CUST_ID, LAST_ACTIVITY_DATE) as
(
select
CUST_ID,
MAX(LAST_ACTIVITY_DATE) as LAST_ACTIVITY_DATE
from ACCOUNT
group by CUST_ID
)
select
a.ACCOUNT_ID,
a.AVAIL_BALANCE,
a.OPEN_DATE,
a.LAST_ACTIVITY_DATE
from ACCOUNT as a
inner join query as q
on a.CUST_ID = q.CUST_ID
and a.LAST_ACTIVITY_DATE = q.LAST_ACTIVITY_DATE
I have been trying to subtract two columns in sql server to form a third one. Below is my query
select AD.Id, Sum(APS.Amount) AS TotalDue,
isnull((select sum(Amount) from Activation where InvoiceId in (select InvoiceId from Invoices where AgreementId = AD.Id)),0)
As AllocatedToDate
from AdvantageDetails AD
inner join AllPaymentsSubstantial APS
on APS.AgreementId=AD.Id
where AD.OrganizationId=30
group by AD.Id
What I tried is below but it is not working. :
select AD.Id, Sum(APS.Amount) AS TotalDue,
isnull((select sum(Amount) from Activation where InvoiceId in (select InvoiceId from Invoices where AgreementId = AD.Id)),0)
As AllocatedToDate , (TotalDue-AllocatedToDate) as NewColumn
from AdvantageDetails AD
inner join AllPaymentsSubstantial APS
on APS.AgreementId=AD.Id
where AD.OrganizationId=30
group by AD.Id
At last I tried it using a CTE which worked fine. But I want to do it without creating CTE. Can there be any other way for performing the same functionality. I do not want to use CTE because it is forcasted that there
can be other columns which will be calculated in future.
with CTE as(select AD.Id, Sum(APS.Amount) AS TotalDue,
isnull((select sum(Amount) from Activation where InvoiceId in (select InvoiceId from Invoices where AgreementId = AD.Id)),0)
As AllocatedToDate , (TotalDue-AllocatedToDate) as NewColumn
from AdvantageDetails AD
inner join AllPaymentsSubstantial APS
on APS.AgreementId=AD.Id
where AD.OrganizationId=30
group by AD.Id) select * , (CTE.TotalDue-CTE.AllocatedToDate)As Newcolumn from CTE
You can do it without a CTE by repeating the entire formula that makes up AllocatedToDate.
You cannot use the alias of a column in the SELECT list, so you cannot do this:
SELECT {some calculation} AS ColumnA, (ColumnA - ColumnB) AS ColumnC
If you don't want to use a CTE or derived table, you have to do this:
SELECT {some calculation} AS ColumnA, ({some calculation} - ColumnB) AS ColumnC
And by the way, I can't imagine why the possibility of future columns being added is a reason not to use a CTE. To me, it sounds like a reason TO use a CTE, as you will only have to make changes in one place in the code, and not duplicate the same code in different places in the same query.
You can just use nested queries:
select Id, TotalDue, AllocatedToDate, (TotalDue-AllocatedToDate) as NewColumn
from (
select AD.Id, Sum(APS.Amount) AS TotalDue,
isnull((select sum(Amount) from Activation where InvoiceId in (select InvoiceId from Invoices where AgreementId = AD.Id)),0)
As AllocatedToDate
from AdvantageDetails AD
inner join AllPaymentsSubstantial APS
on APS.AgreementId=AD.Id
where AD.OrganizationId=30
group by AD.Id
) x
I have a requirement (simple, but can't find simple solution) to fetch mobile number and unique transaction id (latest transaction would be good, but any transaction id is also ok)
Sample Data
Seq. Mobile No. Transaction No.
1 1234567890 ABC1234
2 2345678901 ABC2392
3 2345678901 ABC2782
I simply want to find mobile number 2345678901 and any of the one transaction, however latest would be good.
Output
Seq. Mobile No. Transaction No.
1 1234567890 ABC1234
2 2345678901 ABC2782
I know simply DISTINCT won't work, so not sure what's the best way to get the outcome.
I found a way to do it via sub-query, but I want to do it in single query for better performance.
Plz Help!!
You can use ROW_NUMBER for this:
SELECT Seq, MobileNo, TransactionNo
FROM (
SELECT Seq, MobileNo, TransactionNo,
ROW_NUMBER() OVER (PARTITION BY MobileNo ORDER BY Seq DESC) AS rn
FROM mytable) AS t
WHERE t.rn = 1
The above query will pick exactly one record per MobileNo: the one having the greatest Seq value.
You can use group by.
select [Seq], [Mobile No], [Transaction No] from yourtable t1
inner join
(select [Mobile No], max([Transaction No]) as T_no from yourtable
group by [Mobile No]) t2
on t1.[Mobile No]=t2.[Mobile No] and t1.[Transaction No]=t2.T_no
Right query gives you latest [Transaction No] per [Mobile No] and left query is used only for finding matching [Seq].
CREATE TABLE #Transaction
(
Seq VARCHAR(12),
MobileNo VARCHAR(12),
TransactionNo VARCHAR(12)
)
INSERT INTO #Transaction VALUES
(1,'1234567890','ABC1234')
,(2,'2345678901','ABC2392')
,(3,'2345678901','ABC2782')
SELECT DT.Seq,DT.MobileNo,DT.TransactionNo FROM
(SELECT Seq,
MobileNo,
TransactionNo,
ROW_NUMBER() OVER(PARTITION BY MobileNo ORDER BY Seq) AS Rn
FROM
#Transaction) DT
WHERE DT.Rn = 1
I'd like to use the percentile_cont function to get median values in T-SQL. However, I also need to get mean values as well. I'd like to do something like the following:
SELECT CustomerID ,
AVG(Expenditure) AS MeanSpend , percentile_cont
( .5) WITHIN GROUP(ORDER BY Expenditure) OVER( ) AS MedianSpend
FROM Customers
GROUP BY CustomerID
Can this be accomplished? I know I can use the OVER clause to group the percentile_cont results...
but then I'm stuck using two queries, am I not?
Just figured it out... gotta drop the group by and give both aggregation functions a over statement.
SELECT CustomerID,
AVG(Expenditure) OVER(PARTITION BY CustomerID) AS MeanSpend,
percentile_cont(.5) WITHIN GROUP(ORDER BY Expenditure) OVER(PARTITION BY CustomerID) AS MedianSpend
FROM Customers
You can't use "group by" with window functions. These functions return the aggregated values for every row. One way is to use "select distinct" to get rid of the duplicate rows. Just make sure you partition each window function by the non-aggregated columns (groupId in this example).
--Generate test data
SELECT TOP(10)
value.number%3 AS groupId
, value.number AS number
INTO #data
FROM master.dbo.spt_values AS value
WHERE value."type" = 'P'
ORDER BY NEWID()
;
--View test data
SELECT * FROM #data ORDER BY groupId,number;
--CALCULATE MEDIAN
SELECT DISTINCT
groupId
, AVG(number) OVER(PARTITION BY groupId) AS mean
, percentile_cont(.5) WITHIN GROUP(ORDER BY number) OVER(PARTITION BY groupId) AS median
FROM #data
;
--Clean up
DROP TABLE #data;
I'm working with SQL Server 2005.
My query is:
SELECT (
SELECT COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
And the error:
The ORDER BY clause is invalid in views, inline functions, derived
tables, subqueries, and common table expressions, unless TOP or FOR
XML is also specified.
How can I use ORDER BY in a sub query?
This is the error you get (emphasis mine):
The ORDER BY clause is invalid in
views, inline functions, derived
tables, subqueries, and common table
expressions, unless TOP or FOR XML is
also specified.
So, how can you avoid the error? By specifying TOP, would be one possibility, I guess.
SELECT (
SELECT TOP 100 PERCENT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
If you're working with SQL Server 2012 or later, this is now easy to fix. Add an offset 0 rows:
SELECT (
SELECT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id OFFSET 0 ROWS
) as dorduncuay
Besides the fact that order by doesn't seem to make sense in your query....
To use order by in a sub select you will need to use TOP 2147483647.
SELECT (
SELECT TOP 2147483647
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
My understanding is that "TOP 100 PERCENT" doesn't gurantee ordering anymore starting with SQL 2005:
In SQL Server 2005, the ORDER BY
clause in a view definition is used
only to determine the rows that are
returned by the TOP clause. The ORDER
BY clause does not guarantee ordered
results when the view is queried,
unless ORDER BY is also specified in
the query itself.
See SQL Server 2005 breaking changes
Hope this helps,
Patrick
If building a temp table, move the ORDER BY clause from inside the temp table code block to the outside.
Not allowed:
SELECT * FROM (
SELECT A FROM Y
ORDER BY Y.A
) X;
Allowed:
SELECT * FROM (
SELECT A FROM Y
) X
ORDER BY X.A;
You don't need order by in your sub query. Move it out into the main query, and include the column you want to order by in the subquery.
however, your query is just returning a count, so I don't see the point of the order by.
A subquery (nested view) as you have it returns a dataset that you can then order in your calling query. Ordering the subquery itself will make no (reliable) difference to the order of the results in your calling query.
As for your SQL itself:
a) I seen no reason for an order by as you are returning a single value.
b) I see no reason for the sub query anyway as you are only returning a single value.
I'm guessing there is a lot more information here that you might want to tell us in order to fix the problem you have.
Add the Top command to your sub query...
SELECT
(
SELECT TOP 100 PERCENT
COUNT(1)
FROM
Seanslar
WHERE
MONTH(tarihi) = 4
GROUP BY
refKlinik_id
ORDER BY
refKlinik_id
) as dorduncuay
:)
maybe this trick will help somebody
SELECT
[id],
[code],
[created_at]
FROM
( SELECT
[id],
[code],
[created_at],
(ROW_NUMBER() OVER (
ORDER BY
created_at DESC)) AS Row
FROM
[Code_tbl]
WHERE
[created_at] BETWEEN '2009-11-17 00:00:01' AND '2010-11-17 23:59:59'
) Rows
WHERE
Row BETWEEN 10 AND 20;
here inner subquery ordered by field created_at (could be any from your table)
In this example ordering adds no information - the COUNT of a set is the same whatever order it is in!
If you were selecting something that did depend on order, you would need to do one of the things the error message tells you - use TOP or FOR XML
Try moving the order by clause outside sub select and add the order by field in sub select
SELECT * FROM
(SELECT COUNT(1) ,refKlinik_id FROM Seanslar WHERE MONTH(tarihi) = 4 GROUP BY refKlinik_id)
as dorduncuay
ORDER BY refKlinik_id
For me this solution works fine as well:
SELECT tbl.a, tbl.b
FROM (SELECT TOP (select count(1) FROM yourtable) a,b FROM yourtable order by a) tbl
Good day
for some guys the order by in the sub-query is questionable.
the order by in sub-query is a must to use if you need to delete some records based on some sorting.
like
delete from someTable Where ID in (select top(1) from sometable where condition order by insertionstamp desc)
so that you can delete the last insertion form table.
there are three way to do this deletion actually.
however, the order by in the sub-query can be used in many cases.
for the deletion methods that uses order by in sub-query review below link
http://web.archive.org/web/20100212155407/http://blogs.msdn.com/sqlcat/archive/2009/05/21/fast-ordered-delete.aspx
i hope it helps. thanks you all
For a simple count like the OP is showing, the Order by isn't strictly needed. If they are using the result of the subquery, it may be. I am working on a similiar issue and got the same error in the following query:
-- I want the rows from the cost table with an updateddate equal to the max updateddate:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype -- *** This causes an error***
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- *** To accomplish this, there are a few options:
-- Add an extraneous TOP clause, This seems like a bit of a hack:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT TOP 99.999999 PERCENT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- **** Create a temp table to order the maxCost
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
INTO #MaxCost
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
SELECT * FROM #Costs Cost
INNER JOIN #MaxCost CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, costs.costtype
Other possible workarounds could be CTE's or table variables. But each situation requires you to determine what works best for you. I tend to look first towards a temp table. To me, it is clear and straightforward. YMMV.
On possible needs to order a subquery is when you have a UNION :
You generate a call book of all teachers and students.
SELECT name, phone FROM teachers
UNION
SELECT name, phone FROM students
You want to display it with all teachers first, followed by all students, both ordered by. So you cant apply a global order by.
One solution is to include a key to force a first order by, and then order the names :
SELECT name, phone, 1 AS orderkey FROM teachers
UNION
SELECT name, phone, 2 AS orderkey FROM students
ORDER BY orderkey, name
I think its way more clear than fake offsetting subquery result.
I Use This Code To Get Top Second Salary
I am Also Get Error Like
The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified.
TOP 100 I Used To Avoid The Error
select * from (
select tbl.Coloumn1 ,CONVERT(varchar, ROW_NUMBER() OVER (ORDER BY (SELECT 1))) AS Rowno from (
select top 100 * from Table1
order by Coloumn1 desc) as tbl) as tbl where tbl.Rowno=2