Fork() to performe different processes - c

Question

I'm trying to use the multiple fork() calls to create several children with different task
I found a code on
Multiple child process
Which is really close for what I want , yet I couldn't fully understand it
pid_t firstChild, secondChild;
firstChild = fork();
if(firstChild != 0)
{
// In parent
secondChild = fork();
if(secondChild != 0)
{
// In parent
}
else
{
// In secondChild
}
}
else
{
// In firstChild
}
My questions are:
How many process have been created (I assume that we have 4 since it's 2 forks!)?
In this part of the code
firstChild = fork();
if(firstChild != 0)
{
// In parent
secondChild = fork();
if(secondChild != 0)
{
// In parent
}
Does "//in parent" mean both of them are the same process (they have the same PID when I tried to test it).
How can I create 3 children using 2 forks?( I can draw the tree that ends with 4 leaves 3 of them are children and 1 parent)
Thank you (please feel free to tell me if I'm not totally getting the Fork concept)

Answer 1

How many process have been created (I assume that we have 4 since it's 2 forks!)?
Depending on the result of your forks it should be 0 to 2. Probably 2 if nothing goes wrong. There's a parent process that forks 2 children processes.
Does "//in parent" mean both of them are the same process (they have the same PID when I tried to test it).
Yes. In your case the code is checking for a return value of fork being non zero. That's not a very good idea since it covers 2 distinct cases:
It could be less than zero indicating an error, or ...
It could be greater than zero indicating to the parent the pid of the newly spawned process
Anyway ... considering all goes well and both the forks succeed, you will end up with a parent process having 2 different children.
How can I create 3 children using 2 forks?( I can draw the tree that ends with 4 leaves 3 of them are children and 1 parent
Something like this should do the trick:
firstChild = fork();
if (firstChild < 0) {
exit(EXIT_FAILURE);
perror("fork");
}
secondChild = fork();
Notice that by not checking the return value of fork() any more I'm getting a child process continuing execution at the same place as the parent. So the next fork will actually be executed by both the parent and the children each spawning a new process. So I'll get something like this ...
parent─┬─child1───(child1's child)
└─child2
I can't think of any way you can get this with only 2 forks though:
parent─┬─child1
├─child3
└─child2
Note: It's customary on stackoverflow to only limit yourself to one question per topic.

Answer 2

The following code shows how to create 4 process (1 parent 3 children) with only 2 forks
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
#include <sys/types.h>
int *list;
void calculate_average(int );
void calculate_maximum(int);
void calculate_minimum(int);
void calculate_average(int count)
{
int i, total = 0;
for (i = 0; i < count; i++)
total += list[i];
double average = total / count;
printf("average is %f\n",average);
}
void calculate_maximum(int count)
{
int i;
int maximum = list[0];
for (i = 1; i < count; i++)
if (list[i] > maximum)
maximum = list[i];
printf("maximum is %d\n",maximum);
}
void calculate_minimum(int count)
{
int i;
int minimum = list[0];
for (i = 1; i < count; i++)
if (list[i] < minimum)
minimum = list[i];
printf("minimum is %d\n",minimum);
}
int main(int argc, char *argv[])
{
pid_t pid, pid1;
int num_of_args = argc-1;
int i;
/* allocate memory to hold array of integers */
list = malloc(sizeof(int)*num_of_args);
for (i = 0; i < num_of_args; i++)
list[i] = atoi(argv[i+1]);
printf("The %d number of input ingeters are\n",num_of_args);
for (i = 0; i < num_of_args; i++)
printf("%d\n",list[i]);
/* fork a child process */
pid = fork();
if (pid < 0) { /* error occurred */
fprintf(stderr, "Fork Failed\n");
return 1;
}
else if (pid == 0) { /* P2 */
pid1=getppid();
calculate_average(num_of_args);
}
else { /* P1 */
pid1=getpid();
wait(NULL);
}
pid = fork();
if (pid < 0) { /* error occurred */
fprintf(stderr, "Fork Failed\n");
return 1;
}
else if (pid == 0) { /* could be either P3 or P4 */
if (getppid() == pid1) { /* P3 */
calculate_minimum(num_of_args);
}
else { /* P4 */
calculate_maximum(num_of_args);
}
}
else {
wait(NULL);
}
return 0;
}
Note that one of the children will be a parent for a grandchild