Can somebody help me about how to query the average of this?
I have this table.
teacher | class | students | rating
-----------------------------------
T1 1 001 6
T1 1 002 6
T1 2 003 1
T1 3 004 1
T2 1 001 6
T2 1 002 6
T2 2 003 1
T2 3 004 1
if I do Select teacher, class, avg(rating) from table group by teacher, class then I get this:
teacher | class | rating
------------------------
T1 1 6
T1 2 1
T1 3 1
T2 1 6
T2 2 1
T2 3 1
what I want to do is get the average rating of that result and group it by teacher which is:
teacher | rating
------------------------
T1 2.66667
T2 2.66667
because if i do Select avg(rating) from table group by teacher, I get
teacher | rating
------------------------
T1 3.5
T2 3.5
You can do this:
SELECT teacher,avg(avgrating) as avgrating
FROM
(Select teacher, class, avg(rating) avgrating
from TableName
group by teacher, class) Temp
GROUP BY teacher
Result:
TEACHER AVGRATING
T1 2.666666
T2 2.666666
Sample result in SQL Fiddle.
OR:
SELECT T1.teacher,avg(T2.avgrating) as rating
FROM TableName T1 JOIN
(SELECT teacher,class,avg(rating) as avgrating
FROM TableName T2
GROUP BY teacher,class) T2 ON T1.teacher=T2.teacher
GROUP BY T1.teacher
SQL Fiddle.
use a nested select:
select teacher , avg(avgr) from
(Select teacher, class, avg(rating) avgr from table group by teacher, class) qry
group by teacher
Related
I have two tables.
Table1 has following data
Id1 Name Comments
--------------------
1 abc hgdhg
2 xyz mnoph
3 ysdfr jkljk
4 asdf iiuoo
5 pqrs liuoo
Table2 has following data
Id2 Id1 count date
-------------------------------
1 1 18 11/16/2005
2 1 1 11/15/2005
3 1 4 11/25/2005
4 2 4 11/22/2005
5 3 8 11/05/2005
6 3 3 11/30/2005
7 4 2 11/29/2005
8 3 0 11/04/2005
9 2 5 11/02/2005
10 3 9 11/22/2005
11 2 15 11/10/2005
12 5 12 11/19/2005
I want to return output as name, comments, sum of all count since 11/10/2005
I am trying the following query(with out date where condition)
select
Name, Comments, sum(count)
from
Table1 T1
join
Table2 T2 on T1.Id1 = T2.Id1
group by
ID1
But it is throwing error
Name is invalid in the select list because it is not contained in either an aggregate function or the Group by clause.
Can anyone help me with query (with the date where condition)? What's wrong with this?
Thanks in advance
You have to add any columns not contained in the aggregate function, and use where to filter the results:
select Name,
Comments,
sum(count)
from Table1 T1 join Table2 T2 on T1.Id1 = T2.Id1
where T2.[date] >= '11/10/2005'
group by Name, Comments
you can use below query
SELECT T1.Name ,
T1.Comments ,
SUM(T2.[count]) AS [count]
FROM Table1 T1
INNER JOIN Table2 T2 ON T1.Id1 = T2.Id1
WHERE CAST(T2.[date] AS DATE) >= CAST('11/10/2005' AS DATE)
GROUP BY T1.Name ,
T1.Comments
Every column in a select statement without an aggregate function needs to be in the group by sentence too to prevent aggregate errors, about limiting the date, use where clause to define the condition, like shows ahead.
select
Name, Comments, sum(count)
from
Table1 T1
join
Table2 T2 on T1.Id1 = T2.Id1
where
date >= '2005-11-10 00:00:00'
group by
Name, Comments
I am trying to join two tables but did not able to success
Test Supplier Table
SID NAME
1 Test
2 Test2
Test Stock Table
ID NewID SupID Qty
1 101 1 2
2 102 1 5
3 103 2 6
101 1 4
101 1 7
101 2 5
103 2 10
The output I am looking for
ID NAME Qty
2 Test 5
101 Test 13
101 Test2 5
103 Test2 16
My code is -
Select S.NAME, ST.ID, SUM(ST.Qty)
From Stock ST
Inner Join ST.SupID = S.SID
I need to combine those ID's which are matching with the new ID's with another ID's. If you see the results, I need to combine ID 1 qty with ID 101 because ID 1 has new ID 101 and no need to display ID 1. I have tried inner join but did not work.
First, you find those with NEW ID and those without NEW ID. For those with NewID, use NEWID, for those without use ID (old ID). then you use UNION ALL to combine both result and join to the Supplier table to obtain the NAME.
; with
cte as
(
-- with NewID
select ID = NewID, SupID, Qty = sum(Qty)
from Stock ST
where exists
(
select *
from Stock x
where x.ID = ST.NewID
)
group by NewID, SupID
union all
-- without NewID
select ID, SupID, Qty = sum(Qty)
from Stock ST
where not exists
(
select *
from Stock x
where x.ID = ST.NewID
)
group by ID, SupID
)
select c.ID, SP.NAME, Qty = sum(Qty)
from cte c
inner join Supplier SP on c.SupID = SP.SID
group by c.ID, SP.NAME
Start with the Stock table and join to the Supplier table (remembering to name the table in the join) and then self-left join to the IDs in the Stock table to determine if they exist or not. Then group by on whichever ID you want to keep.
SELECT
COALESCE(ST2.ID, ST.ID) ID
, S.NAME NAME
, SUM(ST.Qty) Qty
FROM Stock ST
INNER JOIN Supplier S
ON ST.SupID = S.SID
LEFT JOIN (
SELECT DISTINCT ID
FROM Stock
) ST2
ON ST.NewID = ST2.ID
GROUP BY
COALESCE(ST2.ID, ST.ID)
, S.NAME
I have three tables.
A
ID NAME
--- ----
1 abc
2 asd
3 qwe
B
ID INCOME
--- ------
1 2
2 3
1 4
C
NAME TOTAL
---- ----
abc 8
asd 20
I want to join this three tables with a SQL query to produce an output like
ID INCOME TOTAL
---------------
1 6 8
2 3 20
Could anyone help me?
You could try this:
select
t1.id, sum(t2.income) income, sum(t3.total) total
from
table1 t1
join
table2 t2 on t1.id = t2.id
join
table3 t3 on t3.name = t1.name
group by
t1.id
order by
t1.id
I have two tables having same columns.I want to get those columns whose values are distinct in both tables.How Can I achieve this?please help.Iam stuck.
imageid is primary key in both tables.Its not necessary that imageids present in first table should be present on second table.
first table
imageid name id
1 priya 001
2 neha 002
3 divya 003
4 santo 004
second table
imageid name id
1 priy 001
2 neha 003
4 santo 004
Result
imageid firstdata seconddata columnname
1 priy priya name
2 002 003 id
I have tried this-
select t1.imageid, t1.name as firstdata, t2.name as seconddata, 'name' as colname
from t1 join
t2
on t1.imageid = t2.imageid
where t1.name <> t2.name
union all
select t1.imageid, t1.id as firstdata, t2.id as seconddata, 'id'
from t1 join
t2
on t1.imageid = t2.imageid
where t1.id <> t2.id;
Actually I Have 136 columns and I want query to be optimized.
How can I write a SQL statement to select distinct data from three tables?
There are three tables
1)
Registration
id name contact
123 abc 123456789
2) bookingReg
PkBkID FkRegID ac_no
1 123 QT123
3) products
PkPro FkBkID pro_name Qty price
1 1 abc 2 150
2 1 def 1 400
3 1 ghi 5 500
4 1 abc 2 150
SELECT * FROM Registration as a
JOIN bookingReg as b ON (b.FkRegID = '123')
JOIN products as c ON (c.FkBkID = b.PkBkID )
I want distinct pro_name
Out put is
ac_no qty price
QT123 8 1050
HOw ?
Answer based on my assumption
SELECT pro_name,
ac_no,
SUM(qty) Sumqty,
SUM(price) SumPrice
FROM Registration a
JOIN bookingReg b
ON b.FkRegID = a.id
JOIN products c
ON c.FkBkID = b.PkBkID
GROUP BY pro_name, ac_no
EDIT Remove ac_no from SELECT and GROUP BY if you don't want to see this field in result.
Pls try this
SELECT A.ac_no, SUM(A.Qty) Qty, SUM(A.Price) Price
FROM
(
SELECT DISTINCT B.ac_no, P.Qty, P.Price
FROM Registration R
INNER JOIN bookingReg B ON B.FkRegID = R.id
INNER JOIN products P ON P.FkBkID = B.PkBkID
) A
GROUP BY A.ac_no