Applying a left shift in C [duplicate] - c

This question already has answers here:
Function to left shift a 2D array in C
(3 answers)
Closed 8 years ago.
I am learning how to manipulate a 2D array in C and I have to apply a left shift to a matrix, so A[0][0] becomes the value at A[0][1] etc. This is the code and output that I got after a few tries; I think I may be getting close:
void LeftShift2D(int A[M][N]){
int i;
int j;
int temp;
for(i = 0; i < M; i++){
for(j = 0; j < N; j++){
temp = A[0][0];
A[i][j] = A[i+1][j+1];
}
}
A[i][j] = temp;
}
Given this as the input:
14 17 28 26 24
26 17 13 10 2
3 8 21 20 24
17 1 7 23 17
12 9 28 10 3
21 3 14 8 26
this is the desired output:
17 28 26 24 26
17 13 10 2 3
8 21 20 24 17
1 7 23 17 12
9 28 10 3 21
3 14 8 26 14
but this is the actual output I'm getting:
14 17 28 26 24
26 17 13 10 2
3 8 21 20 24
17 1 7 23 17
12 9 28 10 3
21 3 14 8 26
4
17 13 10 2 3
8 21 20 24 17
1 7 23 17 12
9 28 10 3 21
3 14 8 26 4
-1218716075 -1217196044 0 -1079502888 134514340
What's wrong?

By far the easiest way to do what you want is:
void LeftShift2D(int A[M][N])
{
int i;
int temp = A[0][0];
int *base = &A[0][0];
for (i = 0; i < M * N - 1; i++)
base[i] = base[i+1];
A[i] = temp;
}
This treats the array as a vector and shifts the data down one space, rotating the value originally at the start to the end. If you wanted to rotate each row separately, you'd use different code, more closely related to what you show:
void LeftShift2D(int A[M][N])
{
int temp;
for (int i = 0; i < M; i++)
{
int j;
int temp = A[i][0]
for (j = 0; j < N - 1; j++)
A[i][j] = A[i][j+1];
A[i][j] = temp;
}
}
Your code has various problems. The A[i][j] = A[i+1][j+1]; assignment accesses data out of bounds, and copies data 'diagonally', copying the cell to the bottom-right (or south-east) of the current cell, not the cell to the right (east) of the current cell. It has problems wrapping, too.

You have a buffer overflow here
A[i][j] = A[i+1][j+1];
you need to iterate to i < M - 1 and j < N - 1.
You are accessing invalid memory which explains the observed values, that also invokes undefined behavior so you could observe some strange behavior eventually.

Related

Why is there a segmentation-fault error only with certain input values on pascal's triangle? (C)

I am trying to create a program outputting the pascal's triangle, using C in OnlineGDB and repl.it using a 2x2 array asking how many lines the user wants to print. The main problem is that the program works, but only until printing for 7 rows in onlinegdb, and only 3 rows in repl.it.
There is no error in OnlineGDB, and repl.it says "signal: segmentation fault (core dumped)"
Additionally, I added 3 "PASS" print lines to see where the error occurs, and when reaching the 8th line in onlineGDB it passes all 3 of the for statements filling the array. When reaching the 4th line in repl.it passes all 3 of the for statements filling the array, but both of them doesn't print out the correct numbers. Again, inputted numbers below these values show that all of the code works.
Is there a fix for this, or is it an error with websites handling arrays?
#include <stdio.h>
int main(void){
int intCount;
int intCount1;
int intRows;
int intColumns;
printf("HOW MANY ROWS DO YOU WANT?? ");
scanf("%i", &intRows);
intColumns = intRows;
int intNum[intRows][intColumns];
printf("PASS ");
// FIRST FILL ARRAY WITH 0
for(intCount = 0; intCount <= intRows+1; ++intCount){
for(intCount1 = 0; intCount1 <= intColumns+1; ++intCount1){
intNum[intCount][intCount1] = 0;
}
}
printf("PASS ");
// SET STARTING POINT (1)
intNum[0][0] = 1;
// NOW FILL ARRAY WITH PASCAL TRIANGLE
for(intCount = 0; intCount <= intRows; ++intCount){
for(intCount1 = 0; intCount1 <= intColumns; ++intCount1){
intNum[intCount+1][intCount1+1] = ((intNum[intCount][intCount1+1])+ (intNum[intCount][intCount1]));
}
}
printf("PASS\n");
// NOW PRINT ARRAY
for(intCount = 0; intCount <= intRows; ++intCount){
for(intCount1 = 0; intCount1 <= intColumns; ++intCount1){
// WITHOUT ZEROES:
/*if(intNum[intCount][intCount1] != 0){
printf("%5i",intNum[intCount][intCount1]);
}*/
// WITH ZEROES:
printf("%4i",intNum[intCount][intCount1]);
}
printf("\n");
}
return 0;
}
Logic: In the code above I created a 2 x 2 array with height and width dimensions one larger than the user asks for. I then fill the array with zeroes, and start with a 1 in the top left corner. From there I can use the pascals triangle formula by adding the two numbers above it
I tried changing the counting variables of arrays to make sure everything was correct, but it did not help. I originally coded on onlineGDB but used repl.it to see if there was any further errors, to which there was none. Additionally checked other questions on stack.
Desired Output:
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
OnlineGDB Output: (limited to 7 rows in the input)
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
repl.it Output: (limited to 3 rows in the input)
1
1 1
1 2 1
Note: In the output, my code also prints the 0s at the moment and the whole array so that I can visualize it. I am also 100% sure it's the same code uploaded to both
This could be something simple, but I appreciate all the help I can get. I'm more curious why the outputs are different on separate websites with the same code.
Why are you using loops like
for (intCount = 0; intCount <= intRows+1; ++intCount)
{
for (intCount1 = 0; intCount1 <= intColumns+1; ++intCount1)
{
intNum[intCount][intCount1] = 0;
}
}
when you allocated intNum[intRows][intColumns]? You are trampling way out of bounds. That's why your code crashes. That's why you get different behaviours in different systems.
Use:
for (int i = 0; i < intRows; i++)
{
for (int j = 0; j < int columns; j++)
intNum[i][j] = 0;
}
or an equivalent. Note that you use < and not <=; you use the declared limit, not that limit plus one.
Here is some working code, printing without the zeros. Your algorithm for generating the values in Pascal's Triangle was flawed on at least two counts. As before, it trampled way out of bounds of the array, and it also produced two rows with a single 1 in the output (when zeros were not printed). This code avoids those flaws. It also uses i and j as the loop counters — old Fortran programmers die hard.
/* SO 7549-7765 */
#include <stdio.h>
#include <stdlib.h>
int main(void)
{
int intRows;
int intColumns;
printf("How many rows do you want? ");
if (scanf("%i", &intRows) != 1)
{
fprintf(stderr, "failed to read an integer\n");
exit(1);
}
if (intRows < 1 || intRows > 64)
{
fprintf(stderr, "value %d is outside the range 1..64\n", intRows);
exit(1);
}
printf("Rows: %d\n", intRows);
intColumns = intRows;
int intNum[intRows][intColumns];
printf("PASS\n");
// First, fill array with zeros
for (int i = 0; i < intRows; i++)
{
for (int j = 0; j < intColumns; j++)
{
intNum[i][j] = 0;
}
}
printf("PASS\n");
// Set starting point (1)
intNum[0][0] = 1;
// Now fill array with Pascal's Triangle
for (int i = 1; i < intRows; i++)
{
intNum[i][0] = intNum[i-1][0];
for (int j = 1; j <= i; j++)
{
intNum[i][j] = intNum[i-1][j-1] + intNum[i-1][j];
}
}
printf("PASS\n");
// Now print array
for (int i = 0; i < intRows; i++)
{
for (int j = 0; j < intColumns; j++)
{
// Without zeros:
if (intNum[i][j] != 0)
printf(" %5d", intNum[i][j]);
// With zeros:
// printf(" %5d", intNum[i][j]);
}
printf("\n");
}
return 0;
}
Note the use of " %5d" in the printing format. That space ensures that the numbers remain separate even if there are 6 or more digits in the values (which first happens with 21 rows requested).
Sample output:
How many rows do you want? 15
Rows: 15
PASS
PASS
PASS
1
1 1
1 2 1
1 3 3 1
1 4 6 4 1
1 5 10 10 5 1
1 6 15 20 15 6 1
1 7 21 35 35 21 7 1
1 8 28 56 70 56 28 8 1
1 9 36 84 126 126 84 36 9 1
1 10 45 120 210 252 210 120 45 10 1
1 11 55 165 330 462 462 330 165 55 11 1
1 12 66 220 495 792 924 792 495 220 66 12 1
1 13 78 286 715 1287 1716 1716 1287 715 286 78 13 1
1 14 91 364 1001 2002 3003 3432 3003 2002 1001 364 91 14 1

Partition a Array

Given a randomly ordered array (arr) of n elements, function partitionArray(int arr[], int n, int x) partition the elements into two subsets such that elements <= x are in left subset and elements > x are in the right subset.
The first line of the test case will contain two numbers n (number of elements in a list ) and x (number to use for partition) separated by space.
The next line will contain N space-separated integers.
I am getting the wrong output for certain cases from the following Function.
Here's my code:
void partitionArray(int arr[], int n, int x)
{
int i, j, temp;
i = 0;
j = n-1;
while (i < j)
{
while (arr[i] <=x)
i++;
while (arr[j] > x)
j--;
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
i++;
j--;
}
}
For the cases I am getting the right output is:
10 6
28 26 25 5 6 7 24 29 6 10
For the cases I am not getting the right output is:
10 17
28 26 25 11 16 12 24 29 6 10
The output I am getting in this:
10
6
12
11
25
16
24
29
26
28
Expected Output:
10
6
12
11
16
25
24
29
26
28
10 6
28 26 25 11 5 7 24 29 6 10
The output I am getting in this:
6
25
5
11
26
7
24
29
28
10
Expected Output:
6
5
25
11
26
7
24
29
28
10
Can Anyone help me this
Below change will do:
if(i < j){
temp = arr[i];
arr[i] = arr[j];
arr[j] = temp;
}
When swapping when the value of j is i+1 and arr[i]<x and arr[j]>x, after i++ and j-- from while loops, the value of j is i-1 in your code. Hence checking i<j before swapping is important.
Suppose input is
2 5
1 10
Your output will be
10 1
And the index has to be checked as index may run out of the size of the array.
while (i<n && arr[i]<=x)
i++;
while (j>=0 && arr[j]>x)
j--;
Example inputs:
5 7
5 3 2 4 1
5 3
7 6 9 5 6

Eratosthenes prime numbers

I have created a program to search for prime numbers. It works without problems until the entered number is smaller than 52, when it is bigger output prints out some blank (0) numbers and I don't know why. Also other numbers have blank output.
My code is:
#include <stdio.h> //Prime numbers
#include <stdlib.h>
#include <math.h>
#include <string.h>
#include <unistd.h>
int c[100], n, a[50], d, e, b = 1;
void sort() {
for (int i = 1; i < n; i++) {
if (c[i] > 1) {
a[b] = c[i];
printf("%d %d %d\n", a[1], b, i);
b++;
e = 2;
d = 0;
while (d <= n) {
d = c[i] * e;
c[d - 1] = 0;
e++;
}
}
}
}
int main() {
printf("Enter number as an limit:\n");
scanf("%d", &n);
for (int i = 0; i < n; i++) {
c[i] = i + 1;
}
sort();
printf("Prime numbers between 1 and %d are:\n", n);
for (int i = 1; i < b; i++) {
printf("%d ", a[i]);
}
return 0;
}
Here is output for 25:
Enter number as an limit:
25
2 1 1
2 2 2
2 3 4
2 4 6
2 5 10
2 6 12
2 7 16
2 8 18
2 9 22
Prime numbers between 1 and 25 are:
2 3 5 7 11 13 17 19 23
But for 83 is:
Enter number as an limit:
83
2 1 1
2 2 2
2 3 4
2 4 6
2 5 10
2 6 12
2 7 16
2 8 18
2 9 22
2 10 28
2 11 30
2 12 36
2 13 40
2 14 42
2 15 46
2 16 52
0 17 58
0 18 60
0 19 66
0 20 70
0 21 72
0 22 78
0 23 82
Prime numbers between 1 and 83 are:
0 3 5 7 11 0 17 19 23 29 31 37 0 43 47 53 0 61 67 71 73 79 83
Blank spots always spots after 17th prime number. And always the blank numbers are the same. Can you help me please what is the problem?
The loop setting entries in c for multiples of c[i] runs too far: you should compute the next d before comparing against n:
for (d = c[i] * 2; d <= n; d += c[i]) {
c[d - 1] = 0;
}
As a matter of fact you could start at d = c[i] * c[i] because all lower multiples have already been seen during the previous iterations of the outer loop.
Also note that it is confusing to store i + 1 into c[i]: the code would be simpler with an array of booleans holding 1 for prime numbers and 0 for composite.
Here is a modified version:
#include <stdio.h>
int main() {
unsigned char c[101];
int a[50];
int n, b = 0;
printf("Enter number as a limit:\n");
if (scanf("%d", &n) != 1 || n < 0 || n > 100) {
printf("invalid input\n");
return 1;
}
for (int i = 0; i < n; i++) {
c[i] = 1;
}
for (int i = 2; i < n; i++) {
if (c[i] != 0) {
a[b] = i;
//printf("%d %d %d\n", a[0], b, i);
b++;
for (int d = i * i; d <= n; d += i) {
c[d] = 0;
}
}
}
printf("Prime numbers between 1 and %d are:\n", n);
for (int i = 0; i < b; i++) {
printf("%d ", a[i]);
}
printf("\n");
return 0;
}
Output:
chqrlie$ ./sieve4780
Enter number as a limit:
25
Prime numbers between 1 and 25 are:
2 3 5 7 11 13 17 19 23
chqrlie$ ./sieve4780
Enter number as a limit:
83
Prime numbers between 1 and 83 are:
2 3 5 7 11 13 17 19 23 29 31 37 41 43 47 53 59 61 67 71 73 79
Your problem seems to be caused by the fact that you have declared an array with size 50, but in fact it goes further than that: imagine you want to use Eratosthenes' procedure to find the first 10,000 prime numbers. Does this mean that you need to declare an array of size 10,000 first (or even bigger), risking to blow up your memory?
No: best thing to do is to work with collections where you don't need to set the maximum size at declaration time, like a linked list, a vector, ..., like that you can make your list grow as much as you like during runtime.

how to understand these code which rearrange (a1 a2...am b1 b2..bn ) in an array to(b1 b2 ..bn a1 a2..am) [closed]

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Closed 6 years ago.
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This code is designed by someone to change array [a1 a2...am b1 b2..bn ] to the array [b1 b2 ..bn a1 a2..am], but it involves the greatest common divisor which I can't get the point.
void Exchange(int a[],int m,int n,int s){
int p=m,temp=m+n;int k=s%p;
while(k!=0){temp=p;p=k;k=temp%p;}
for(k=0 ; k<p ;k++){ //below is where i cant't understand
temp=a[k];i=k;j=(i+m)%(m+n);
while(j!=k)
{a[i]=a[j];i=j;j=(j+m)%(m+n);}
a[i]=temp;
}
};
EDIT: "Properly" indented:
void Exchange(int a[], int m, int n, int s) {
int p = m, temp = m + n, k = s % p;
while (k != 0) {
temp = p;
p = k;
k = temp % p;
}
for (k = 0 ; k < p; k ++) { // below is where i cant't understand
temp = a[k];
i = k;
j = (i + m) % (m + n);
while (j != k) {
a[i] = a[j];
i = j;
j = (j + m) % (m + n);
}
a[i] = temp;
}
};
The code is using a single value of overhead to implement array rotation. If the lengths are mutually prime, a single pass suffices. If not, you have to repeat the shift cycle by the GCD of the lengths
I said earlier that there are other questions on SO that cover this. A look found SO 3333-3814 which deals with a single rotation. I did some messing with code to support that a while ago, demonstrating the need for GCD, but I didn't previously post it.
Here's the code — it uses C99 VLAs — variable length arrays.
#include <stdio.h>
static int gcd(int x, int y)
{
int r;
if (x <= 0 || y <= 0)
return(0);
while ((r = x % y) != 0)
{
x = y;
y = r;
}
return(y);
}
static void dump_matrix(int m, int n, int source[m][n])
{
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
printf("%4d", source[i][j]);
putchar('\n');
}
}
static void init_matrix(int m, int n, int source[m][n])
{
for (int i = 0; i < m; i++)
{
for (int j = 0; j < n; j++)
source[i][j] = (i + 1) * (j + 2);
}
}
static void rotate_1col(int n, int vector[n], int z)
{
z %= n;
if (z != 0)
{
int c = gcd(n, z);
int s = n / c;
for (int r = 0; r < c; r++)
{
int x = r;
int t = vector[x];
for (int i = 0; i < s; i++)
{
int j = (x + z) % n;
int v = vector[j];
vector[j] = t;
x = j;
t = v;
}
}
}
}
static void rotate_cols(int m, int n, int source[m][n], int z)
{
for (int i = 0; i < m; i++)
rotate_1col(n, source[i], z);
}
int main(void)
{
int m = 3;
for (int n = 2; n < 9; n++)
{
int source[m][n];
for (int z = 0; z <= n; z++)
{
init_matrix(m, n, source);
printf("Initial:\n");
dump_matrix(m, n, source);
rotate_cols(m, n, source, z);
printf("Post-rotate %d:\n", z);
dump_matrix(m, n, source);
putchar('\n');
}
}
return 0;
}
The code demonstrates different sizes of rotation on different sizes of array. Example sections of the output:
…
Initial:
2 3 4
4 6 8
6 9 12
Post-rotate 1:
4 2 3
8 4 6
12 6 9
…
Initial:
2 3 4 5
4 6 8 10
6 9 12 15
Post-rotate 3:
3 4 5 2
6 8 10 4
9 12 15 6
…
Initial:
2 3 4 5 6 7
4 6 8 10 12 14
6 9 12 15 18 21
Post-rotate 1:
7 2 3 4 5 6
14 4 6 8 10 12
21 6 9 12 15 18
Initial:
2 3 4 5 6 7
4 6 8 10 12 14
6 9 12 15 18 21
Post-rotate 2:
6 7 2 3 4 5
12 14 4 6 8 10
18 21 6 9 12 15
Initial:
2 3 4 5 6 7
4 6 8 10 12 14
6 9 12 15 18 21
Post-rotate 3:
5 6 7 2 3 4
10 12 14 4 6 8
15 18 21 6 9 12
…
Initial:
2 3 4 5 6 7 8 9
4 6 8 10 12 14 16 18
6 9 12 15 18 21 24 27
Post-rotate 4:
6 7 8 9 2 3 4 5
12 14 16 18 4 6 8 10
18 21 24 27 6 9 12 15
Initial:
2 3 4 5 6 7 8 9
4 6 8 10 12 14 16 18
6 9 12 15 18 21 24 27
Post-rotate 5:
5 6 7 8 9 2 3 4
10 12 14 16 18 4 6 8
15 18 21 24 27 6 9 12
Initial:
2 3 4 5 6 7 8 9
4 6 8 10 12 14 16 18
6 9 12 15 18 21 24 27
Post-rotate 6:
4 5 6 7 8 9 2 3
8 10 12 14 16 18 4 6
12 15 18 21 24 27 6 9
…
First of all, to get the result you said you expected, I have set m and n to be half the array size. I also assumed that s would be initialised to zero, in which case, the first while loop does not iterate. Also, there are several declarations missing in your code so my explanation makes some assumptions.
The variable p holds the number of array elements to swap;
// This is to keep the value to be overwritten by the swap
temp=a[k];
// This is the array index of the bottom half element to write the top half element to
i=k;
// this is to get the current index of the top half;
j=(i+m)%(m+n);
// This assignes the bottom index value with the top half value
while(j!=k)
{
// Write top half element to corresponding bottom half element
a[i]=a[j];
// We can now overwrite top half element; this assignes the index at wich to copy the bottom half element
i=j;
// This is to get out of the loop
j=(j+m)%(m+n);
}
// The bottom half element held at the beginning is now written to the top half at the corresponding index
a[i]=temp;
Hope this is the answer you were looking for. I arrived at this result by using a debugger and by stepping in the code line by line. I don't know if you know how to use a debugger but if not, then I highly recommend your lean how to use one; it it time well spent and it returns an awesome dividend :-)

Why is my code not making the entire array print in sequential order

an array is entered:
ary[] = [11 12 13 14 15 16 17 18 19 20 11 12 13 14 15 16 17 18 19 20 11 12 13 14 15 16 17 18 19 20 11 12 13 14 -1] (the negative one signifies that it is the end of the array)
a size is entered:
size = 34
I need this array to be rearranged so that it is in sequential order. Below is my code:
int x;
int numpasses;
int temp;
for(numpasses = 1; numpasses < size; numpasses++)
{
for(x = 0; x < size - numpasses; x++)
{
if(ary[x] > ary[x + 1] && ary[x] != ary[size - 1])
{
temp = ary[x];
ary[x] = ary[x + 1]; //THIS PORTION SWITHCHES TWO ADJECENT VALUES TO MAKE ARRAY SEQUENTIAL
ary[x + 1] = temp;
}
}
int a;
for(a = 0; a < size; a++)
{
printf("%d ", ary[a]);
}
}
This prints the numbers as follows:
11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 11 12 13 14 15 16 17 18 19 20 11 12 13 14
Replacing the line
if(ary[x] > ary[x + 1] && ary[x] != ary[size - 1])
by
if(ary[x] > ary[x + 1] )
worked fine for me.
I'll let you figure out why.
PS.
Please add
printf("\n");
after printing the array. It makes seeing the result at the end of the outer loop a little bit clearer.

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