I've some records in table_3 and I want to insert that record to table_2 but value of first column (Id) will be (NUMBER+1) of table_1. My code is
INSERT INTO TABLE_2(Id,NAME)
SELECT (SELECT MAX(NUMBER) FROM TABLE_1)+1 AS Id,name
FROM TABLE_3
Count of table_1 is 200. and count of TABLE_3 is 10. I want new inserted Ids are like
(201,202,203,204,205,206,207,208,209,210)
but from query am getting is like...
(201,201,201,201,201,201,201,201,201,201)
you can do it simply with only one select using ROW_NUMBER() and a group by
INSERT INTO TABLE_2(Id,NAME)
SELECT MAX(NUMBER) + ROW_NUMBER() OVER (ORDER BY name),name
FROM TABLE_3
group by name
In your query (SELECT MAX(NUMBER) FROM TABLE_1)+1 is always the same, since MAX(NUMBER) is just 200.
If you want to increment by 1 for each new record inserted, starting at (SELECT MAX(NUMBER) FROM TABLE_1)+1, try this:
INSERT INTO TABLE_2 (Id, NAME)
SELECT Id + rn, name
FROM (
SELECT (SELECT MAX(NUMBER) FROM TABLE_1) AS Id, name,
ROW_NUMBER() OVER (ORDER BY name) AS rn
FROM TABLE_3 ) t
Related
I have a large table (130 columns). It is a monthly dataset that is separated by month (jan,feb,mar,...). every month I get a small set of duplicate rows. I would like to remove one of the rows, it does not matter which row to be deleted.
This query seems to work ok when I only select the ID that I want to filter the dups on, but when I select everything "*" from the table I end up with all of the rows, dups included. My goal is to filter out the dups and insert the result set into a new table.
SELECT DISTINCT a.[ID]
FROM MonthlyLoan a
JOIN (SELECT COUNT(*) as Count, b.[ID]
FROM MonthlyLoan b
GROUP BY b.[ID])
AS b ON a.[ID] = b.[ID]
WHERE b.Count > 1
and effectiveDate = '01/31/2017'
Any help will be appreciated.
This will show you all duplicates per ID:
;WITH Duplicates AS
(
SELECT ID
rn = ROW_NUMBER() OVER (PARTITION BY ID ORDER BY ID)
FROM MonthlyLoan
)
SELECT ID,
rn
FROM Duplicates
WHERE rn > 1
Alternatively, you can set rn = 2 to find the immediate duplicate per ID.
Since your ID is dupped (A DUPPED ID!!!!)
all you need it to use the HAVING clause in your aggregate.
See the below example.
declare #tableA as table
(
ID int not null
)
insert into #tableA
values
(1),(2),(2),(3),(3),(3),(4),(5)
select ID, COUNT(*) as [Count]
from #tableA
group by ID
having COUNT(*) > 1
Result:
ID Count
----------- -----------
2 2
3 3
To insert the result into a #Temporary Table:
select ID, COUNT(*) as [Count]
into #temp
from #tableA
group by ID
having COUNT(*) > 1
select * from #temp
I want to find the recent duplicate records from SQL Server 2012. Here is the table structure I have.
I have table name called UserRegistration which contains the duplicate of UserID(GUID) and in same table, I have CreatedDate Column as well (Date). Now I want to find the recent duplicate records from this table.
Here is the same data.
id FirstName LastName CreatedDate UserID
109 FirstNameA LastNameA 28-04-2015 GUID1
110 FirstNameC LastNameD 19-05-2015 GUID2
111 FirstNameE LastNameF 22-05-2015 GUID1
If you notice on above tables, GUID 1 are having the duplicate, Now I want to find the recent one means it should return me only those rows with duplication but recent data. So in above table structure, it should return me 111 because record has been created recently compared to the 109. I believe you understand.
Do let me know if you have any question. I am happy to answer. Thanks. Awaiting for the reply.
Harshal
Try the below query this should do the work based on your i/p data -
create table #UserRegistration (id int,FirstName varchar(20),LastName varchar(20),CreatedDate date,UserID varchar(20))
insert into #UserRegistration
select 109, 'FirstNameA', 'LastNameA', '2015-04-28', 'GUID1' union
select 110, 'FirstNameC', 'LastNameD', '2015-05-19', 'GUID2' union
select 111, 'FirstNameE', 'LastNameF', '2015-05-22', 'GUID1'
select id, FirstName, LastName, CreatedDate, UserID from
(SELECT ur.*,row_number() over(partition by UserID order by CreatedDate) rn
FROM #UserRegistration ur) A
where rn > 1
You could use CTE. Group your records by UserID and give your particular row a rank ordered by CreatedDate.
insert into tab(id, FirstName, LastName, CreatedDate, UserID)
values(109, 'FirstNameA', 'LastNameA', '2015-04-28', 'guid1'),
(110, 'FirstNameC', 'LastNameD', '2015-05-19', 'guid2'),
(111, 'FirstNameE', 'LastNameF', '2015-05-22', 'guid1');
with cte as
(
select id, ROW_NUMBER() over (partition by UserID order by CreatedDate asc) as [Rank],
FirstName, LastName, CreatedDate, UserID
from tab
)
select id, FirstName, LastName, CreatedDate, UserID from cte where Rank > 1
Rank > 1 condition is responsible for retrieving duplicated items.
sqlfiddle link:
http://sqlfiddle.com/#!6/4d1f2/6
Solved this by using tmp-tables:
SELECT a.UserID,
MAX(a.CreatedDate) As CreatedDate
INTO #latest
FROM <your table> a
GROUP BY a.UserID
HAVING COUNT(a.UserID) > 1
SELECT b.id
FROM #latest a
INNER JOIN <your table> b ON a.UserID = b.UserID AND a.CreatedDate = b.CreatedDate
try this,
SELECT * FROM TableName tt WHERE
exists(select MAX(createdDate)
from TableName
where tt.UserID = UserID
group by UserID
having MAX(createdDate)= tt.createdDate)
I think your createddate field is not a date field, then try Format
WITH TempAns (id,UserID,duplicateRecordCount)
AS
(
SELECT id,
UserID,
ROW_NUMBER()OVER(partition by UserID ORDER BY id)
AS duplicateRecordCount
FROM #t
)
select * from #t where id in (
select max(id )
from TempAns
where duplicateRecordCount > 1
group by name )
You'd rank your records with ROW_NUMBER() to give all last records per userid #1. With COUNT() you make sure only to get the userids having more than one record.
select
id, firstname, lastname, createddate, userid
from
(
select
id, firstname, lastname, createddate, userid,
row_number() over (partition by userid oder by createddate desc) as rn,
count(*) over (partition by userid) as cnt
from userregistration
) ranked
where rn = 1 -- only last one
and cnt > 1; -- but only if there is more than one record for the userid
This gets the latest record for every userid that has duplicates.
I am trying to insert rows from one table to another that are not in the one I am moving them to. I also want to only move the ones that have the highest datestamp. (I want to only insert rows that are not in tb1 and have the max timestamp)
This is what I have so far:
INSERT INTO [db].[dbo].[tb1]
SELECT *
FROM tb2
WHERE ( dbo.tb2.STime = (SELECT Max(STime)
FROM dbo.tb2) )
AND ( EMPNO NOT IN (SELECT EMPNO
FROM [db].[dbo].[tb1]) );
I Get this error when I execute:
Msg 147, Level 15, State 1, Line 43 An aggregate may not appear in the
WHERE clause unless it is in a subquery contained in a HAVING clause
or a select list, and the column being aggregated is an outer
reference.
-EDIT
RESOLVED
WITH aggregateTime (maxTime) AS (
SELECT MAX(STime) AS maxTime
FROM tb2
)
INSERT INTO db.dbo.tb1
SELECT *
FROM tb2
INNER JOIN aggregateTime ON 1=1
WHERE tb2.STime = aggregateTime.maxTime AND EMPNO NOT IN (SELECT EMPNO FROM tb1);
You could use a CTE with just one column that is the maxtime from tb2. Then join on the CTE and reference it when checking for if its the max or not.
WITH aggregateTime (maxTime) AS (
SELECT MAX(STime) AS maxTime
FROM tb2
)
INSERT INTO tb1 (id, EMPNO, Street1)
SELECT id, EMPNO, Street1
FROM tb2
INNER JOIN aggregateTime ON 1=1
WHERE tb2.STime = aggregateTime.maxTime AND EMPNO NOT IN (SELECT EMPNO FROM tb1);
Working SQL Fiddle: http://sqlfiddle.com/#!6/141bf/4
I have a two tables like below
A
Id Name
1 a
2 b
B
Id Name
1 t
6 s
My requirement is to find the maximum id from table and display the name and id for that maximum without using case and if.
i findout the maximum by using below query
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
I findout the maximum 6 using the above query.but i can't able to find the name.I tried the below query but it's not working
SELECT MAX(id)
FROM (SELECT id,name FROM A
UNION
SELECT id,name FROM B) as c
How to find the name?
Any help will be greatly appreciated!!!
First combine the tables, since you need to search both. Next, determine the id you need. JOIN the id back with the temporarily created table to retreive the name that belongs to that id:
WITH tmpTable AS (
SELECT id,name FROM A
UNION
SELECT id,name FROM B
)
, max AS (
SELECT MAX(id) id
FROM tmpTable
)
SELECT t.id, t.name
FROM max m
JOIN tmpTable t ON m.id = t.id
You could use ROW_NUMBER(). You have to UNION ALL TableA and TableB first.
WITH TableA(Id, Name) AS(
SELECT 1, 'a' UNION ALL
SELECT 2, 'b'
)
,TableB(Id, Name) AS(
SELECT 1, 't' UNION ALL
SELECT 6, 's'
)
,Combined(Id, Name) AS(
SELECT * FROM TableA UNION ALL
SELECT * FROM TableB
)
,CTE AS(
SELECT *, RN = ROW_NUMBER() OVER(ORDER BY ID DESC) FROM Combined
)
SELECT Id, Name
FROM CTE
WHERE RN = 1
Just order by over the union and take first row:
SELECT TOP 1 * FROM (SELECT * FROM A UNION SELECT * FROM B) x
ORDER BY ID DESC
This won't show ties though.
For you stated that you used SQL Server 2008. Therefore,I used FULL JOIN and NESTED SELECT to get what your looking for. See below:
SELECT
(SELECT
1,
ISNULL(A.Id,B.Id)Id
FROM A FULL JOIN B ON A.Id=B.Id) AS Id,
(SELECT
1,
ISNULL(A.Name,B.Name)Name
FROM A FULL JOIN B ON A.Id=B.Id) AS Name
It's possible to use ROW_NUMBER() or DENSE_RANK() functions to get new numiration by Id, and then select value with newly created orderId equal to 1
Use:
ROW_NUMBER() to get only one value (even if there are some repetitions of max id)
DENSE_RANK() to get all equal max id values
Here is an example:
DECLARE #tb1 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
DECLARE #tb2 AS TABLE
(
Id INT
,[Name] NVARCHAR(255)
)
INSERT INTO #tb1 VALUES (1, 'A');
INSERT INTO #tb1 VALUES (7, 'B');
INSERT INTO #tb2 VALUES (4, 'C');
INSERT INTO #tb1 VALUES (7, 'D');
SELECT * FROM
(SELECT Id, Name, ROW_NUMBER() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
SELECT * FROM
(SELECT Id, Name, DENSE_RANK() OVER (ORDER BY Id DESC) AS [orderId]
FROM
(SELECT Id, Name FROM #tb1
UNION
SELECT Id, Name FROM #tb2) as tb3) AS TB
WHERE [orderId] = 1
Results are:
I have two columns:
namecode name
050125 chris
050125 tof
050125 tof
050130 chris
050131 tof
I want to group by namecode, and return only the name with the most number of occurrences. In this instance, the result would be
050125 tof
050130 chris
050131 tof
This is with SQL Server 2000
I usually use ROW_NUMBER() to achieve this. Not sure how it performs against various data sets, but we haven't had any performance issues as a result of using ROW_NUMBER.
The PARTITION BY clause specifies which value to "group" the row numbers by, and the ORDER BY clause specifies how the records within each "group" should be sorted. So partition the data set by NameCode, and get all records with a Row Number of 1 (that is, the first record in each partition, ordered by the ORDER BY clause).
SELECT
i.NameCode,
i.Name
FROM
(
SELECT
RowNumber = ROW_NUMBER() OVER (PARTITION BY t.NameCode ORDER BY t.Name),
t.NameCode,
t.Name
FROM
MyTable t
) i
WHERE
i.RowNumber = 1;
select distinct namecode
, (
select top 1 name from
(
select namecode, name, count(*)
from myTable i
where i.namecode = o.namecode
group by namecode, name
order by count(*) desc
) x
) as name
from myTable o
SELECT max_table.namecode, count_table2.name
FROM
(SELECT namecode, MAX(count_name) AS max_count
FROM
(SELECT namecode, name, COUNT(name) AS count_name
FROM mytable
GROUP BY namecode, name) AS count_table1
GROUP BY namecode) AS max_table
INNER JOIN
(SELECT namecode, COUNT(name) AS count_name, name
FROM mytable
GROUP BY namecode, name) count_table2
ON max_table.namecode = count_table2.namecode AND
count_table2.count_name = max_table.max_count
I did not try but this should work,
select top 1 t2.* from (
select namecode, count(*) count from temp
group by namecode) t1 join temp t2 on t1.namecode = t2.namecode
order by t1.count desc
Here are to examples that you could use but the temp table use is more efficient than the view, but was done on a small data sample. You would want to check your own statistics.
--Creating A View
GO
CREATE VIEW StateStoreSales AS
SELECT t.state,t.stor_id,t.stor_name,SUM(s.qty) 'TotalSales'
,ROW_NUMBER() OVER (PARTITION BY t.state ORDER BY SUM(s.qty) DESC) AS 'Rank'
FROM [dbo].[sales] s
JOIN [dbo].[stores] t ON (s.stor_id = t.stor_id)
GROUP BY t.state,t.stor_id,t.stor_name
GO
SELECT * FROM StateStoreSales
WHERE Rank <= 1
ORDER BY TotalSales Desc
DROP VIEW StateStoreSales
---Using a Temp Table
SELECT t.state,t.stor_id,t.stor_name,SUM(s.qty) 'TotalSales'
,ROW_NUMBER() OVER (PARTITION BY t.state ORDER BY SUM(s.qty) DESC) AS 'Rank' INTO #TEMP
FROM [dbo].[sales] s
JOIN [dbo].[stores] t ON (s.stor_id = t.stor_id)
GROUP BY t.state,t.stor_id,t.stor_name
SELECT * FROM #TEMP
WHERE Rank <= 1
ORDER BY TotalSales Desc
DROP TABLE #TEMP