This is my Python Program that I have been having some issues with:
-- coding: cp1252 --
from time import gmtime, strftime
print("Welcome to the PiggyBank version 1.")
num_write = int(input("How much money would you like to store in your PiggyBank?"))
f = open("PiggyBanks_Records.txt", "w")
current_time = strftime("%Y-%m-%d %H:%M:%S", gmtime())
convert_1 = str(current_time)
convert_2 = str(int(num_write))
add_1 = ("\n" + convert_1 + " £" + convert_2)
add_2 = ("\n" + add_1) #Tried to make it so new line is added every time the program is run
final_record = str(add_2)
print("Final file written to the PiggyBank: " + final_record)
#Write to File
f.write(final_record)
f.close()
Right now whenever the program writes to the file it over-writes. I would preferably would like to keep, like a history of the amounts added. If anyone can help so the string that needs to be written to the .txt file goes down by one line and essentially keeps going for ever. I am also open to any suggestion on how I can shorten this code.
You need to open your file with append mode :
f = open("PiggyBanks_Records.txt", "a")
Using the 'w' write option with open automatically looks for the specified file, and deletes its contents if it already exists (which you can read about here) or creates it if it doesn't. Use 'a' instead to add / append to the file.
Related
I have this code portion for instance :
fichiers=glob.glob('/path/*.file')
for f in fichiers:
if os.path.isfile(f):
fichier = open(f,'r')
for l in fichier:
m = regex.match(l)
if m:
print('%s/ EMO /%s'%(m.group(1),m.group(3)))
#here I want to write this modified line
else:
#write line non modified
fichier.close()
And I would like, instead of printing results in the shell, apply the substitution to all lines of each line with copying files with new names or in a new directory (to be sure not making mistakes).
Have you some idea to teach me how to do that please ?
It's really quite simple: all you need to do is define your output directory and open a new file in that directory to write to, every time you open a file that you read. Check this out:
import glob
import os
outdirpath = "/path/to/output/directory"
for fpath in glob.glob('/path/*.file'):
if not os.path.isfile(fpath): continue
with open(fpath) as fichier, open(os.path.join(outdirpath, os.path.basename(fpath)), 'w') as outfile:
for line in fichier:
m = regex.match(line)
if m:
outfile.write('%s/ EMO /%s'%(m.group(1),m.group(3)))
else:
outfile.write(line)
i have this function: write_reversed_file(input_filename, output_filename) that writes to the given output file the contents of the given input file with the lines in reversed order. i just need the output to be written to the file (output_filename) rather than to the terminal (python shell).
the only part im missing is to store the output into the file.
i successfully managed to complete the reversing lines part.
def write_reversed_file(input_filename, output_filename):
for line in reversed(list(open(filename))):
print(line.rstrip())
def write_reversed_file(input_filename, output_filename):
s = ""
f = open(input_filename,"r")
lines = f.read().split("\n")
f.close()
for line in reversed(lines):
s+=line.rstrip()+"\n"
f = open(outPutFile.txt,"w")
f.write(s)
f.close()
It is good practice to use 'with open as' format when working with files since it is automatically closing the file for us. (as recommended in docs.python.org)
def write_reversed_file(input_filename, output_filename):
with open(output_filename, 'w') as f:
with open(input_filename, 'r') as r:
for line in reversed(list(r.read())):
f.write(line)
write_reversed_file("inputfile.txt", "outputfile.txt")
How can I get Python to loop through a directory and find a specific string in each file located within that directory, then output a summary of what it found?
I want to search the long files for the following string:
FIRMWARE_VERSION = "2.15"
Only, the firmware version can be different in each file. So I want the log file to report back with whatever version it finds.
import glob
import os
print("The following list contains the firmware version of each server.\n")
os.chdir( "LOGS\\" )
for file in glob.glob('*.log'):
with open(file) as f:
contents = f.read()
if 'FIRMWARE_VERSION = "' in contents:
print (file + " = ???)
I was thinking I could use something like the following to return the extra characters but it's not working.
file[:+5]
I want the output to look something like this:
server1.web.com = FIRMWARE_VERSION = "2.16"
server2.web.com = FIRMWARE_VERSION = "3.01"
server3.web.com = FIRMWARE_VERSION = "1.26"
server4.web.com = FIRMWARE_VERSION = "4.1"
server5.web.com = FIRMWARE_VERSION = "3.50"
Any suggestions on how I can do this?
You can use regex for grub the text :
import re
for file in glob.glob('*.log'):
with open(file) as f:
contents = f.read()
if 'FIRMWARE_VERSION = "' in contents:
print (file + '='+ re.search(r'FIRMWARE_VERSION ="([\d.]+)"',contents).group(1))
In this case re.search will do the job! with searching the file content based on the following pattern :
r'FIRMWARE_VERSION ="([\d.]+)"'
that find a float number between two double quote!also you can use the following that match anything right after FIRMWARE_VERSIONbetween two double quote.
r'FIRMWARE_VERSION =(".*")'
Python 3 program allows people to choose from list of employee names.
Data held on text file look like this: ('larry', 3, 100)
(being the persons name, weeks worked and payment)
I need a way to assign each part of the text file to a new variable,
so that the user can enter a new amount of weeks and the program calculates the new payment.
Below is my code and attempt at figuring it out.
import os
choices = [f for f in os.listdir(os.curdir) if f.endswith(".txt")]
print (choices)
emp_choice = input("choose an employee:")
file = open(emp_choice + ".txt")
data = file.readlines()
name = data[0]
weeks_worked = data[1]
weekly_payment= data[2]
new_weeks = int(input ("Enter new number of weeks"))
new_payment = new_weeks * weekly_payment
print (name + "will now be paid" + str(new_payment))
currently you are assigning the first three lines form the file to name, weeks_worked and weekly_payment. but what you want (i think) is to separate a single line, formatted as ('larry', 3, 100) (does each file have only one line?).
so you probably want code like:
from re import compile
# your code to choose file
line_format = compile(r"\s*\(\s*'([^']*)'\s*,\s*(\d+)\s*,\s*(\d+)\s*\)")
file = open(emp_choice + ".txt")
line = file.readline() # read the first line only
match = line_format.match(line)
if match:
name, weeks_worked, weekly_payment = match.groups()
else:
raise Exception('Could not match %s' % line)
# your code to update information
the regular expression looks complicated, but is really quite simple:
\(...\) matches the parentheses in the line
\s* matches optional spaces (it's not clear to me if you have spaces or not
in various places between words, so this matches just in case)
\d+ matches a number (1 or more digits)
[^']* matches anything except a quote (so matches the name)
(...) (without the \ backslashes) indicates a group that you want to read
afterwards by calling .groups()
and these are built from simpler parts (like * and + and \d) which are described at http://docs.python.org/2/library/re.html
if you want to repeat this for many lines, you probably want something like:
name, weeks_worked, weekly_payment = [], [], []
for line in file.readlines():
match = line_format.match(line)
if match:
name.append(match.group(1))
weeks_worked.append(match.group(2))
weekly_payment.append(match.group(3))
else:
raise ...
I'm running a script made in Groovy from Soap UI and the script needs to generate lots of files.
Those files have also in the name two numbers from a list (all the combinations in that list are different), and there are 1303 combinations
available and the script generates just 1235 files.
A part of the code is:
filename = groovyUtils.projectPath + "\\" + "$file"+"_OK.txt";
targetFile = new File(filename);
targetFile.createNewFile();
where $file is actually that part of the file name which include those 2 combinations from that list:
file = "abc" + "-$firstNumer"+"_$secondNumber"
For those file which are not created is a message returned:"The filename, directory name or volume label syntax is incorrect".
I've tried puting another path:
filename = "D:\\rez\\" + "\\" + "$file"+"_OK.txt";
targetFile = new File(filename);
targetFile.createNewFile();
and also:
File parentFolder = new File("D:\\rez\\");
File targetFile = new File(parentFolder, "$file"+"_OK.txt");
targetFile.createNewFile();
(which I've found here: What are possible reasons for java.io.IOException: "The filename, directory name, or volume label syntax is incorrect")
but nothing worked.
I have no ideea where the problem is. Is strange that 1235 files are created ok, and the rest of them, 68 aren't created at all.
Thanks,
My guess is that some of the files have illegal characters in their paths. Exactly which characters are illegal is platform specific, e.g. on Windows they are
\ / : * ? " < > |
Why don't you log the full path of the file before targetFile.createNewFile(); is called and also log whether this method succeeded or not, e.g.
filename = groovyUtils.projectPath + "\\" + "$file"+"_OK.txt";
targetFile = new File(filename);
println "attempting to create file: $targetFile"
if (targetFile.createNewFile()) {
println "Successfully created file $targetFile"
} else {
println "Failed to create file $targetFile"
}
When the process is finished, check the logs and I suspect you'll see a common pattern in the ""Failed to create file...." messages
File.createNewFile() returns false when a file or directory with that name already exists. In all other failure cases (security, I/O) it throws an exception.
Evaluate createNewFile()'s return value or, additionally, use the File.exists() method:
File file = new File("foo")
// works the first time
createNewFile(file)
// prints an error message
createNewFile(file)
void createNewFile(File file) {
if (!file.createNewFile()) {
assert file.exists()
println file.getPath() + " already exists."
}
}