I am making a game from a batch file and one of the inputs can accept any character (~!##$%^&*()`) and any other. Is there any way to look for any character other than numbers and use the GOTO command? This is my script so far:
set /p guess=
echo "%guess%"|findstr /L "[a-z][A-Z]~`!##$%^&*()-_=+\^|^^;:"',<.>/?*"
if %errorlevel% == 0 goto Invalid_Number
if %guess% == %number% goto Correct
... everything else here ...
:Invalid_Number
echo Invalid Number. Input must be a number
pause
Is there any way to make this work, all it says is Access Denied, I am testing this on a school computer though, it might not work.
Put this at the bottom of your script:
:isInt <str>
for /f "delims=0123456789" %%a in ("%1") do exit /b 1
exit /b 0
Then to invoke it, do
call :isInt %guess% && success || fail
Here's a more complete example:
#echo off
setlocal
set /a rand = %RANDOM% %% 10 + 1
:begin
set /P "guess=Guess a number between 1 and 10: "
call :isInt %guess% || goto invalid
if %guess% gtr 0 if %guess% lss 11 (
if %guess% equ %rand% (
echo Lucky guess!
exit /b
) else (
echo Oooh, so close. Try again.
goto begin
)
)
:invalid
echo Please enter a valid integer between 1 and 10.
goto begin
:isInt <str>
for /f "delims=0123456789" %%a in ("%1") do exit /b 1
exit /b 0
This is the same basic idea as MC ND's solution, but instead of using the for statement to unset %guess%, it sets %errorlevel% and stops looping at the first non-numeric character. This makes it infinitesimally more efficient. :)
And with either success or fail, I like to use conditional execution (the && and || stuff).
:ask
set /p "guess=?" || goto :ask
setlocal enabledelayedexpansion
for /f "delims=0123456789" %%a in ("!guess!") do set "guess="
endlocal & set "guess=%guess%"
if not defined guess (
echo invalid input
goto ask
)
echo valid input
The basic idea behind the test is to use the numbers as delimiters in a for /f command, so they are removed from the input. If anything remains it is not a number and the code in the do clause is executed.
The delayedexpansion is enabled/disabled to handle problematic characters (specially double quotes) that could be typed in the input field.
May I suggest you a different, better approach? Instead of read any line and then check if it contains a number, your program may directly read a number, so the checking is not necessary. The way to do that is emulating SET /P command via a subroutine. This way, you may add additional constraints to the input, like read a maximum number of digits, for example.
#echo off
rem Read a number emulating SET /P command
rem Antonio Perez Ayala
setlocal
rem Define the following variable before call InputNumber subroutine
set "thisFile=%~F0"
call :InputNumber number="Enter a number of up to 5 digits: " 5
echo Number read: %number%
goto :EOF
:InputNumber var="prompt" [digits]
setlocal EnableDelayedExpansion
rem Initialize variables
if "%~3" equ "" (set numDigits=9) else set "numDigits=%3"
set "digits=0123456789"
for /F %%a in ('copy /Z "%thisFile%" NUL') do set "CR=%%a"
for /F %%a in ('echo prompt $H ^| cmd') do set "BS=%%a"
rem Show the prompt and start reading
set /P "=%~2" < NUL
set "input="
set i=0
:nextKey
set "key="
for /F "delims=" %%a in ('xcopy /W "%thisFile%" "%thisFile%" 2^>NUL') do if not defined key set "key=%%a"
rem If key is CR: terminate input
if "!key:~-1!" equ "!CR!" goto endRead
rem If key is BS: delete last char, if any
set "key=!key:~-1!"
if "!key!" equ "!BS!" (
if %i% gtr 0 (
set /P "=!BS! !BS!" < NUL
set "input=%input:~0,-1%"
set /A i-=1
)
goto nextKey
)
rem If key is not a digit: ignore it
if "!digits:%key%=!" equ "%digits%" goto nextKey
rem If can not accept more digits: ignore it
if %i% equ %numDigits% goto nextKey
rem Else: show and accept the digit
set /P "=%key%" < NUL
set "input=%input%%key%"
set /A i+=1
goto nextKey
:endRead
echo/
endlocal & set "%~1=%input%"
exit /B
You may also add any other processing to the input line, like show asterisks instead of digits, etc. For a large example on this topic, see this post
Related
I would like write a batch file to count the number of occurrences of a specific character in each line of a text file.
For example, the count of \ in the string "aa\bb\cc\dd\" would be 4.
The find and the findstr show only the number of lines which is contains the exact character.
You might try the following script, providing the input string as (quoted) command line argument:
set "STRING=%~1$"
set STRING="%STRING:\=" "%"
set /A "COUNT=-1"
for %%E in (%STRING%) do set /A "COUNT+=1"
echo Count of `\`: %COUNT%
This replaces every character to be counted by " + SPACE + " and encloses the entire string in between "", so the input string aa\bb\cc\dd\ becomes "aa" "bb" "cc" "dd" "". The resulting string is fed into a for loop that recognises individual items to iterate through -- five in this case. The counter variable COUNT is initialised with a value of -1, so the result is not the number of iterated items but the separators, namely the \ characters present in the original string.
This approach fails if the string contains ? or * characters. It would also fail in case the character to count is one of the following: ", %, =, *, ~.
#echo off
setlocal
set "string=aa\bb\cc\dd\"
set "count=-1"
for %%a in ("%string:\=" "%") do set /A count+=1
echo %count%
This method works correctly as long as the string don't include wild-card characters: *?; if this is required, I would use the same npocmaka's method, but written in a simpler way:
#echo off
setlocal EnableDelayedExpansion
set "string=aa\bb\cc\dd\"
set "str=A%string%Z"
set "count=-1"
for /F "delims=" %%a in (^"!str:\^=^"^
% Do NOT remove this line %
^"!^") do (
set /A count+=1
)
echo %count%
While slow, you can try with this
#echo off
setlocal enableextensions disabledelayedexpansion
set "inputFile=input.txt"
set "searchChar=\"
for /f "delims=" %%a in ('
findstr /n "^" "%inputFile%"
') do for /f "delims=:" %%b in ("%%~a") do (
set "line=%%a"
for /f %%c in ('
cmd /u /v /e /q /c"(echo(!line:*:=!)"^|find /c "%searchChar%"
') do echo Line %%b has %%c characters
)
The input file is readed using findstr /n to get all the lines in the file with a number prefix (both for output "decoration" and to ensure all the lines in the file are processed). Each line is processed inside a pipe, from cmd to find. The cmd instance is started with unicode output (/u) so when the readed line is echoed, the output will be a two bytes sequence for each input character, one of them a 0x0 ASCII character. The find command sees the 0 as a line terminator, so we get each character in the input line as one separated line. Now, the find command counts in how many lines the searched character happens.
#ECHO OFF
SETLOCAL
SET "String=a\b\c\\\\d"
CALL :count "%string%" \
ECHO %tally%
GOTO :EOF
:count
SETLOCAL enabledelayedexpansion
SET /a tally=0
SET "$2=%~1"
:cloop
SET "$1=%$2%"
SET "$2=!$1:*%2=!"
IF "%$1%" neq "%$2%" SET /a tally+=1&GOTO cloop
endlocal&SET tally=%tally%
GOTO :eof
Here's a way to count particular characters in a string. It won't work for the usual suspects.
here's one way:
#echo off
:checkCountOf string countOf [rtnrVar]
:: checks count of a substring in a string
setlocal EnableDelayedExpansion
set "string=aa"
set "string=%~1"
set "checkCountOf=%~2"
if "%~1" equ "" (
if "%~3" neq "" (
endlocal & (
echo 0
set "%~3=0"
exit /b 0
)
) else (
endlocal & (
echo 0
exit /b 0
)
)
)
if "!checkCountOf!" equ "$" (
set "string=#%string%#"
set "string=!string:%checkCountOf%%checkCountOf%=#%checkCountOf%#%checkCountOf%#!"
) else (
set "string=$%string%$"
set "string=!string:%checkCountOf%%checkCountOf%=$%checkCountOf%$%checkCountOf%$!"
)
set LF=^
rem ** Two empty lines are required
set /a counter=0
for %%L in ("!LF!") DO (
for /f "delims=" %%R in ("!checkCountOf!") do (
set "var=!string:%%~R%%~R=%%~L!"
set "var=!var:%%~R=%%~L!"
for /f "tokens=* delims=" %%# in ("!var!") do (
set /a counter=counter+1
)
)
)
if !counter! gtr 0 (
set /a counter=counter-1
)
if "%~3" neq "" (
endlocal & (
echo %counter%
set "%~3=%counter%"
)
) else (
endlocal & (
echo %counter%
)
)
you can call it like:
call ::checkCountOf "/aa/b/c/" "/" slashes
echo %slashes%
exit /b %errorlevel%
wont work with some special characters (",~ and !)
You can also use replacement and the :strlen function
Not tested extensively but works with your example.
#ECHO OFF
SETLOCAL disabledelayedexpansion
SET "String=\a\b\c\\\\d\\"
set "previous=%string%"
set /a count=0
:loop
set "newstg=%previous:*\=%"
IF NOT "%previous%"=="%newstg%" (
set /a count+=1
set "previous=%newstg%"
IF DEFINED previous goto loop
)
echo %count%
pause
GOTO :eof
Here is one more option. I don't think this is bullet proof with poison characters.
#ECHO OFF
SETLOCAL disabledelayedexpansion
SET "String=\\a\b\c\\\\d\\"
set i=0
set "x=%string%"
set "x=%x:\=" & set /A i+=1 & set "x=%"
echo %i%
pause
I want to count all the characters of a certain text. However in my code it only counts single string. But the requirement needs to count all characters including whites spaces and new line.. For example:
Hello World!
How are you today?
Hope you are okay
How am i going to do that in my code?Thanks.
My code:
#ECHO OFF
for %%i in (y.txt) do #set count=%%~zi
REM Set "string" variable
SET string=(Hello World
How are you today?
Im fine..) // i want to read these string because my code only read single string
REM Set the value of temporary variable to the value of "string" variable
SET temp_str=%string%
REM Initialize counter
SET str_len=0
:loop
if defined temp_str (
REM Remove the first character from the temporary string variable and increment
REM counter by 1. Countinue to loop until the value of temp_str is empty string.
SET temp_str=%temp_str:~1%
SET /A str_len += 1
GOTO loop
)
REM Echo the actual string value and its length.
ECHO %string% is %str_len% characters long!
this is all, you need:
#ECHO OFF
set /p "file=enter filename: "
for %%i in (%file%) do #set count=%%~zi
echo this file has %count% characters including whitespaces and special chars like line-feed/carriage-return etc.
With this function you can calculate the line number, the number of words and the number of characters in a text file
#ECHO OFF
SETLOCAL ENABLEDELAYEDEXPANSION
SET "MOD=%1"
SET "ARC=%2"
IF %MOD%==/L GOTO :CONTLIN
IF %MOD%==/P GOTO :CONTPAL
IF %MOD%==/C GOTO :CONTCAR
:CONTLIN
FOR /f "TOKENS=*" %%z IN (%ARC%) DO SET /a LINEAS+=1
ECHO %LINEAS%
EXIT /b 0
:CONTPAL
FOR /f "TOKENS=*" %%x IN (%ARC%) DO FOR %%y IN (%%x) DO SET /a PALABRAS+=1
ECHO %PALABRAS%
EXIT /b 0
:CONTCAR
SETLOCAL
FOR /f "TOKENS=*" %%a IN (%ARC%) DO (FOR %%b IN (%%a) DO (FOR %%a IN (%%b) DO (SET
A=%%a)&(CALL :CC !A!)))
ECHO %CARACTERES%
EXIT /b 0
:CC
SET B=!A!
:I
SET /a CARACTERES+=1
SET B=%B:~1%
IF DEFINED B GOTO :I
EXIT /b 0
And I could access it from a file like this:
#ECHO OFF
SET ARCHIVO=TEXTO.TXT
FOR /F %%a IN ('CONTTEXT /L %ARCHIVO%') DO SET /a LINEAS=%%a
FOR /F %%a IN ('CONTTEXT /P %ARCHIVO%') DO SET /a PALABRAS=%%a
FOR /F %%a IN ('CONTTEXT /C %ARCHIVO%') DO SET /a CARACTERES=%%a
ECHO %LINEAS% LINEAS
ECHO %PALABRAS% PALABRAS
ECHO %CARACTERES% CARACTERES
PAUSE
How can I check that the first character of a string is a letter and so that it is not a number, or rather a cipher? There are no spaces or special characters in this string.
#ECHO OFF
SETLOCAL
SET /a num=5678
CALL :initnum
SET "num=hello"
CALL :initnum
SET "num=4ello"
CALL :initnum
SET "num=hell0"
CALL :initnum
SET "num=he8lo"
CALL :initnum
SET "num="
CALL :initnum
ECHO(==============
SET /a nam=7654
SET "nem=hello"
SET "nim=4ello"
SET "nom=hell0"
SET "num=he8lo"
SET "nzm="
CALL :initnum2 nam
CALL :initnum2 nem
CALL :initnum2 nim
CALL :initnum2 nom
CALL :initnum2 num
CALL :initnum2 nzm
GOTO :EOF
:initnum
IF NOT DEFINED num ECHO NUM is empty, so it doesn't begin with a numeric&GOTO :EOF
FOR /l %%a IN (0,1,9) DO IF %num:~0,1%==%%a ECHO %num% Begins with numeric&GOTO :EOF
ECHO %num% Does NOT begin with a numeric
GOTO :eof
:initnum2
IF NOT DEFINED %1 ECHO %1 is empty, so it doesn't begin with a numeric&GOTO :EOF
CALL SET "$1=%%%1%%"
FOR /l %%a IN (0,1,9) DO IF %$1:~0,1%==%%a ECHO %1 (%$1%) Begins with numeric&GOTO :EOF
ECHO %1 (%$1%) Does NOT begin with a numeric
GOTO :eof
You should be able to get what you want from this demo.
#echo off
setlocal enableextensions disabledelayedexpansion
set "var=1hello"
for /f "tokens=* delims=0123456789" %%a in ("%var%") do (
if not "%%a"=="%var%" echo var starts with a number
)
If the var contents starts with a number, the token/delim management in the for command will remove it.
edited just to include the usual (included the previous code) and some less used options just in case someone is interested
#echo off
setlocal enableextensions disabledelayedexpansion
set "var=1hello"
echo(%var%
rem Option 1 - Use the for command to tokenize the string
rem A dot is added to handle empty vars
for /f "tokens=* delims=0123456789" %%a in ("%var%.") do (
if not "%%a"=="%var%." (
echo var starts with a number
) else (
echo var does not start with a number
)
)
rem Option 2 - Use set arithmetic and detect errors
rem This will fail if the string starts with + or -
set "%var%_=0"
set /a "test=%var%_" 2>nul
if not errorlevel 1 (
echo var does not start with a number
) else (
echo var starts with a number
)
rem Option 3 - Use substring operations and logic operators
set "test=%var%."
if "%test:~0,1%" GEQ "0" if "%test:~0,1%" LEQ "9" set "test="
if defined test (
echo var does not start with a number
) else (
echo var starts with a number
)
rem Option 4 - Use findstr
rem This is SLOW as findstr needs to be executed
echo(%var%|findstr /b /r /c:"[0-9]" >nul && (
echo var starts with a number
) || (
echo var does not start with a number
)
I think this is the simplest way:
#echo off
setlocal EnableDelayedExpansion
set digits=0123456789
set var=1something
if "!digits:%var:~0,1%=!" neq "%digits%" (
echo First char is digit
) else (
echo First char is not digit
)
The first character of var is tried to be removed from digits string. If such a char was a digit, digits string change; otherwise, digits string remains the same.
#echo off
setlocal
set "the_string=a23something"
for /l %%a in (%the_string% ; 1 ; %the_string%) do set "cl_string=%%~a"
if %the_string:~0,1% neq 0 if "%cl_string%" equ "0" (
echo does not start with number
) else (
echo starts with number
)
endlocal
Another approach is with FINDSTR which eventually will be slower as it is an external for cmd.exe command.
#echo off
set "the_string=something"
echo %the_string%|findstr /b /r "[0-9]" >nul 2>&1 && (
echo starts with number
) || (
echo does not start with number
)
This will work in your situation:
echo %variable%|findstr "^[a-zA-Z]" >nul && echo it starts with an alpha character
Using findstr with regexp :
#echo off
set "$string=2toto"
echo %$string:~0,1%|findstr /i "^-*0*x*[0-9][0-9]*$">nul && echo is NUM || echo Is not NUM
in place of echo is NUM or echo is not NUM you can use a goto to redirect your script the way you want it.
#echo off
set "$string=2toto"
echo %$string:~0,1%|findstr /i "^-*0*x*[0-9][0-9]*$">nul && goto:isnum || goto:isnotnum
:isnum
echo is NUM
exit/b
:isnotnum
echo is not NUM
You have to set the string as a variable; in this way you are able to extract substrings from a main string. Here is an example:
#echo off
set EXAMPLESTRING=12345abcde
set FIRSTCHARACTERSTRING=%EXAMPLESTRING:~0,1%
The result of this short script should be 1 in this case.
Then, you can set a series of conditions to verify whether the first character is a number or not:
if %FIRSTCHARACTERSTRING%==0 goto NUMBER
if %FIRSTCHARACTERSTRING%==1 goto NUMBER
if %FIRSTCHARACTERSTRING%==2 goto NUMBER
if %FIRSTCHARACTERSTRING%==3 goto NUMBER
if %FIRSTCHARACTERSTRING%==4 goto NUMBER
if %FIRSTCHARACTERSTRING%==5 goto NUMBER
if %FIRSTCHARACTERSTRING%==6 goto NUMBER
if %FIRSTCHARACTERSTRING%==7 goto NUMBER
if %FIRSTCHARACTERSTRING%==8 goto NUMBER
if %FIRSTCHARACTERSTRING%==9 goto NUMBER
goto LETTER
:NUMBER
echo The first character is a number!
goto EOF
:LETTER
echo The first character is a letter!
goto EOF
Maybe this is not the most efficient solution but it works fine and it is easier to understand.
In batch, how would I remove all non alphanumeric (a-z,A-Z,0-9,_) characters from a variable?
I'm pretty sure I need to use findstr and a regex.
The solutionof MC ND works, but it's really slow (Needs ~1second for the small test sample).
This is caused by the echo "!_buf!"|findstr ... construct, as for each character the pipe creates two instances of cmd.exe and starts findstr.
But this can be solved also with pure batch.
Each character is tested if it is in the map variable
:test
set "_input=Th""i\s&& is not good _maybe_???"
set "_output="
set "map=abcdefghijklmnopqrstuvwxyz 1234567890"
:loop
if not defined _input goto endLoop
for /F "delims=*~ eol=*" %%C in ("!_input:~0,1!") do (
if "!map:%%C=!" NEQ "!map!" set "_output=!_output!%%C"
)
set "_input=!_input:~1!"
goto loop
:endLoop
echo(!_output!
And it could be speed up when the goto loop is removed.
Then you need to calculate the stringLength first and iterate then with a FOR/L loop over each character.
This solution is ~6 times faster than the above method and ~40 times faster than the solution of MC ND
set "_input=Th""i\s&& is not good _maybe_!~*???"
set "_output="
set "map=abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ 1234567890"
%$strLen% len _input
for /L %%n in (0 1 %len%) DO (
for /F "delims=*~ eol=*" %%C in ("!_input:~%%n,1!") do (
if "!map:%%C=!" NEQ "!map!" set "_output=!_output!%%C"
)
)
exit /b
The macro $strlen can be defined with
set LF=^
::Above 2 blank lines are required - do not remove
#set ^"\n=^^^%LF%%LF%^%LF%%LF%^^":::: StrLen pResult pString
set $strLen=for /L %%n in (1 1 2) do if %%n==2 (%\n%
for /F "tokens=1,2 delims=, " %%1 in ("!argv!") do (%\n%
set "str=A!%%~2!"%\n%
set "len=0"%\n%
for /l %%A in (12,-1,0) do (%\n%
set /a "len|=1<<%%A"%\n%
for %%B in (!len!) do if "!str:~%%B,1!"=="" set /a "len&=~1<<%%A"%\n%
)%\n%
for %%v in (!len!) do endlocal^&if "%%~b" neq "" (set "%%~1=%%v") else echo %%v%\n%
) %\n%
) ELSE setlocal enableDelayedExpansion ^& set argv=,
EDITED - #jeb is right. This works but is really, really slow.
#echo off
setlocal enableextensions enabledelayedexpansion
set "_input=Th""i\s&& is not good _maybe_???"
set "_output="
:loop
if not defined _input goto endLoop
set "_buf=!_input:~0,1!"
set "_input=!_input:~1!"
echo "!_buf!"|findstr /i /r /c:"[a-z 0-9_]" > nul && set "_output=!_output!!_buf!"
goto loop
:endLoop
echo !_output!
endlocal
So, back to the drawing board. How to make it faster? lets try to do as less operations as we can and use as much long substring as we can. So, do it in two steps
1.- Remove all bad characters that can generate problems. To do it we will use the hability of for command to identify these chars as delimiters , and then join the rest of the sections of god characters of string
2.- Remove the rest of the bad characters, locating them in string using the valids charactes as delimiters to find substrings of bad characters, replacing then in string
So, we end with (sintax adapted to what has been answered here)
#echo off
setlocal enableextensions enabledelayedexpansion
rem Test empty string
call :doClean "" output
echo "%output%"
rem Test mixed strings
call :doClean "~~asd123#()%%%^"^!^"~~~^"""":^!!!!=asd^>^<bm_1" output
echo %output%
call :doClean "Thi\s&& is ;;;;not ^^good _maybe_!~*???" output
echo %output%
rem Test clean string
call :doClean "This is already clean" output
echo %output%
rem Test all bad string
call :doClean "*******//////\\\\\\\()()()()" output
echo "%output%"
rem Test long string
set "zz=Thi\s&& is not ^^good _maybe_!~*??? "
set "zz=TEST: %zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%%zz%"
call :doClean "%zz% TEST" output
echo %output%
rem Time long string
echo %time%
for /l %%# in (1 1 100) do call :doClean "%zz%" output
echo %time%
exit /b
rem ---------------------------------------------------------------------------
:doClean input output
setlocal enableextensions enabledelayedexpansion
set "map=abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ1234567890 "
set "input=%~1"
set "output="
rem Step 1 - Remove critical delimiters
(
:purgeCritical
for /L %%z in (1 1 10) do (
for /f tokens^=1^-9^,^*^ delims^=^=^"^"^~^;^,^&^*^%%^:^!^(^)^<^>^^ %%a in ("!input!") do (
set "output=!output!%%a%%b%%c%%d%%e%%f%%g%%h%%i"
set "input=%%j"
)
if not defined input goto outPurgeCritical
)
goto purgeCritical
)
:outPurgeCritical
rem Step 2 - remove any remaining special character
(
:purgeNormal
for /L %%z in (1 1 10) do (
set "pending="
for /f "tokens=1,* delims=%map%" %%a in ("!output!") do (
set "output=!output:%%a=!"
set "pending=%%b"
)
if not defined pending goto outPurgeNormal
)
goto purgeNormal
)
:outPurgeNormal
endlocal & set "%~2=%output%"
goto :EOF
Maybe not the fastest, but at least a "decent" solution
#echo eof
call :purge "~~asd123#()%%%^"^!^"~~~^:^=asd^>^<bm_1" var
echo (%var%)
goto :eof
:purge StrVar [RtnVar]
setlocal disableDelayedExpansion
set "str1=%~1"
setlocal enableDelayedExpansion
for %%a in ( - ! # # $ % ^^ ^& + \ / ^< ^> . ' [ ] { } ` ^| ^" ) do (
set "str1=!str1:%%a=!"
)
rem dealing with some delimiters
set "str1=!str1:(=!"
set "str1=!str1:)=!"
set "str1=!str1:;=!"
set "str1=!str1:,=!"
set "str1=!str1:^^=!"
set "str1=!str1:^~=!"
set "temp_str="
for %%e in (%str1%) do (
set "temp_str=!temp_str!%%e"
)
endlocal & set "str1=%temp_str%"
setlocal disableDelayedExpansion
set "str1=%str1:!=%"
set "str1=%str1::=%"
set "str1=%str1:^^~=%"
for /f "tokens=* delims=~" %%w in ("%str1%") do set "str1=%%w"
endlocal & set "str1=%str1%"
endlocal & if "%~2" neq "" (set %~2=%str1%) else echo %str1%
goto :eof
Still cannot deal with ~ and = but working on it
EDIT: = now will be cleared
EDIT: ~ now will be cleared
Okay so here is what I have.
#echo off
setLocal EnableDelayedExpansion
:begin
set /a M=0
set /a number=0
set /p Input=You:
echo %Input% >> UIS
for /F "tokens=1 delims= " %%i in ("%Input%") do (
set /a M+=1
set i!M!=%%i
)
del UIS 1>nul 2>nul
:loop
set /a number+=1
set invar=!i%number%!
echo %invar%
pause > nul
goto loop
Say, for example, the Input string was "Lol this is my input string"
I want the for loop to set i!M! where M = 1 to "Lol", where M = 2 i!M! is "this" and where M = 3 i!M! is "is" and so on. Now, of course, this can't go on forever, so even if I have to stop when M = 25 or something, and say the string was only 23 words long. Then when M = 24 and 25 then i!M! is simply null or undefined.
Any help is appreciated, thank you.
for /f reads line by line, not word by word.
Here's an answer proposed at How to split a string in a Windows batch file? and modified for your situation:
#echo off
setlocal ENABLEDELAYEDEXPANSION
REM Set a string with an arbitrary number of substrings separated by semi colons
set teststring=Lol this is my input string
set M=0
REM Do something with each substring
:stringLOOP
REM Stop when the string is empty
if "!teststring!" EQU "" goto displayloop
for /f "delims= " %%a in ("!teststring!") do set substring=%%a
set /a M+=1
set i!M!=!substring!
REM Now strip off the leading substring
:striploop
set stripchar=!teststring:~0,1!
set teststring=!teststring:~1!
if "!teststring!" EQU "" goto stringloop
if "!stripchar!" NEQ " " goto striploop
goto stringloop
:displayloop
set /a number+=1
set invar=!i%number%!
echo %invar%
pause > nul
goto displayloop
endlocal
for /F command divide a line in a definite number of tokens that must be processed at once via different replaceable parameters (%%i, %%j, etc). Plain for command divide a line in an undefined number of words (separated by space, comma, semicolon or equal-sign) that are processed one by one in an iterative loop. This way, you just need to change this for:
for /F "tokens=1 delims= " %%i in ("%Input%") do (
by this one:
for %%i in (%Input%) do (
PS - I suggest you to write the array in the standard form, enclosing the subscript in square brackets; it is clearer this way:
set i[!M!]=%%i
or
set invar=!i[%number%]!