if-else code for total price won't compile - c

Question

what is wrong with this im to make c code for total price with one of three ram options.et ramchoices=1or2or3 /this is where I know my problem lies but don't know how to fix it. the compiler needs a one to one relationship. how do I break this up and still show that ramchoice depends on what I pick and those choices affect price./
int main(void) {
/*declare variables*/
float baseprice;
float total;
float ramchoice;
baseprice=1029.48;
/*ramchoice can be 1 or 2 or 3*/
ramchoice=1||ramchoice=2||ramchoice=3;
total=baseprice+ramchoice;
/*initiate variable*/
scanf("%f",&ramchoice);
if("%f" (ramchoice==1))
{
total=baseprice+179.99;
}
else if("%f" ramchoice==2)
{
total=baseprice+94.99;
}
else if("%f" ramchoice==3)
{
total=baseprice+69.99;
}
printf("total is %f",total);
return 0;
}

Answer 1

There are several lines that are unlike any C code I've ever seen before.
Are you completely making up your own syntax and meaning?
Have you read any instructions/tutorials on C?
ramchoice=1||ramchoice=2||ramchoice=3;
Whatever you think this line does, it sets variable ramchoice to have value 1, then it stops.
if("%f" (ramchoice==1))
if does NOT take a string like "%f". if expects a boolean expression.
You're close to a boolean with ramchoice==1, but the "%f" at the start is so very wrong.
Seriously, you cannot make up rules to a language and pray that it works.
Here is my re-write that pretty much fixes your issues:
int main(void)
{
/*declare variables*/
float baseprice = 1029.48;
float total;
int ramchoice;
printf("Please enter a ram selection: 1, 2, or 3\n");
scanf("%d",&ramchoice);
switch(ramchoice)
{
case 1: total=baseprice+179.99; break;
case 2: total=baseprice+94.99; break;
case 3: total=baseprice+69.99; break;
default: printf("That was not a valid choice\n");
}
printf("total is %f",total);
return 0;
}

Answer 2

There's somethings in your code that make no sence (are not correct in C):
ramchoice=1||ramchoice=2||ramchoice=3; total=baseprice+ramchoice;
"%f" (ramchoice==1)
The first I don't understand why you are using it.
The second one gives me the idea that your not understanding how scanf works.
Also, you are declaring ramchoice as a float, but you are comparing it to another value (1, 2 or 3). Due to the representation of float values, this may not work. I mean, if you have float x = 1; and then do x == 1, it may return false. To fix this you can just change it to an int (in this case, in others you can use an error margin).
Here's a fix of your code:
int main(void) {
/*declare variables*/
float baseprice;
float total;
int ramchoice;
baseprice=1029.48;
/*initiate variable*/
scanf("%i",&ramchoice);
if(ramchoice==1)
{
total=baseprice+179.99;
}
else if(ramchoice==2)
{
total=baseprice+94.99;
}
else if(ramchoice==3)
{
total=baseprice+69.99;
}
printf("total is %f",total);
return 0;
}

Answer 3

Get rid of the "%f" in the if statements
Comment those 2 lines:
ramchoice=1||ramchoice=2||ramchoice=3;
total=baseprice+ramchoice;
and code should compile.