I want the results of my query to be the top 3 newest, distinct Campaign Names for each Campaign Type.
My query at the moment is:
DECLARE #currentRecord varchar(160);
SET #currentRecord = '316827D2-B522-E811-816A-0050569FE3BD';
SELECT DISTINCT
rs.CampaignName,
rs.CampaignType,
rs.receivedon,
rs.Rank
FROM
(SELECT
fs_retentioncontact,
receivedon,
regardingobjectidname AS CampaignName,
fs_campaignresponsetypename AS CampaignType,
RANK() OVER (PARTITION BY fs_campaignresponsetypename, regardingobjectidname
ORDER BY receivedon DESC) AS Rank
FROM
dbo.FilteredCampaignResponse) rs
INNER JOIN
dbo.FilteredContact ON rs.fs_retentioncontact = dbo.FilteredContact.contactid
WHERE
(dbo.FilteredContact.parentcustomerid IN (#currentRecord))
AND Rank <= 3
ORDER BY
CampaignType, receivedon DESC;
There may be multiple results for each campaign name as well as campaign response because they are linked to individual contacts but I only want to see the 3 latest unique campaigns for each campaign type.
My query is not partitioning by each individual campaign response type (there are 6 different ones) as I was expecting. If I remove the regardingobjectidname from the PARTITION BY I only get a single row in the results when I should be getting 18 rows. This particular company has over 700 campaign responses across the 6 campaign types.
My query is returning 102 rows so it seems to be removing duplicates on campaign name which is part of what I need but not the whole story.
I have read quite a few posts regarding rank() on here e.g.
how-to-use-rank-in-sql-server
[ using-sql-rank-for-overall-rank-and-rank-within-a-group]2
but I am not able to work out what I am doing wrong from their examples. Could it be the positioning of the 'receivedon' in the ORDER BY? or something else?
I have finally worked out from reading a post on another site how to get the top 3 of each group. I shall post my answer in case it helps anyone else.
I had to use ROW_NUMBER() OVER (PARTITION BY instead of RANK() OVER (PARTITION BY and I also moved the INNER JOIN and WHERE clause (to filter for the correct company) from the outer query to the inner query.
DECLARE #currentRecord varchar(160)
SET #currentRecord='316827D2-B522-E811-816A-0050569FE3BD'
SELECT distinct rs.CampaignName
,rs.CampaignType
, rs.receivedon
,RowNum
FROM(
SELECT fs_retentioncontact
, receivedon
, regardingobjectidname AS CampaignName
,fs_campaignresponsetypename as CampaignType
,ROW_NUMBER() OVER (PARTITION BY fs_campaignresponsetypename ORDER BY fs_campaignresponsetypename, receivedon DESC) AS RowNum
FROM FilteredCampaignResponse
INNER JOIN dbo.FilteredContact ON fs_retentioncontact = dbo.FilteredContact.contactid
WHERE(dbo.FilteredContact.parentcustomerid IN (#currentRecord)))rs
WHERE RowNum <=3
ORDER BY CampaignType,receivedon DESC;
I'm new to SQL in general and I need to delete all duplicates in a given database.
For the moment, I use this DB to experiment some things.
The table currently looks like this :
I know I can find all duplicates using this query :
SELECT COUNT(*) AS NBR_DOUBLES, Name, Owner
FROM dbo.animals
GROUP BY Name, Owner
HAVING COUNT(*) > 1
but I have a lot of trouble finding an adapted and updated solution to not only find all the duplicates, but also delete them all, only leaving one of each.
Thanks a lot for taking some of your time to help me.
;WITH numbered AS (
SELECT ROW_NUMBER() OVER(PARTITION BY Name, Owner ORDER BY Name, Owner) AS _dupe_num
FROM dbo.Animals
)
DELETE FROM numbered WHERE _dupe_num > 1;
This will delete all but one of each occurance with the same Name & Owner, if you need it to be more specific you should extend the PARTITION BY clause. If you want it to take in account the entire record you should add all your fields.
The record left behind is currently random, since it seems you do not have any field to have any sort of ordering on.
What you want to do is use a projection that numbers each record within a given duplicate set. You can do that with a Windowing Function, like this:
SELECT Name, Owner
,Row_Number() OVER ( PARTITION BY Name, Owner ORDER BY Name, Owner, Birth) AS RowNum
FROM dbo.animals
ORDER BY Name, Owner
This should give you results like this:
Name Owner RowNum
Ecstasy Sacha 1
Ecstasy Sacha 2
Ecstasy Sacha 3
Gremlin Max 1
Gremlin Max 2
Gremlin Max 3
Outch Max 1
Outch Max 2
Outch Max 3
Now you want to convert this to a DELETE statement that has a WHERE clause targeting rows with RowNum > 1. The way to use a windowing function with a DELETE is to first include the windowing function as part of a common table expression (CTE), like this:
WITH dupes AS
(
SELECT Name, Owner,
Row_Number() OVER ( PARTITION BY Name, Owner ORDER BY Name, Owner, Birth) AS RowNum
FROM dbo.animals
)
DELETE FROM dupes WHERE RowNum > 1;
This will delete later duplicates, but leave row #1 for each group intact. The only trick now is to make sure row #1 is the correct row, since not all of your duplicates have the same values for the Birth or Death columns. This is the reason I included the Birth column in the windowing function, while other answers (so far) have not. You need to decide if you want to keep the oldest animal or the youngest, and optionally change the Birth order in the OVER clause to match your needs.
Use CTE. I will show you a sample :
Create table #Table1(Field1 varchar(100));
Insert into #Table1 values
('a'),('b'),('f'),('g'),('a'),('b');
Select * from #Table1;
WITH CTE AS(
SELECT Field1,
RN = ROW_NUMBER()OVER(PARTITION BY Field1 ORDER BY Field1)
FROM #Table1
)
--SELECT * FROM CTE WHERE RN > 1
DELETE FROM CTE WHERE RN > 1
What I am doing is, numbering the rows. If there are duplicates based on PARTITION BY columns, it will be numbered sequentially, else 1.
Then delete those records whose count is greater than 1.
I won't spoon feed you solution hence you will have to play with PARTITION BY to reach your output
output :
Select * from #Table1;
Field1
---------
a
b
f
g
a
b
/*with cte as (...) SELECT * FROM CTE;*/
Field1 RN
------- -----
a 1
a 2
b 1
b 2
f 1
g 1
if NBR_DOUBLES had an ID field, I believe you could use this;
DELETE FROM NBR_DOUBLES WHERE ID IN
(
SELECT MAX(ID)
FROM dbo.animals
GROUP BY Name, Owner
HAVING COUNT(*) > 1
)
I have some sample data as follows
Name Value Timestamp
a 23 2016/12/23 11:23
a 43 2016/12/23 12:55
b 12 2016/12/23 12:55
I want to select the latest value for a and b. When I used Last_Value, I used the following query
Select Name, Last_Value(Value) over (partition by Name order by timestamp) from table
This returned 2 rows for a, but I wanted it grouped so that I get only the last entered value for each name. So I had to use sub queries.
select x.Name,x.Value from (Select Name, Last_Value(Value) over (partition by Name order by timestamp) ) as x group by x.Name,x.Value
This again returns 2 records for a...I just wanted to do a group by and orderby and instaed of selelcting the max() wanted to select the top record.
Can anybody tell me how to solve this problem?
One method doesn't use window functions:
select t.*
from table t
where t.timestamp = (select max(t2.timestamp) from table t2 where t2.name = t.name);
Otherwise, the subquery method is fine, although I would often use row_number() and conditional aggregation rather than last_value() (or first_value() with a descending order by).
Unfortunately, SQL Server does not support first_value() or last_value() as an aggregation function, only as a window function.
I have a table with data about cities that includes their name, population and other fields irrelevant to my question.
ID Name Population
1 A 45667
2 B 123456
3 C 3005
4 D 13769
To find the max population is basic, but I need a resulting table that has the max population in one column, and the corresponding city's name in another column
Population Name
123456 B
I've looked through similar questions, but for some reason the answers look over-complicated. Is there a way to write the query in 1 or 2 lines?
There are several ways that this can be done:
A filter in the WHERE clause:
select id, name, population
from yourtable
where population in (select max(population)
from yourtable)
Or a subquery:
select id, name, population
from yourtable t1
inner join
(
select max(population) MaxPop
from yourtable
) t2
on t1.population = t2.maxpop;
Or you can use TOP WITH TIES. If there can be no ties, then you can remove the with ties. This will include any rows that have the same population value:
select top 1 with ties id, name, population
from yourtable
order by population desc
Since you are using SQL Server you can also use ranking functions to get the result:
select id, name, population
from
(
select id, name, population,
row_number() over(order by population desc) rn
from yourtable
) src
where rn = 1
See SQL Fiddle with Demo of all.
As a side note on the ranking function, you might want to use dense_rank() instead of row_number(). Then in the event you have more than one city with the same population you will get both city names. (See Demo)
I'm working with SQL Server 2005.
My query is:
SELECT (
SELECT COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
And the error:
The ORDER BY clause is invalid in views, inline functions, derived
tables, subqueries, and common table expressions, unless TOP or FOR
XML is also specified.
How can I use ORDER BY in a sub query?
This is the error you get (emphasis mine):
The ORDER BY clause is invalid in
views, inline functions, derived
tables, subqueries, and common table
expressions, unless TOP or FOR XML is
also specified.
So, how can you avoid the error? By specifying TOP, would be one possibility, I guess.
SELECT (
SELECT TOP 100 PERCENT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
If you're working with SQL Server 2012 or later, this is now easy to fix. Add an offset 0 rows:
SELECT (
SELECT
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id OFFSET 0 ROWS
) as dorduncuay
Besides the fact that order by doesn't seem to make sense in your query....
To use order by in a sub select you will need to use TOP 2147483647.
SELECT (
SELECT TOP 2147483647
COUNT(1) FROM Seanslar WHERE MONTH(tarihi) = 4
GROUP BY refKlinik_id
ORDER BY refKlinik_id
) as dorduncuay
My understanding is that "TOP 100 PERCENT" doesn't gurantee ordering anymore starting with SQL 2005:
In SQL Server 2005, the ORDER BY
clause in a view definition is used
only to determine the rows that are
returned by the TOP clause. The ORDER
BY clause does not guarantee ordered
results when the view is queried,
unless ORDER BY is also specified in
the query itself.
See SQL Server 2005 breaking changes
Hope this helps,
Patrick
If building a temp table, move the ORDER BY clause from inside the temp table code block to the outside.
Not allowed:
SELECT * FROM (
SELECT A FROM Y
ORDER BY Y.A
) X;
Allowed:
SELECT * FROM (
SELECT A FROM Y
) X
ORDER BY X.A;
You don't need order by in your sub query. Move it out into the main query, and include the column you want to order by in the subquery.
however, your query is just returning a count, so I don't see the point of the order by.
A subquery (nested view) as you have it returns a dataset that you can then order in your calling query. Ordering the subquery itself will make no (reliable) difference to the order of the results in your calling query.
As for your SQL itself:
a) I seen no reason for an order by as you are returning a single value.
b) I see no reason for the sub query anyway as you are only returning a single value.
I'm guessing there is a lot more information here that you might want to tell us in order to fix the problem you have.
Add the Top command to your sub query...
SELECT
(
SELECT TOP 100 PERCENT
COUNT(1)
FROM
Seanslar
WHERE
MONTH(tarihi) = 4
GROUP BY
refKlinik_id
ORDER BY
refKlinik_id
) as dorduncuay
:)
maybe this trick will help somebody
SELECT
[id],
[code],
[created_at]
FROM
( SELECT
[id],
[code],
[created_at],
(ROW_NUMBER() OVER (
ORDER BY
created_at DESC)) AS Row
FROM
[Code_tbl]
WHERE
[created_at] BETWEEN '2009-11-17 00:00:01' AND '2010-11-17 23:59:59'
) Rows
WHERE
Row BETWEEN 10 AND 20;
here inner subquery ordered by field created_at (could be any from your table)
In this example ordering adds no information - the COUNT of a set is the same whatever order it is in!
If you were selecting something that did depend on order, you would need to do one of the things the error message tells you - use TOP or FOR XML
Try moving the order by clause outside sub select and add the order by field in sub select
SELECT * FROM
(SELECT COUNT(1) ,refKlinik_id FROM Seanslar WHERE MONTH(tarihi) = 4 GROUP BY refKlinik_id)
as dorduncuay
ORDER BY refKlinik_id
For me this solution works fine as well:
SELECT tbl.a, tbl.b
FROM (SELECT TOP (select count(1) FROM yourtable) a,b FROM yourtable order by a) tbl
Good day
for some guys the order by in the sub-query is questionable.
the order by in sub-query is a must to use if you need to delete some records based on some sorting.
like
delete from someTable Where ID in (select top(1) from sometable where condition order by insertionstamp desc)
so that you can delete the last insertion form table.
there are three way to do this deletion actually.
however, the order by in the sub-query can be used in many cases.
for the deletion methods that uses order by in sub-query review below link
http://web.archive.org/web/20100212155407/http://blogs.msdn.com/sqlcat/archive/2009/05/21/fast-ordered-delete.aspx
i hope it helps. thanks you all
For a simple count like the OP is showing, the Order by isn't strictly needed. If they are using the result of the subquery, it may be. I am working on a similiar issue and got the same error in the following query:
-- I want the rows from the cost table with an updateddate equal to the max updateddate:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype -- *** This causes an error***
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- *** To accomplish this, there are a few options:
-- Add an extraneous TOP clause, This seems like a bit of a hack:
SELECT * FROM #Costs Cost
INNER JOIN
(
SELECT TOP 99.999999 PERCENT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
) CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, Costs.costtype
-- **** Create a temp table to order the maxCost
SELECT Entityname, costtype, MAX(updatedtime) MaxUpdatedTime
INTO #MaxCost
FROM #HoldCosts cost
GROUP BY Entityname, costtype
ORDER BY Entityname, costtype
SELECT * FROM #Costs Cost
INNER JOIN #MaxCost CostsMax
ON Costs.Entityname = CostsMax.entityname
AND Costs.Costtype = CostsMax.Costtype
AND Costs.UpdatedTime = CostsMax.MaxUpdatedtime
ORDER BY Costs.Entityname, costs.costtype
Other possible workarounds could be CTE's or table variables. But each situation requires you to determine what works best for you. I tend to look first towards a temp table. To me, it is clear and straightforward. YMMV.
On possible needs to order a subquery is when you have a UNION :
You generate a call book of all teachers and students.
SELECT name, phone FROM teachers
UNION
SELECT name, phone FROM students
You want to display it with all teachers first, followed by all students, both ordered by. So you cant apply a global order by.
One solution is to include a key to force a first order by, and then order the names :
SELECT name, phone, 1 AS orderkey FROM teachers
UNION
SELECT name, phone, 2 AS orderkey FROM students
ORDER BY orderkey, name
I think its way more clear than fake offsetting subquery result.
I Use This Code To Get Top Second Salary
I am Also Get Error Like
The ORDER BY clause is invalid in views, inline functions, derived tables, subqueries, and common table expressions, unless TOP or FOR XML is also specified.
TOP 100 I Used To Avoid The Error
select * from (
select tbl.Coloumn1 ,CONVERT(varchar, ROW_NUMBER() OVER (ORDER BY (SELECT 1))) AS Rowno from (
select top 100 * from Table1
order by Coloumn1 desc) as tbl) as tbl where tbl.Rowno=2