In my binary search tree I want to create a function that can get all words starting with a prefix and store all words in an array called results
this is my tree
struct BinarySearchTree_t
{
char *mot,*def;
struct BinarySearchTree_t *left;
struct BinarySearchTree_t *right;
};
typedef struct BinarySearchTree_t BinarySearchTree;
my function :
size_t findWordsByPrefix(BinarySearchTree* tree, char* prefix, char*** results)
{
BinarySearchTree *tmp;
tmp=tree;
static int size=0;
if (!tmp)
return 0;
else if (strncmp(tmp->mot,prefix,strlen(prefix))==0)
{
(*results)= realloc(*results,(1+size)*sizeof(*(*results)));
(*(*results+size))= malloc(strlen(tmp->mot)*sizeof(char));
strcpy((*results)[size],tmp->mot);
size++;
return (1 + findWordsByPrefix(tmp->left,prefix, &results) + findWordsByPrefix(tmp->right,prefix, &results));
}
else
return (strncmp(tmp->mot,prefix,strlen(prefix))<0)?findWordsByPrefix(tmp->right,prefix, &results):findWordsByPrefix(tmp->left,prefix, &results) ;
}
This function should return a number of words starting with the given prefix.
my problem is that the program crash when it is run , and I don't how to resize my array results
so every time I found a word I should increase the size of the results array .
and I would know how exacly manipulate the pointer of pointer of pointer given in arg of this function (char ***results) : what exactly means?
If I simply compile your code, I get severe compiler warnings including:
1>binarysearchtree.c(98) : warning C4047: 'function' : 'char ***' differs in levels of indirection from 'char ****'
1>binarysearchtree.c(98) : warning C4024: 'findWordsByPrefix' : different types for formal and actual parameter 3
This alone will cause a crash -- you are calling your own function recursively with the wrong arguments.
Next, I believe you need to allocate one more than the length of the string, to hold a copy of a string:
malloc((strlen(tmp->mot) + 1 )*sizeof(char))
Next, you're passing around an array of strings of variable size -- and storing the size in a static variable. It's impossible to know if this will work, so don't do it.
Instead, if you want to use a dynamic array of strings, I suggest extracting out a struct to hold them, like so:
struct ResultTable_t
{
int size;
char **results;
};
typedef struct ResultTable_t ResultTable;
void InitializeResults(ResultTable *p_table)
{
p_table->size = 0;
p_table->results = NULL;
}
void AddResult(ResultTable *p_table, char *result)
{
if (result == NULL)
return;
p_table->size++;
p_table->results = realloc(p_table->results, p_table->size * sizeof(*p_table->results));
p_table->results[p_table->size-1] = malloc((strlen(result) + 1) * sizeof(**p_table->results));
strcpy(p_table->results[p_table->size-1], result);
}
void FreeResults(ResultTable *p_table)
{
if (p_table->results != NULL)
{
int i;
for (i = 0; i < p_table->size; i++)
{
free(p_table->results[i]);
}
free(p_table->results);
}
p_table->size = 0;
p_table->results = NULL;
}
(As an improvement, you might consider using geometric growth instead of linear growth for your table of results.)
Then your function becomes:
size_t findWordsByPrefix(BinarySearchTree* tree, char* prefix, ResultTable *p_table)
{
if (!tree)
return 0;
else if (strncmp(tree->mot,prefix,strlen(prefix))==0)
{
AddResult(p_table, tree->mot);
return (1 + findWordsByPrefix(tree->left,prefix, p_table) + findWordsByPrefix(tree->right,prefix, p_table));
}
else if (strncmp(tree->mot,prefix,strlen(prefix))<0)
{
return findWordsByPrefix(tree->right,prefix, p_table);
}
else
{
return findWordsByPrefix(tree->left,prefix, p_table);
}
}
And you would use it like:
ResultTable results;
InitializeResults(&results);
// Get some prefix to search for.
char prefix = GetSomePrefix();
int size = findWordsByPrefix(tree, prefix, &results);
// Do something with the results
// Free all memory of the results
FreeResults(&results);
Update
If the ResultTable is distasteful for some reason, you can pass the dynamic array and array sizes in directly:
void AddResult(char ***p_results, int *p_size, char *word)
{
if (word == NULL)
return;
(*p_size)++;
(*p_results) = realloc(*p_results, ((*p_size)+1) * sizeof(**p_results));
(*p_results)[(*p_size)-1] = malloc((strlen(word) + 1) * sizeof(***p_results));
strcpy((*p_results)[(*p_size)-1], word);
}
void FreeResults(char ***p_results, int *p_size)
{
int i;
if (p_results == NULL || *p_results == NULL)
return;
for (i = 0; i < (*p_size); i++)
{
free ((*p_results)[i]);
}
free (*p_results);
*p_results = NULL;
*p_size = 0;
}
size_t findWordsByPrefix(BinarySearchTree* tree, char* prefix, char ***p_results, int *p_size)
{
if (!tree)
return 0;
else if (strncmp(tree->mot,prefix,strlen(prefix))==0)
{
AddResult(p_results, p_size, tree->mot);
return (1 + findWordsByPrefix(tree->left,prefix, p_results, p_size) + findWordsByPrefix(tree->right,prefix, p_results, p_size));
}
else if (strncmp(tree->mot,prefix,strlen(prefix))<0)
{
return findWordsByPrefix(tree->right,prefix, p_results, p_size);
}
else
{
return findWordsByPrefix(tree->left,prefix, p_results, p_size);
}
}
and use like:
char **results = NULL;
int tablesize = 0;
// Get some prefix to search for.
char prefix = GetSomePrefix();
int size = findWordsByPrefix(tree, prefix, &results, &tablesize);
// Do something with the results
// Free all memory of the results
FreeResults(&results, &tablesize);
Related
I'm making an hashing table data structure and having segmentation fault error on my inicialization function. Here the code:
void allocTableSlots(alu **table, int index){
if(index == MAX)
return;
else{
table[index] = calloc(1, sizeof(alu));
table[index]->registration = -1;
table[index]->next = -1;
allocTableSlots(table, index+1);
}
}
void initializateHashTable(hash *hashing){
hashing = calloc(1, sizeof(hash));
allocTableSlots(hashing->table, 0);
hashing->collisionArea = 690;
}
My structs are these:
#define MAX 997
typedef struct alu{
int registration;
char name[80];
char email[80];
int next;
} alu;
typedef struct reg{
alu *table[MAX];
int collisionArea;
}hash;
The error comes in:
if(index == MAX)
on allocTableSlots() function
If I change MAX, for MAX-1, or any other number, like 500 the error still comes after position 499, so its not look like that I trying to access an invalid position of my array table
I already tried an iterative version (in case that my recursion has some error) but still the same
As suggested in the comments, you most likely should just return the pointer to the allocated block from the init function. Furthermore, if the maximum bucket size is known, as is in your code with MAX, the code simplifies to:
...
typedef struct reg {
alu table[MAX];
int collisionArea;
} hash;
hash *initializateHashTable(void) {
hash *t = calloc(1, sizeof *t);
if (!t) return NULL; // check calloc, just in case.
/* Whatever initialization you want to perform. As per your code,
setting registration and next members to -1 */
for (int i = 0; i < MAX; i++) {
t->table[i].registration = t->table[i].next = -1;
}
t->collisionArea = 690; // EDIT: Forgot the collisionArea
return t;
}
Hi I am attempting to implement a really simple hashmap in regular C with a string as key and a void pointer as value as I wish to use the map for multiple data types.
So far I have this
struct node{
void * value;
char * key;
};
unsigned long strhash(char *string)
{
unsigned long hash = 5381;
int c;
while ((c = *string++))
{
hash = ((hash << 5) + hash) + c;
}
return hash;
}
map_t *map_create(int maxSize){
map_t *map = malloc(sizeof(map_t));
map->curSize = 0;
map->maxSize = maxSize;
map->nodes = calloc(map->maxSize, sizeof(node_t *));
return map;
}
node_t *node_create(char *key, void *value){
node_t *node = malloc(sizeof(node_t));
node->key = key;
node->value = value;
return node;
}
void map_insert(map_t *map, char *key, void *value){
node_t *node = node_create(key, value);
int idx = strhash(key) % map->maxSize;
if(map->nodes[idx] == NULL){
map->nodes[idx] = node;
}else{
while(map->nodes[idx] != NULL){
idx++%map->maxSize;
}
map->nodes[idx] = node;
}
return;
}
void map_print(map_t *map){
for(int i = 0; i < map->maxSize; i++){
if(map->nodes[i] != NULL){
printf("index: %d\t value: %d\n",i, *(int*)map->nodes[i]->value);
}
}
return;
}
void map_destroy(map_t *map){
for(int i = 0; i < map->maxSize; i++){
if(map->nodes[i] != NULL){
free(map->nodes[i]);
}
}
free(map->nodes);
free(map);
return;
}
int main(){
map_t *map = map_create(32);
for(int i = 0; i < 30; i++){
map_insert(map, (char*)&i, &i);
}
map_print(map);
map_destroy(map);
return 0;
}
The problem is the output is not as I'd expect when the map gets printed all that is retrieved is the value "30" on all indexes which is the last number inserted into the map. If I change the value to type int the map works as expected, so is there must be something crucial I am missing in regards to pointers.
I am not the greatest at C so any light which could be shed on this would be most appreciated.
The problem is that you're using the same pointer every time you call map_insert(). It just stores the pointer, it doesn't copy the data. Each time through the loop you change the contents of that memory, so all the hash map elements point to that same value.
There are two ways you can fix it. One way is to always make a dynamically-allocated copy of the data before calling map_insert():
for (int i = 0; i < 30; i++) {
int *i_copy = malloc(sizeof *i_copy);
*i_copy = i;
map_insert(map, (char *)i_copy, (char *)i_copy);
}
The other option is to add the size of the value to the map_insert() and node_create() arguments. Then node_create call malloc() and memcpy() to copy the value to dynamic memory.
BTW, there's another problem. The key is supposed to be a null-terminated string (strhash() depends on this), but you're using &i, which is a pointer to an integer. Casting a pointer to an integer to char* doesn't return a string, it just returns a pointer to the same location with a different data type. I haven't fixed this above.
OP stores a reference to the same value, so of course all lookups yield the same value (which is not even a string, but whatever the storage representation of the value of the variable i happens to be).
I prefer chaining the hash map entries, and keeping a copy of the hash in the entry:
struct entry {
struct entry *next;
size_t hash;
void *data;
size_t data_size;
int data_type;
unsigned char name[];
};
typedef struct {
size_t size;
size_t used; /* Number of entries, total */
struct entry **slot; /* Array of entry pointers */
size_t (*hash)(const unsigned char *, size_t);
} hashmap;
int hashmap_new(hashmap *hmap, const size_t size,
size_t (*hash)(const unsigned char *, size_t))
{
if (!hmap)
return -1; /* No hashmap specified */
hmap->size = 0;
hmap->used = 0;
hmap->slot = NULL;
hmap->hash = NULL;
if (size < 1)
return -1; /* Invalid size */
if (!hash)
return -1; /* No hash function specified. */
hmap->slot = calloc(size, sizeof hmap->slot[0]);
if (!hmap->slot)
return -1; /* Not enough memory */
hmap->size = size;
hmap->hash = hash;
return 0;
}
void hashmap_free(hashmap *hmap)
{
if (hmap) {
size_t i = hmap->size;
while (i-->0) {
struct entry *next = hmap->slot[i];
struct entry *curr;
while (next) {
curr = next;
next = next->next;
free(curr->data);
/* Poison the entry, to help detect use-after-free bugs. */
curr->next = NULL;
curr->data = NULL;
curr->hash = 0;
curr->data_size = 0;
curr->data_type = 0;
curr->name[0] = '\0';
free(curr);
}
}
}
free(hmap->slot);
hmap->size = 0;
hmap->used = 0;
hmap->slot = NULL;
hmap->hash = NULL;
}
To insert a key-value pair, the function either uses the data specified as-is, in which case it's the caller's responsibility to ensure each key has their own unique data not overwritten later; or we copy the user data. In the above hashmap_free() function, you'll see free(curr->data);; it assumes we allocated memory dynamically, and copied the user data there. So:
int hashmap_add(hashmap *hmap, const unsigned char *name,
const void *data, const size_t data_size,
const int data_type)
{
const size_t namelen = (name) ? strlen(name) : 0;
struct entry *curr;
size_t i;
if (!hmap)
return -1; /* No hashmap specified. */
if (name_len < 1)
return -1; /* NULL or empty name. */
/* Allocate memory for the hashmap entry,
including enough room for the name, and end of string '\0'. */
curr = malloc(sizeof (struct entry) + namelen + 1;
if (!curr)
return -1; /* Out of memory. */
/* Copy data, if any. */
if (data_size > 0) {
curr->data = malloc(data_size);
if (!curr->data) {
free(curr);
return -1; /* Out of memory. */
}
memcpy(curr->data, data, data_size);
} else {
curr->data = NULL;
curr->data_size = 0;
}
curr->data_type = data_type;
/* Calculate the hash of the name. */
curr->hash = hmap->hash(name, namelen);
/* Copy name, including the trailing '\0'. */
memcpy(curr->name, name, namelen + 1);
/* Slot to prepend to. */
i = curr->hash % hmap->size;
curr->next = hmap->slot[i];
hmap->slot[i] = curr;
/* An additional node added. */
hmap->used++;
return 0;
}
The meaning of data_type is completely up to the user of the code.
Lookup can be made based on the hash and the data type:
/* Returns 0 if found. */
int hashmap_find(hashmap *hmap, const unsigned char *name,
const int data_type,
void **dataptr_to, size_t *size_to)
{
struct entry *curr;
size_t hash;
if (size_to)
*size_to = 0;
if (dataptr_to)
*dataptr_to = NULL;
if (!hmap)
return -1; /* No hashmap specified. */
if (!name || !*name)
return -1; /* NULL or empty name. */
hash = hmap->hash(name, strlen(name));
curr = hmap->slot[hash % hmap->size];
for (curr = hmap->slot[hash % hmap->size]; curr != NULL; curr = curr->next) {
if (curr->data_type == data_type && curr->hash == hash &&
!strcmp(curr->name, name)) {
/* Data type an name matches. Save size if requested. */
if (size_to)
*size_to = curr->data_size;
if (dataptr_to)
*dataptr_to = curr->data;
return 0; /* Found. */
}
}
return -1; /* Not found. */
}
The above lookup returns 0 if found, and nonzero if error or not found. (This way, even zero-size NULL data can be stored in the hash map.)
If the number of data types supported is small, say 32, then using an unsigned int with each bit (1U<<0 == 1, 1U<<1 == 2, 1U<<2 == 4, and so on) reserved for a specific type, you can do the lookup using a mask, allowing only the specified types. Similarly, the data_type can be a mask, describing which types the value can be interpreted as (almost always will have just one bit set).
This scheme also allows one to dynamically resize the hashmap, by allocating a new slot array of pointers, and moving each old entry to the new one. The keys don't need to be rehashed, because the original hash is stored in each entry. For lookup efficiency, the chains (hanging off each slot) should be as short as possible. A common "rule of thumb" is that hashmap->size should be between hashmap->used and 2 * hashmap->used.
When you call map_insert(map, (char*)&i, &i); the value inserted into hasmap is the pointer to i variable, i.e. its address in memory, and not the value of i.
So when you change i value inside the for loop there is the side-effect to all entries into the hashmap, and at the end of the loop you only see the last value assigned.
i have a task in class to the return an array of struck Symbol from huffman tree.
the function getSL get a huffman tree(only) and return struck of Symbol.
each spot in the array contain a char from the "leaf" of the tree and the
length of his code(how many cross section till the leaf).
my main problem was to find how i advance the cnt of the arry that it will not overright the arry.
thank you.
typedef struct HNode {
char chr;
struct HNode *left, *right;
} HNode;
typedef struct {
char chr;
int counter;
}Symbol;
this is what i did till now.
Symbol * getSL(HNode *root) {
if (root->left == NULL && root->right == NULL) {
Symbol* b = (Symbol*)malloc(100);
b->counter=0;
b->chr = root->chr;
return b;
}
Symbol* a = (Symbol*)malloc(100);
if (root->left != NULL) {
a= getSL(root->left);
a->counter++;
}
if (root->right != NULL) {
a= getSL(root->right);
a->counter++;
}
return a;
}
Apart from the malloc problem (see the comments already), you have a fundamental problem: You allocate a new struct, but then replace it with the one returned from the recursive call. So you lose the one created before (actually, memory leaking!).
Easiest variant would now be converting your Symbol to linked list nodes; then you simply could do:
Symbol* lastLeafFound; // probaly a function parameter!
if(!(root->left || root->right))
{
// leaf found:
Symbol* a = (Symbol*)malloc(sizeof(Symbol));
a->chr = root->chr;
a->counter = /* ... */;
a->next = NULL;
lastLeafFound->next = a;
// you might return a now as last leaf found, using it in the next recursive call
}
Sure, above code is incomplete, but should give you the idea...
If you cannot modify your struct, then you need to create an array and pass it on to every new recursive call (prefer not to use global variables instead):
void doGetSL
(
HNode* root,
Symbol** symbols, // your array to be used
unsigned int* count, // number of symbols contained so far
unsigned int* capacity // maximum possible symbols
)
Passing all data as pointers allows the function to modify them as needed and they are still available from outside...
Symbol* getSL(HNode* root)
{
if(!root)
return NULL;
unsigned int count = 0;
unsigned int capacity = 128;
// allocate a whole array:
Symbol* array = malloc(capacity*sizeof(Symbol));
if(array) // malloc could fail...
{
doGetSL(root, &array, &count, &capacity);
// as you cannot return the number of leaves together with
// the array itself, you will need a sentinel:
array[count].chr = 0;
// obvious enough, I'd say, alternatively you could
// set counter to 0 or -1 (or set both chr and counter)
}
return array;
}
doGetSL will now use above set up "infrastructure":
{
if(!(root->left || root->right))
{
if(*count == *capacity)
{
// no memory left -> we need a larger array!
// store in separate variables:
unsigned int c = *capacity * 2;
Symbol* s = realloc(symbols, c * sizeof(Symbol));
// now we can check, if reallocation was successful
// (on failure, s will be NULL!!!):
if(s)
{
// OK, we can use them...
*symbols = s; // <- need a pointer for (pointer to pointer)!
*capacity = c;
}
else
{
// re-allocation failed!
// -> need appropriate error handling!
}
}
(*symbols)[count].chr = root->chr;
(*symbols)[count].counter = /*...*/;
++*count;
}
else
{
if(root->left)
{
doGetSL(root->left, symbols, count, capacity);
}
if(root->right)
{
doGetSL(root->right, symbols, count, capacity);
}
}
}
One thing yet omitted: setting the counter. That would be quite easy: add another parameter to doGetSL indicating the current depth, which you increment right when entering doGetSL, you can then just assign this value when needed.
You can further improve above variant (especially readability), if you introduce a new struct:
struct SLData
{
Symbol* symbols, // your array to be used
unsigned int count, // number of symbols contained so far
unsigned int capacity // maximum possible symbols
};
and pass this one instead of the three pointers:
doGetSL(HNode*, struct SLData*, unsigned int depth);
struct SLData data =
{
.count = 0;
.capacity = 128;
.array = malloc(capacity*sizeof(Symbol));
};
if(data.array)
doGetSL(root, &data, 0); // again passed as pointer!
i have decleard a structure and allocate some memory too . using a function i update datas . i got error segmentation fault when i acssing data.
This is my code
In headerfile :
typedef struct
{
int member;
char *name;
}place;
void update(place **,int);
void display(place **,int);
in function
static memallocate(place **ptr,int viname,int index)
{
ptr[index]=(place *)malloc(sizeof(place));
ptr[index]->name=(char *)malloc(viname*sizeof(char *));
}
void update(place **ptr,int index)
{
---read string value "na" find the strlen as "pp"---
memallocate(ptr,pp,index);
ptr[index]->name=na;
}
void display(place **ptr,int index)
{
int i;
for(i=0;i<index;i++)
{
printf("%s\n",ptr[i]->name);
printf("%s\n",ptr[i]->country);
}
}
in main file :
void main()
{
int index=0;
place *pla[5]={NULL};
while(index<2)
{
update(&pla[index],index);
index++;
}
display(pla,index);
}
my problem is i got segmentation fault when acessing function display and can't print datas ptr[0]->name,ptr[0]->country,ptr[1]->name,ptr[1]->country ..why this happen ? any memory fault . I got printing when i use printf after each updation .
I see two mayor issues here.
1st
Here
static void memallocate(place **ptr,int viname,int index)
{
ptr[index]=(place *)malloc(sizeof(place));
ptr[index]->name=(char *)malloc(viname*sizeof(char *));
}
you allocate too much memory. It shall be
static void memallocate(place ** ptr, int viname, int index)
{
ptr[index] = malloc(sizeof(place));
ptr[index]->name = malloc(viname * sizeof(char));
}
or even better:
static int memallocate(place ** ptr, size_t viname, size_t index)
{
int result = 0;
if (NULL == ptr)
{
result = -1;
errno = EINVAL;
}
else
{
ptr[index] = malloc(sizeof *ptr[index]);
if (NULL == ptr[index])
{
result = -1;
}
else
{
ptr[index]->name = malloc(viname * sizeof *(ptr[index]->name));
if (NULL == ptr[index]->name)
{
result = -1;
free(ptr[index]);
}
}
}
return result;
}
2nd
Then here (assuming na to be a char* properly initilaised to reference a C-"string")
void update(place **ptr,int index)
{
---read string value "na" find the strlen as "pp"---
memallocate(ptr,pp,index);
ptr[index]->name=na;
}
you overwrite what you just assigned to name. To copy a C-"string" use strcpy().
int update(place ** ptr, size_t index)
{
---read string value "na" find the strlen as "pp"---
int result = memallocate(ptr, pp, index)
if (-1 == result)
{
perror("memallocate() failed");
}
else
{
strcpy(ptr[index]->name, na);
}
return result;
}
Then call it like this:
int main(void)
{
size_t index = 0;
place * pla[5] = {NULL};
/* Loop over all array's elements. */
while (index < sizeof pla/sizeof *pla)
{
update(pla, index);
++index;
}
...
}
Notes:
Always check the outcome of relevant function calls (here malloc()) and design your functions to be able to pass failures up to the caller.
Do not cast the result of malloc(), calloc() and realloc() in C. It is not needed nor recommended.
Prefer using size_t over int for memory sizes and indexes. size_t does not waste a bit for negative numbers and it is guaranteed to be large enough to address any arrays' element or represent any memory size. sizeof as well as strlen() return size_t not int for example.
When you call your update(), you are passing a place ** of the current index as argument.
However, you nevertheless pass index too and later in your memallocate() allocate memory as if it was a pointer to the place *[].
So it should help to remove the parameter index from update() and memallocate() and change the memory allocation to something like:
*ptr = (place *)malloc(sizeof(place));
*ptr->name = (char *)malloc(viname*sizeof(char *));
I want to make an array with unknown size , is it true to make it like this ? :
int *array,var,i=0;
FILE *fp;
fopen=("/home/inputFile.txt","r");
fscanf(fp,"%d",&var);
while(fp!=NULL)
{
if(var>0)
{
array=malloc(sizeof(int));
array[i++]=var
}
fscanf(fp,"%d",&var);
}
This is absurdly false, full of memory leaks and undefined behaviors.
However, it's not that far from one of the right ways, the linked list way:
struct linked_int
{
int value;
struct linked_int* pNext;
};
struct linked_int *pHead=NULL;
struct linked_int **ppTail = &pHead;
int* array = NULL;
int cpt=0;
/*Read file, building linked list*/
FILE *fp = fopen("/home/inputFile.txt","r");
if(fp != NULL)
{
int var;
while(fscanf(fp,"%d",&var)==1)
{
if(var>0)
{
struct linked_int *pNew = malloc(sizeof(struct linked_int));
pNew->value = var;
pNew->pNext = NULL;
/*Append at the tail of the list*/
*ppTail = pNew;
ppTail = &(pNew->pNext);
cpt++;
}
}
fclose(fp);
}
/*Copy from the linked list to an array*/
array = malloc(sizeof(int) * cpt);
if(array != NULL)
{
int i;
struct linked_int const *pCur = pHead;
for(i=0 ; i<cpt ; i++)
{
arr[i] = pCur->value;
pCur = pCur->pNext;
}
}
/*Free the linked list*/
while(pHead != NULL)
{
struct linked_int *pDelete = pHead;
pHead = pHead->pNext;
free(pDelete);
}
ppTail = &pHead;
Other ways:
Another right way is the realloc way, which consists in re-allocating the array with an ever expanding size (usually with a geometric growth, i.e. multiplying the array size by a number such as 1.5 every time). A wrong way to do so is to add 1 to the array size every time.
It goes something like this:
int arrayCapacity=0, numberOfItems=0;
int* array = NULL;
int var;
while(fscanf(fp, "%d", &var)==1)
{
if(numberOfItems >= arrayCapacity)
{
/*Need to resize array before inserting*/
const int MIN_CAPACITY = 4;
const double GROWTH_RATE = 1.5;
int newCapacity = arrayCapacity<MIN_CAPACITY ? MIN_CAPACITY : (int)(arrayCapacity*GROWTH_RATE);
int* tmp = realloc(array, newCapacity*sizeof(int));
if(tmp==NULL)
{
/*FAIL: can't make the array bigger!*/
}
else
{
/*Successfully resized the array.*/
array = tmp;
arrayCapacity = newCapacity;
}
}
if(numberOfItems >= arrayCapacity)
{
puts("Cannot add, array is full and can't be enlarged.");
break;
}
else
{
array[numberOfItems] = var;
numberOfItems++;
}
}
/*Now we have our array with all integers in it*/
The obvious result is that in this code, there can be unused space in the array. This isn't a problem.
sizeof(int) will return you 4 (and note that few compilers/settings may say you 2 or 8 in response). So your code is equivalent to allocating a 4 bytes long array.
If you want an array with unknown size, it could be worth to take a loot at STL containers like std::vector (because it will manage allocations and resizes behind the scene). If you plan to stick with "plain C" scope, you may be interested with TSTL2CL library: http://sourceforge.net/projects/tstl2cl
The basic thing is, ARRAY is STATIC not DYNAMIC.