sql order by inside a subquery - sql-server

Question

I have this query:
SELECT * FROM ( SELECT ROW_NUMBER() OVER (ORDER BY CASE WHEN ISNUMERIC(dtLu.sLu) = 1 THEN CONVERT(INT, dtLu.sLu) ELSE 9999999 END asc, dtLu.sLu) as row,
dtLu.*, dtLuDerived.cCll, dtMtrDerived.cMtrCll, dtMtrDerived.cMtrCllIn, dtMtrDerived.cMtrCllOut FROM dtLu
LEFT OUTER JOIN (
SELECT pLu, COUNT(pLu) AS cCll
FROM dtCll
GROUP BY pLu)
AS dtLuDerived ON dtLu.pLu = dtLuDerived.pLu
LEFT OUTER JOIN (
SELECT dtCll.pLu, SUM(cMtrCll) AS cMtrCll, SUM(cMtrCllIn) AS cMtrCllIn, SUM(cMtrCllOut) AS cMtrCllOut
FROM dtMtrCll
INNER JOIN dtCll on dtCll.pCll = dtMtrCll.pCll
WHERE dtCll.pWhr IN (SELECT DISTINCT pWhr FROM dtUserWhr WHERE pUser = 5)
GROUP BY dtCll.pLu)
AS dtMtrDerived ON dtLu.pLu = dtMtrDerived.pLu
INNER JOIN dtLct on dtLct.pLct = dtLu.pLct
WHERE dtLu.pLu > 0 AND dtLct.pLctAsl IN (select pAsl from dtAsl where pAslUnt = 1)
-- this is the ORDER I need
ORDER BY dtLu.pLct DESC
) a
WHERE a.row > 0 and a.row <= 17
but if I use the order ORDER BY dtLu.pLct DESC it gives me error...
The ORDER BY clause is invalid in views, inline functions, derived
tables, subqueries, and common table expressions, unless TOP, OFFSET
or FOR XML is also specified.
I searched, found various samples, but my subquery is different, 'cause is needed to retrieve only 17 rows per page (next page will have the last line like this: WHERE a.row > 17 and a.row <=35)
how can I select the top 17 rows but with an order inside?
thanks

Answer 1

You are trying to put the order in your inner query which doesn't work. Move the order by to the main query. Also, you should list your columns instead of using *. You could probably improved this query a bit with fewer subselects but that is outside the scope of your question.
SELECT * FROM ( SELECT ROW_NUMBER() OVER (ORDER BY CASE WHEN ISNUMERIC(dtLu.sLu) = 1 THEN CONVERT(INT, dtLu.sLu) ELSE 9999999 END asc, dtLu.sLu) as row,
dtLu.* --you should list the columns out here
, dtLuDerived.cCll, dtMtrDerived.cMtrCll, dtMtrDerived.cMtrCllIn, dtMtrDerived.cMtrCllOut FROM dtLu
LEFT OUTER JOIN (
SELECT pLu, COUNT(pLu) AS cCll
FROM dtCll
GROUP BY pLu)
AS dtLuDerived ON dtLu.pLu = dtLuDerived.pLu
LEFT OUTER JOIN (
SELECT dtCll.pLu, SUM(cMtrCll) AS cMtrCll, SUM(cMtrCllIn) AS cMtrCllIn, SUM(cMtrCllOut) AS cMtrCllOut
FROM dtMtrCll
INNER JOIN dtCll on dtCll.pCll = dtMtrCll.pCll
WHERE dtCll.pWhr IN (SELECT DISTINCT pWhr FROM dtUserWhr WHERE pUser = 5)
GROUP BY dtCll.pLu)
AS dtMtrDerived ON dtLu.pLu = dtMtrDerived.pLu
INNER JOIN dtLct on dtLct.pLct = dtLu.pLct
WHERE dtLu.pLu > 0 AND dtLct.pLctAsl IN (select pAsl from dtAsl where pAslUnt = 1)
-- this is the ORDER I need
--ORDER BY dtLu.pLct DESC
) a
WHERE a.row > 0 and a.row <= 17
order by a.pLct

Answer 2

Use TOP 100 Percent in Subquery
SELECT *
FROM (SELECT top 100 percent Row_number()
OVER (
ORDER BY CASE WHEN Isnumeric(dtLu.sLu) = 1 THEN CONVERT(INT, dtLu.sLu) ELSE 9999999 END ASC, dtLu.sLu) AS row,
dtLu.*,
dtLuDerived.cCll,
dtMtrDerived.cMtrCll,
dtMtrDerived.cMtrCllIn,
dtMtrDerived.cMtrCllOut
FROM dtLu
LEFT OUTER JOIN (SELECT pLu,
Count(pLu) AS cCll
FROM dtCll
GROUP BY pLu) AS dtLuDerived
ON dtLu.pLu = dtLuDerived.pLu
LEFT OUTER JOIN (SELECT dtCll.pLu,
Sum(cMtrCll) AS cMtrCll,
Sum(cMtrCllIn) AS cMtrCllIn,
Sum(cMtrCllOut) AS cMtrCllOut
FROM dtMtrCll
INNER JOIN dtCll
ON dtCll.pCll = dtMtrCll.pCll
WHERE dtCll.pWhr IN (SELECT DISTINCT pWhr
FROM dtUserWhr
WHERE pUser = 5)
GROUP BY dtCll.pLu) AS dtMtrDerived
ON dtLu.pLu = dtMtrDerived.pLu
INNER JOIN dtLct
ON dtLct.pLct = dtLu.pLct
WHERE dtLu.pLu > 0
AND dtLct.pLctAsl IN (SELECT pAsl
FROM dtAsl
WHERE pAslUnt = 1)
-- this is the ORDER I need
ORDER BY dtLu.pLct DESC) a
WHERE a.row > 0
AND a.row <= 17