Drawing a triangle with one loop (Revised) - c

Question

The triangle should look like this
1
11
111
1111
11111
111111
the number of rows is entered by the user and then transforms to the function
Note: Without arrays, must be with one loop(while or for) and not nested loops
the closest I got is a code with 2 loop (but can`t think about how to do it with less loops)
int i,k;
for(i=1;i<=x;i++)
{
for(k=1;k<=i;k++)
{
printf("1");
}
printf("\n");
}
The above question was asked by someone but it was marked as off topic I don't know why..?
I came up with this solution tell me if it's correct or not?
int i=1,k=1;
while (i<=x)
{
if(k<=i)
{
printf("1");
k++;
continue;
}
i++;
k=1;
printf("\n");
}
thanks

Answer 1

You can replace loops(iteration) with recursion, try this(with one loop):
#include <stdio.h>
void draw(int depth)
{
int i;
if(depth <= 0) return;
draw(depth-1);
for(i = 0; i < depth; i++)
printf("1");
printf("\n");
}
int main()
{
draw(5);
return 0;
}
You can do it even without loop
#include <stdio.h>
void draw_num_char(int num)
{
if(num <= 0) return;
printf("1");
draw_num_char(num-1);
}
void draw(int depth)
{
int i;
if(depth <= 0) return;
draw(depth-1);
draw_num_char(depth);
printf("\n");
}
int main()
{
draw(5);
return 0;
}

Answer 2

Recursive solution, one loop, no arrays.
#include <stdio.h>
void liner(int line, int limit) {
int i;
if (line > limit)
return;
for(i=1; i<=line; i++)
printf("1");
printf("\n");
liner (line + 1, limit);
}
int main() {
int limit;
printf ("Enter number of lines ");
scanf ("%d", &limit);
liner (1, limit);
return 0;
}