PlayFramework accessing secondary database data with jpa/hibernate - database

Question

I am trying to connect second db to my webapplication written in PlayFramework2.
I've configured correctly my app. I've added already second source callec crm.
Here is my console log:
--- (RELOAD) ---
[info] play - datasource [jdbc:mysql://localhost/svp] bound to JNDI as DefaultDS
[info] play - datasource [jdbc:mysql://192.168.0.4/scrm_customer] bound to JNDI as CRM
[info] play - database [default] connected at jdbc:mysql://localhost/svp
[info] play - database [CRM] connected at jdbc:mysql://192.168.0.4/scrm_customer
[info] play - Application started (Dev)
I've added to my persistence.xml following:
<persistence-unit name="CRM" transaction-type="RESOURCE_LOCAL">
<provider>org.hibernate.ejb.HibernatePersistence</provider>
<non-jta-data-source>CRM</non-jta-data-source>
</persistence-unit>
and my configuration for that:
db.default.jndiName=DefaultDS
db.default.driver=com.mysql.jdbc.Driver
db.default.url="jdbc:mysql://localhost/svp"
db.default.user=root
db.CRM.jndiName=CRM
db.CRM.driver=com.mysql.jdbc.Driver
db.CRM.url="jdbc:mysql://192.168.0.4/scrm_customer"
db.CRM.user=root
db.default.logStatements=true
jpa.default=defaultPersistenceUnit
But when I am trying to get some data from second db using code as follow:
List<Customer> allCustomers = (List<Customer>) JPA.em("CRM")
.createQuery("FROM Customer", Customer.class)
.getResultList();
I am getting an error:
[error] play - Cannot invoke the action, eventually got an error: java.lang.RuntimeException: No JPA EntityManagerFactory configured for name [CRM]
[error] application -
! #6kd0136e7 - Internal server error, for (GET) [/SupraADMIN/klienci] ->
play.api.Application$$anon$1: Execution exception[[RuntimeException: No JPA EntityManagerFactory configured for name [CRM]]]
at play.api.Application$class.handleError(Application.scala:293) ~[play_2.10-2.2.4.jar:2.2.4]
at play.api.DefaultApplication.handleError(Application.scala:399) [play_2.10-2.2.4.jar:2.2.4]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$3$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:264) [play_2.10-2.2.4.jar:2.2.4]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$3$$anonfun$applyOrElse$3.apply(PlayDefaultUpstreamHandler.scala:264) [play_2.10-2.2.4.jar:2.2.4]
at scala.Option.map(Option.scala:145) [scala-library.jar:na]
at play.core.server.netty.PlayDefaultUpstreamHandler$$anonfun$3.applyOrElse(PlayDefaultUpstreamHandler.scala:264) [play_2.10-2.2.4.jar:2.2.4]
Caused by: java.lang.RuntimeException: No JPA EntityManagerFactory configured for name [CRM]
at play.db.jpa.JPA.em(JPA.java:34) ~[play-java-jpa_2.10-2.2.4.jar:2.2.4]
at models.Customer.getCRMList(Customer.java:124) ~[na:na]
at controllers.admin.CMS.Customers(CMS.java:157) ~[na:na]
at admin.Routes$$anonfun$routes$1$$anonfun$applyOrElse$24$$anonfun$apply$24.apply(routes_routing.scala:429) ~[na:na]
at admin.Routes$$anonfun$routes$1$$anonfun$applyOrElse$24$$anonfun$apply$24.apply(routes_routing.scala:429) ~[na:na]
at play.core.Router$HandlerInvoker$$anon$7$$anon$2.invocation(Router.scala:183) ~[play_2.10-2.2.4.jar:2.2.4]
[error] application - REGUEST: GET /SupraADMIN/klienci GENERATED ERROR: #6kd0136e7: Execution exception in /home/korbeldaniel/Aplikacje/Eclipse/SVP/modules/common/app/models/Customer.java:124
What do I miss? I've checked official documentation, but nothing usefull found.
Please help

Answer 1

Annotate your controller method with following annotation:
#Transactional(value = "CRM", readOnly = true)
and within controller method perform:
JPA.em().createQuery("FROM Customer", Customer.class).getResultList();
Or if you dont want to use annotation:
List<Customer> customers = JPA.withTransaction("CRM", true, new Function0<List<Customer>>() {
#Override
public List<Customer> apply() throws Throwable {
return JPA.em().createQuery("FROM Customer", Customer.class).getResultList();
}
});
I would strongly recommend using JPA.withTransactionAsync instead.