I have written this validation rule in Model but want to validate form data without pressing submit button.
Code:
public $validate = array(
'title' => array(
'rule' => 'notEmpty'
)
);
Do i need to put these rules in function to apply javascript?
without pressing button and for processing you can do this with java script, like
<script>
var input = document.getElementsByName('title')[0];
input.onfocus = function() {
(or do anything else what you need)
this.className = 'some_class_name';
}
input.onblur = function() {
(or do anything else what you need)
this.className = '';
}
</script>
Or with jQuery or any another library used for project
Related
So I have two models, that are Company and User. Here are the relations:
Company:
public $hasMany = array(
'User' => array(
'className' => 'User',
'foreignKey' => 'company_id',
)
User:
public $belongsTo = array(
'Company' => array(
'className' => 'Company',
'foreignKey' => 'company_id',
)
And there is a form were both instances are being created. The problem is that only the Company fields are being validated and User is not. Even though the validation rules for just creating or editting a User work perfect. Here is the form in question:
echo $this->Form->create('Company', array('action'=>'register'));?>
echo $this->Form->input('Company.name', array('label'=>__('Company name*')));
echo $this->Form->input('Company.address', array('label'=>__('Address*')));
echo $this->Form->input('Company.city', array('label'=>__('City*')));
echo $this->Form->input('User.0.name', array('label'=>__('Name*')));
echo $this->Form->input('User.0.email', array('label'=>__('Email*')));
echo $this->Form->input('User.0.email_confirmation', array('label'=>__('Email confirmation')));
echo $this->Form->end(array('label'=>'Save', 'onclick'=>'disableSubmit(this)'));
I am fully aware of the validate only option, but I wonder what is the proper way to make validation work.
Any help or guidance is much appreciated.
As requested, I provide the Model logic as well:
public function registerCompany($data){
unset($this->User->validate['company_id']);
if($this->saveAll($data, array('validate'=>'only'))){
if($this->saveAssociated($data)){
return true;
}
}else{
return false;
}
}
Here are some of the validation rules of User model, there are two different validation types for REST service and for web client, so this is for the web client only. NOTE: it works all good on single user create/edit:
$this->validate = array(
'name'=>array(
'Insert user name'=>array(
'rule'=>'notEmpty',
'message'=>'Insert user name',
'last'=>false
)
)
Use this to validate:
Suppose you are saving the data from "Company Controller".
if( $this->Company->saveAll(array('validate'=>only)){
//your save logic here
} else {
//here form has some validation errors.
debug($this->Company->validationErrors);
}
Try this any reply....
Same you can do with "User"
if( $this->User->saveAll(array('validate'=>only)){
//your save logic here
} else {
//here form has some validation errors.
debug($this->User->validationErrors);
}
And
In form use this for user data:
echo $this->Form->input('User.name', array('label'=>__('Name*')));
saveAll is a wrapper of saveMany and saveAssociated. So you don't have to call both methods.
Then, according to the Cake's doc, to unset a validation you should use the syntax : $this->Model->AssociatedModel->validate...
Should look like this :
public function registerCompany($data){
unset($this->Company->User->validate['company_id']);
if($this->Company->saveAssociated($this->request->data)){
return true;
}else{
return false;
}
}
I am developing a Drupal module. Part of it opens a pop-up window, displays some elements in it, and uses JavaScript to transfer input back to the main page.
As this is a small window, I don't want it to display the full theme borders from the site's theme.
In Drupal 6 I was able to achieve this with the following:
function MyPopupPageHandler() {
#content = "Content...";
//Add additional content to #content;
print theme("page", #content);
}
However, Drupal 7 expects the second parameter of the theme() function to be an array, and none of the examples I've seen show how I set the main content of the page.
What I'd like is a custom page template in the module, that can be overridden by the site theme if it provides one.
I would like to know:
What elements do I need to put in the array I pass to the theme() function?
What should I call my template file?
How do I tell Drupal where to find my template, as it needs to be in the module by default?
Appreciate any help you can offer.
James
Try this
First of all create a menu in .module file
function MYMODULE_menu()
{
$items['Demo'] =array(
'title' => 'Demo Page',
'page callback' => 'demo_page', // call a function
'access arguments' => array('access content'),
);
return $items;
}
After you have create a function
function demo_page()
{
$select = db_select('node', 'n');
$select = $select->fields('n', array('id'))
->extend('PagerDefault');
$queried_nodes = $select->execute()
->fetchAllAssoc('id');
$pager = theme('pager');
return theme('demo_template', array('nodes' => $queried_nodes , 'pager' => $pager)); // call a theme or you have no pass any argument in theme to change a 'nodes'=> NULL or 'pager'=>NULL
}
after i have create a theme function
function MYMODULE_theme()
{
return array(
'demo_template' => array(
'template' => 'demo-page',//this is file name of template file
'variables' => array('nodes' => NULL,'pager' => NULL), //this is pass avarible of templates file
'path' => drupal_get_path('module', 'MYMODULE_NAME').'/template' // set a path of file
),
);
}
after you have create file name like demo-page.tpl.php in sites/all/modules/MYMODULENAME/template/
and clear caches
1) The second parameter of theme() function must be an associative array. Your function should look like :
function MYMODULE_custom_function() {
$content = "Some stuff";
return theme('MYMODULE_custom_output', array('content' => $content));
}
2) I guess you meant "Where should I call my template file?" In the hook_theme() function in your same .module file :
function MYMODULE_theme() {
return array(
'MYMODULE_custom_output' => array(
'variables' => array('content' => array()),
// You can also use template file here : 'template' => 'MYMODULE-template'
// OR use the following theme_function() if you don't want to create a new file
),
);
}
// If you don't use template file
function theme_MYMODULE_custom_output($variables) {
$output = // Arrange your html output here
return $output;
}
3) To tell where to find your custom template file if you decide to use one, you can read this : https://drupal.org/node/715160 and I hope it will help.
Please stay indulgent because I'm still new with Drupal and I did try to do my best here :o)
I am looking for input/help on how to do this. Might be some PHP/cake developers could provide some good solutions here. Cakephp 2.3 something :)
Problem; How to put shortcodes in wysiwyg editor (example: [slideshow=1]slideshow here[/slideshow]) and render an element (in this case, loading and displaying the slideshow with ID=1).
ShortcodeHelper.php
App::import('Helper', 'Html', 'Router');
class ShortcodeHelper extends AppHelper {
public $shortcodes = array(
'slideshow' => '/(\[slideshow=)(.+?)(\])(.+?)(\[\/slideshow\])/'
);
public $returncodes = array(
//'slideshow' => $this->render('/elements/slideshow', array('id'=>'\\2'))
'slideshow' => '<strong rel="\\2">\\4</strong>'
);
public function render($content, $render=null) {
$shortcodes = $this->shortcodes;
$returncodes = $this->returncodes;
if(isset($render)) {
$temp_shortcodes = array();
$temp_returncodes = array();
foreach ($render as $key => $value) {
$temp_shortcodes[$key] = $shortcodes[$value];
$temp_returncodes[$key] = $returncodes[$value];
}
$returncodes = $temp_returncodes;
$shortcodes = $temp_shortcodes;
}
$return = preg_replace($shortcodes, $returncodes, $content);
return $this->output($return);
}
}
view.ctp (call render function from helper, and run the page-content trough it):
<?php echo $this->Shortcode->render($page['Page']['body']); ?>
Thanks. You are awesome!! :)
-Tom
You need to turn the short code string into a method call, parse it.
Your helper will need to be able to detect them and then break them up. Your code needs to be mapped somehow to a callback.
// [slideshow=1]slideshow here[/slideshow]
$this->requestAction(array('controller' => 'slideshows', 'action' => 'view', $id);
For example.
I think the best way here would be to just always map the first arg, the "function call" to an element instead and pass all other args to the element. This way you can do there whatever you want and request the data or just simply display HTML only.
I would put the mapping of short codes into something like Configure::write('ShortCodes', $shortCodeArray); this way plugins could even register their callback mapping by simply adding them to that array.
array(
'slideshow' => array('controller' => 'slideshows', 'action' => 'view')
);
You'll have to merge that with args from the parsed short code.
Why requestAction()? You should not violate the MVC pattern, for this reason you'll have to request the data via requestAction().
This would be most simple functional question in Drupal 7.
Now below mentioned things are mandatory to do and cant change the functionality.
1) I have created a custom block in module.
2) I have included form like below:-
function usercontent_block_view($delta='')
{
$block = array();
switch($delta)
{
case 'user_front_page' :
$block['content'] = drupal_get_form('genre_all_login');
break;
}
return $block;
}
3) Now I have some other content in block but which put me in trouble is shown below:-
function genre_all_login($form) {
$form['new_user'] = array(
'#type' => 'item',
'#markup' => l('Add New User','http://www.google.com'),
);
return $form;
}
4) So it includes a link which will move me to Google once clicked.
5) Now I want to validate certain content inside the block before user navigates to Google.So if the condition doesn't match then I will stop the user by showing an error message and hence user cannot traverse to Google.
Please tell me if it is possible or should I use different technique to handle this scenario.
You can set the #markup like:
l('Add New User','http://www.google.com', array('attributes' => array('class' => 'validate_with_js') ))
And then you can write a JavaScript code to validate:
jQuery(document).ready(function() {
jQuery('.validate_with_js').click(function() {
// Your Validation Cdoe. You can use AJAX here if you need to validate through PHP.
});
});
If you want to validate after submission of the form then you can use #element_validate.
Quick questions
Is there Way to Append a textarea using Cakephp
view code:
<?php echo $ajax->link(
$qnote['Qnote']['subject'],
array(
'controller' => 'qnotes',
'action' => 'view', $qnote['Qnote']['id']
),
array( 'update' => 'Textarea_id')
);
?>
controller Code:
function view($id = null) {
$this->Qnote->id = $id;
$this->set('qnote', $this->Qnote->read());
}
the above code Pulls the information But Replaces the entire Text in the textarea.
Is there a way I can just append the textarea with out removing the existing text in the textarea
if possible can somebody point me in the right direction please.
You can try saving the result of your AJAX request to a hidden field and then having it execute and on page javascript function to simply slap the values from the hidden field to the visible text area.
The AJAX helper lets your specify callback functions, so something like this should work:
<?php echo $ajax->link(
$qnote['Qnote']['subject'],
array(
'controller' => 'qnotes',
'action' => 'view', $qnote['Qnote']['id']
),
array( 'update' => 'Textarea_id_hidden', "complete" => "concat_fields()" )
);
?>
and then the JavaScript in the View
<script type="text/javascript">
function concat_fields() {
$('#Textarea_id').val( $('#Textarea_id').val() . $('#Textarea_id_hidden').val() );
}
</script>
Note: My JavaScript example above assumes you're using JQuery, changes will need to be made if you're not.