mmap is wiping my file instead of copying it - c

Question

So I'm using mmap to then write to another file. But the weird thing is, when my code hits mmap, what it does is clears the file. So I have a file that's populated with random characters (AB, HAA, JAK, etc...). What it's supposed to do is use mmap as read basically and then write that file to the new file. So that first if (argc == 3) is the normal read and write, the second if (argc ==4) is supposed to use mmap. Does anyone have any idea why on Earth this is happening?
#include <stdio.h>
#include <sys/types.h>
#include <sys/stat.h>
#include <fcntl.h>
#include <unistd.h>
#include <sys/io.h>
#include <sys/mman.h>
#include <sys/time.h>
#include <sys/resource.h>
int main(int argc, char const *argv[])
{
int nbyte = 512;
char buffer[nbyte];
unsigned char *f;
int bytesRead = 0;
int size;
int totalBuffer;
struct stat s;
const char * file_name = argv[1];
int fd = open (argv[1], O_RDONLY);
int i = 0;
char c;
int fileInput = open(argv[1], O_RDONLY);
int fileOutPut = open(argv[2], O_WRONLY | O_TRUNC | O_CREAT, S_IRUSR | S_IWUSR);
fstat(fileInput, &s);
size = s.st_size;
printf("%d\n", size);
if (argc == 3)
{
printf("size: %d\n", size);
printf("nbyte: %d\n", nbyte);
while (size - bytesRead >= nbyte)
{
read(fileInput, buffer, nbyte);
bytesRead += nbyte;
write(fileOutPut, buffer, nbyte);
}
read(fileInput, buffer, size - bytesRead);
write(fileOutPut, buffer, size - bytesRead);
}
else if (argc == 4)
{
int i = 0;
printf("4 arg\n");
f = (char *) mmap (0, size, PROT_READ, MAP_PRIVATE, fileInput, 0);
/* This is where it is being wipped */
}
close(fileInput);
close(fileOutPut);
int who = RUSAGE_SELF;
struct rusage usage;
int ret;
/* Get the status of the file and print some. Easy to do what "ls" does with fstat system call... */
int status = fstat (fd, & s);
printf("File Size: %d bytes\n",s.st_size);
printf("Number of Links: %d\n",s.st_nlink);
return 0;
}
EDIT: I wanted to mention that the first read and write works perfectly, it is only when you try to do it through the mmap.

Answer 1

If you mean it's clearing your destination file, then yes, that's exactly what your code will do.
It opens the destination with truncation and then, in your argc==4 section, you map the input file but do absolutely nothing to transfer the data to the output file.
You'll need a while loop of some description, similar to the one in the argc==3 case, but which writes the bytes in mapped memory to the fileOutput descriptor.