Bootloader - Display String Runtime Error - c

I am going to write my first "hello world" bootloader program.I found an article on CodeProject website.Here is link of it.
http://www.codeproject.com/Articles/664165/Writing-a-boot-loader-in-Assembly-and-C-Part
Up-to assembly level programming it was going well, but when I wrote program using c,same as given in this article, I faced a runtime error.
Code written in my .c file is as below.
__asm__(".code16\n");
__asm__("jmpl $0x0000,$main\n");
void printstring(const char* pstr)
{
while(*pstr)
{
__asm__ __volatile__("int $0x10": :"a"(0x0e00|*pstr),"b"(0x0007));
++pstr;
}
}
void main()
{
printstring("Akatsuki9");
}
I created image file floppy.img and checking output using bochs.
It was displaying something like this
Booting from floppy...
S
It should be Akatsuki9. I don't know where did I mistake? Can any one help me to find why am I facing this runtime error?

Brief Answer: The problem is with gcc (in fact, this specific application of generated code) and not with the C program itself. It's hidden in the assembly code.
Long Answer: A longer (more elaborate) explanation with specific details of the problem:
(It would be helpful to have the assembly code. It can be obtained using the -S switch of gcc or use the one that I got from gcc; I've attached it at the end). If you don't already know about opcode-prefixing, c-parameter passing in assembly, etc. then have a look at the following background information section. Looking at the assembly source, it's evident that it's 32bit code. gcc with '.code16' produces 16bit code for 32bit-mode processor (using operand-size prefixes). When this same exact code is run in real (i.e. 16bit) mode, it is treated as 32bit code. This is not an issue (80386 and later processors can execute it as such, previous processors just ignore the operand-size prefix). The problem occurs because gcc calculates offsets based on 32bit-mode of (processor) operation, which is not true (by default) when executing boot-code.
Some background information (experienced assembly language programmers should skip this):
1. Operand-size prefix: In x86, prefix bytes (0x66, 0x67, etc.) are used to obtain variants of an instruction. 0x66 is the operand-size prefix to obtain instruction for non-default operand size; gas uses this technique to produce code for '.code16'. For example, in real (i.e. 16bit) mode, 89 D8 corresponds to movw %bx,%ax while 66 89 D8 corresponds to movl %ebx,%eax. This relationship gets reversed in 32bit mode.
2. parameter passing in C: Parameters are passed on stack and accessed through the EBP register.
3. Call instruction: Call is a branching operation with the next instruction's address saved on stack (for resuming). near Call saves only the IP (when in 16bit mode) or EIP ( when in 32bit mode). far Call saves the CS (code-segment register) along with IP/EIP.
4. Push operation: Saves the value on stack. The size of object is subtracted from ESP.
Exact problem
We start at the
movl %esp, %ebp in main: {{ %ebp is set equal to %esp }}
pushl $.LC0 subtracts 4 from Stack Pointer {{ .LC0 addresses the char* "Akatsuki9"; it is getting saved on stack (to be accessed by printstring function) }}
call printstring subtracts 2 from Stack Pointer (16bit Mode; IP is 2bytes)
pushl %ebp in printstring: {{ 4 is subtracted from %esp }}
movl %esp, %ebp {{ %ebp and %esp are currently at 2+4(=6) bytes from the char *pstr }}
pushl %ebx changes %esp but not %ebp
movl 8(%ebp), %edx {{ Accessing 'pstr' at %ebp+8 ??? }}
Accessing 'pstr' at %ebp+8 instead of %ebp+6 (gcc had calculated an offset of 8, assuming 32bit EIP); the program has just obtained an invalid pointer and it's going to cause problem when the program dereferences it later: movsbl (%edx), %eax.
Fix
As of now I don't know of a good fix for this that will work with gcc. For writing boot-sector code, a native 16bit code-generator, I think, is more effective (size-limit & other quirks as explained above). If you insist on using gcc which currently only generates code for 32bit mode, the fix would be to avoid passing function parameters. For more information, refer to the gcc and gas manuals. And please let me know if there is a workaround or some option that works with gcc.
EDIT
I have found a fix for the program to make it work for the desired purpose while still using gcc. Kinda hackish & clearly not-recommended. Why post then? Well, sort of proof of concept. Here it is: (just replace your printstring function with this one)
void printstring(const char* pstr)
{
const char *hackPtr = *(const char**)((char *)&pstr-2);
while(*hackPtr)
{
__asm__ __volatile__("int $0x10": :"a"(0x0e00|*hackPtr),"b"(0x0007));
++hackPtr;
}
}
I invite #Akatsuki and others (interested) to verify that it works. From my above answer and the added C-pointer arithmetic, you can see why it should.
My Assembly-Source file
.file "bootl.c"
#APP
.code16
jmpl $0x0000,$main
#NO_APP
.text
.globl printstring
.type printstring, #function
printstring:
.LFB0:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
pushl %ebx
.cfi_offset 3, -12
movl 8(%ebp), %edx
movl $7, %ebx
.L2:
movsbl (%edx), %eax
testb %al, %al
je .L6
orb $14, %ah
#APP
# 8 "bootl.c" 1
int $0x10
# 0 "" 2
#NO_APP
incl %edx
jmp .L2
.L6:
popl %ebx
.cfi_restore 3
popl %ebp
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE0:
.size printstring, .-printstring
.section .rodata.str1.1,"aMS",#progbits,1
.LC0:
.string "Akatsuki9"
.section .text.startup,"ax",#progbits
.globl main
.type main, #function
main:
.LFB1:
.cfi_startproc
pushl %ebp
.cfi_def_cfa_offset 8
.cfi_offset 5, -8
movl %esp, %ebp
.cfi_def_cfa_register 5
pushl $.LC0
call printstring
popl %eax
leave
.cfi_restore 5
.cfi_def_cfa 4, 4
ret
.cfi_endproc
.LFE1:
.size main, .-main
.ident "GCC: (Ubuntu 4.8.2-19ubuntu1) 4.8.2"
.section .note.GNU-stack,"",#progbits

I have the same problem, and found a solution that may work for you. It works on the emulators (I tested on bochs and qemu), but can't make it work on real hardware.
Solution
One thing is to use gcc-4.9.2, and to change the code generation to .code16gcc.
Thus, your code becomes:
__asm__(".code16gcc\n");
__asm__("jmpl $0x0000,$main\n");
void printstring(const char* pstr)
{
while(*pstr)
{
__asm__ __volatile__("int $0x10": :"a"(0x0e00|*pstr),"b"(0x0007));
++pstr;
}
}
void main()
{
printstring("Akatsuki9");
}
and to compile it use the -m16 flag on gcc, in my case I tried
gcc -c -m16 file.c
Note that you can change the architecture according to your needs, by setting -march. Or if you want to keep the flags of the tutorial
gcc -c -g -Os -march=i386 -ffreestanding -Wall -Werror -m16 file.c
tl;dr
Set .code16gcc instead of .code16, and use -m16 with gcc-4.9.2.

Related

How do i get rid of call __x86.get_pc_thunk.ax

I tried to compile and convert a very simple C program to assembly language.
I am using Ubuntu and the OS type is 64 bit.
This is the C Program.
void add();
int main() {
add();
return 0;
}
if i use gcc -S -m32 -fno-asynchronous-unwind-tables -o simple.S simple.c this is how my assembly source code File should look like:
.file "main1.c"
.text
.globl main
.type main, #function
main:
pushl %ebp
movl %esp, %ebp
andl $-16, %esp
call add
movl $0, %eax
movl %ebp, %esp
popl %ebp
ret
.size main, .-main
.ident "GCC: (Debian 4.4.5-8) 4.4.5" // this part should say Ubuntu instead of Debian
.section .note.GNU-stack,"",#progbits
but instead it looks like this:
.file "main0.c"
.text
.globl main
.type main, #function
main:
leal 4(%esp), %ecx
andl $-16, %esp
pushl -4(%ecx)
pushl %ebp
movl %esp, %ebp
pushl %ebx
pushl %ecx
call __x86.get_pc_thunk.ax
addl $_GLOBAL_OFFSET_TABLE_, %eax
movl %eax, %ebx
call add#PLT
movl $0, %eax
popl %ecx
popl %ebx
popl %ebp
leal -4(%ecx), %esp
ret
.size main, .-main
.section
.text.__x86.get_pc_thunk.ax,"axG",#progbits,__x86.get_pc_thunk.ax,comdat
.globl __x86.get_pc_thunk.ax
.hidden __x86.get_pc_thunk.ax
.type __x86.get_pc_thunk.ax, #function
__x86.get_pc_thunk.ax:
movl (%esp), %eax
ret
.ident "GCC: (Ubuntu 6.3.0-12ubuntu2) 6.3.0 20170406"
.section .note.GNU-stack,"",#progbits
At my University they told me to use the Flag -m32 if I am using a 64 bit Linux version. Can somebody tell me what I am doing wrong?
Am I even using the correct Flag?
edit after -fno-pie
.file "main0.c"
.text
.globl main
.type main, #function
main:
leal 4(%esp), %ecx
andl $-16, %esp
pushl -4(%ecx)
pushl %ebp
movl %esp, %ebp
pushl %ecx
subl $4, %esp
call add
movl $0, %eax
addl $4, %esp
popl %ecx
popl %ebp
leal -4(%ecx), %esp
ret
.size main, .-main
.ident "GCC: (Ubuntu 6.3.0-12ubuntu2) 6.3.0 20170406"
.section .note.GNU-stack,"",#progbits
it looks better but it's not exactly the same.
for example what does leal mean?
As a general rule, you cannot expect two different compilers to generate the same assembly code for the same input, even if they have the same version number; they could have any number of extra "patches" to their code generation. As long as the observable behavior is the same, anything goes.
You should also know that GCC, in its default -O0 mode, generates intentionally bad code. It's tuned for ease of debugging and speed of compilation, not for either clarity or efficiency of the generated code. It is often easier to understand the code generated by gcc -O1 than the code generated by gcc -O0.
You should also know that the main function often needs to do extra setup and teardown that other functions do not need to do. The instruction leal 4(%esp),%ecx is part of that extra setup. If you only want to understand the machine code corresponding to the code you wrote, and not the nitty details of the ABI, name your test function something other than main.
(As pointed out in the comments, that setup code is not as tightly tuned as it could be, but it doesn't normally matter, because it's only executed once in the lifetime of the program.)
Now, to answer the question that was literally asked, the reason for the appearance of
call __x86.get_pc_thunk.ax
is because your compiler defaults to generating "position-independent" executables. Position-independent means the operating system can load the program's machine code at any address in (virtual) memory and it'll still work. This allows things like address space layout randomization, but to make it work, you have to take special steps to set up a "global pointer" at the beginning of every function that accesses global variables or calls another function (with some exceptions). It's actually easier to explain the code that's generated if you turn optimization on:
main:
leal 4(%esp), %ecx
andl $-16, %esp
pushl -4(%ecx)
pushl %ebp
movl %esp, %ebp
pushl %ebx
pushl %ecx
This is all just setting up main's stack frame and saving registers that need to be saved. You can ignore it.
call __x86.get_pc_thunk.bx
addl $_GLOBAL_OFFSET_TABLE_, %ebx
The special function __x86.get_pc_thunk.bx loads its return address -- which is the address of the addl instruction that immediately follows -- into the EBX register. Then we add to that address the value of the magic constant _GLOBAL_OFFSET_TABLE_, which, in position-independent code, is the difference between the address of the instruction that uses _GLOBAL_OFFSET_TABLE_ and the address of the global offset table. Thus, EBX now points to the global offset table.
call add#PLT
Now we call add#PLT, which means call add, but jump through the "procedure linkage table" to do it. The PLT takes care of the possibility that add is defined in a shared library rather than the main executable. The code in the PLT uses the global offset table and assumes that you have already set EBX to point to it, before calling an #PLT symbol.  That's why main has to set up EBX even though nothing appears to use it. If you had instead written something like
extern int number;
int main(void) { return number; }
then you would see a direct use of the GOT, something like
call __x86.get_pc_thunk.bx
addl $_GLOBAL_OFFSET_TABLE_, %ebx
movl number#GOT(%ebx), %eax
movl (%eax), %eax
We load up EBX with the address of the GOT, then we can load the address of the global variable number from the GOT, and then we actually dereference the address to get the value of number.
If you compile 64-bit code instead, you'll see something different and much simpler:
movl number(%rip), %eax
Instead of all this mucking around with the GOT, we can just load number from a fixed offset from the program counter. PC-relative addressing was added along with the 64-bit extensions to the x86 architecture. Similarly, your original program, in 64-bit position-independent mode, will just say
call add#PLT
without setting up EBX first. The call still has to go through the PLT, but the PLT uses PC-relative addressing itself and doesn't need any help from its caller.
The only difference between __x86.get_pc_thunk.bx and __x86.get_pc_thunk.ax is which register they store their return address in: EBX for .bx, EAX for .ax. I have also seen GCC generate .cx and .dx variants. It's just a matter of which register it wants to use for the global pointer -- it must be EBX if there are going to be calls through the PLT, but if there aren't any then it can use any register, so it tries to pick one that isn't needed for anything else.
Why does it call a function to get the return address? Older compilers would do this instead:
call 1f
1: pop %ebx
but that screws up return-address prediction, so nowadays the compiler goes to a little extra trouble to make sure every call is paired with a ret.
The extra junk you're seeing is due to your version of GCC special-casing main to compensate for possibly-broken entry point code starting it with a misaligned stack. I'm not sure how to disable this or if it's even possible, but renaming the function to something other than main will suppress it for the sake of your reading.
After renaming to xmain I get:
xmain:
pushl %ebp
movl %esp, %ebp
subl $8, %esp
call add
movl $0, %eax
leave
ret

GCC assembly code shows 32bit registers on 64bit machine

I am trying to learn how to use ptrace library for tracing all system calls and their arguments. I am stuck in getting the arguments passed to system call.
I went through many online resources and SO questions and figured out that on 64 bit machine the arguments are stored in registers rax(sys call number), rdi, rsi, rdx, r10, r8, r9
in the same order. Check this website .
Just to confirm this I wrote a simple C program as follows
#include<stdio.h>
#include<fcntl.h>
int main() {
printf("some print data");
open("/tmp/sprintf.c", O_RDWR);
}
and generated assembly code for this using gcc -S t.c but assembly code generated is as below
.file "t.c"
.section .rodata
.LC0:
.string "some print data"
.LC1:
.string "/tmp/sprintf.c"
.text
.globl main
.type main, #function
main:
.LFB0:
.cfi_startproc
pushq %rbp
.cfi_def_cfa_offset 16
.cfi_offset 6, -16
movq %rsp, %rbp
.cfi_def_cfa_register 6
movl $.LC0, %edi
movl $0, %eax
call printf
movl $2, %esi
movl $.LC1, %edi
movl $0, %eax
call open
popq %rbp
.cfi_def_cfa 7, 8
ret
.cfi_endproc
.LFE0:
.size main, .-main
.ident "GCC: (Ubuntu 4.8.4-2ubuntu1~14.04.3) 4.8.4"
.section .note.GNU-stack,"",#progbits
As you can see this code is storing parameters on esi and edi instead.
Why is happening?
Also please guide me on what is the best way to access these passed arguments from these registers/memory location from a C code? How can I figure out if the contents of register is the argument itself or is it a memory location where actual argument is stored?
Thanks!
this code is storing parameters on esi and edi
32-bit instructions are smaller, thus preferred when possible. See also Why do most x64 instructions zero the upper part of a 32 bit register.
How can I figure out if the contents of register is the argument itself or is it a memory location where actual argument is stored?
The AMD64 SystemV calling convention never implicitly replaces a function arg with a hidden pointer. Integer / pointer args in the C prototype always go in the arg-passing registers directly.
structs / unions passed by value go in one or more registers, or on the stack.
The full details are documented in the ABI. See more links in the x86 tag wiki. http://www.x86-64.org/documentation.html is down right now, so I linked the current revision on github.

x86 calling convention: should arguments passed by stack be read-only?

It seems state-of-art compilers treat arguments passed by stack as read-only. Note that in the x86 calling convention, the caller pushes arguments onto the stack and the callee uses the arguments in the stack. For example, the following C code:
extern int goo(int *x);
int foo(int x, int y) {
goo(&x);
return x;
}
is compiled by clang -O3 -c g.c -S -m32 in OS X 10.10 into:
.section __TEXT,__text,regular,pure_instructions
.macosx_version_min 10, 10
.globl _foo
.align 4, 0x90
_foo: ## #foo
## BB#0:
pushl %ebp
movl %esp, %ebp
subl $8, %esp
movl 8(%ebp), %eax
movl %eax, -4(%ebp)
leal -4(%ebp), %eax
movl %eax, (%esp)
calll _goo
movl -4(%ebp), %eax
addl $8, %esp
popl %ebp
retl
.subsections_via_symbols
Here, the parameter x(8(%ebp)) is first loaded into %eax; and then stored in -4(%ebp); and the address -4(%ebp) is stored in %eax; and %eax is passed to the function goo.
I wonder why Clang generates code that copy the value stored in 8(%ebp) to -4(%ebp), rather than just passing the address 8(%ebp) to the function goo. It would save memory operations and result in a better performance. I observed a similar behaviour in GCC too (under OS X). To be more specific, I wonder why compilers do not generate:
.section __TEXT,__text,regular,pure_instructions
.macosx_version_min 10, 10
.globl _foo
.align 4, 0x90
_foo: ## #foo
## BB#0:
pushl %ebp
movl %esp, %ebp
subl $8, %esp
leal 8(%ebp), %eax
movl %eax, (%esp)
calll _goo
movl 8(%ebp), %eax
addl $8, %esp
popl %ebp
retl
.subsections_via_symbols
I searched for documents if the x86 calling convention demands the passed arguments to be read-only, but I couldn't find anything on the issue. Does anybody have any thought on this issue?
The rules for C are that parameters must be passed by value. A compiler converts from one language (with one set of rules) to a different language (potentially with a completely different set of rules). The only limitation is that the behaviour remains the same. The rules of the C language do not apply to the target language (e.g. assembly).
What this means is that if a compiler feels like generating assembly language where parameters are passed by reference and are not passed by value; then this is perfectly legal (as long as the behaviour remains the same).
The real limitation has nothing to do with C at all. The real limitation is linking. So that different object files can be linked together, standards are needed to ensure that whatever the caller in one object file expects matches whatever the callee in another object file provides. This is what's known as the ABI. In some cases (e.g. 64-bit 80x86) there are multiple different ABIs for the exact same architecture.
You can even invent your own ABI that's radically different (and implement your own tools that support your own radically different ABI) and that's perfectly legal as far as the C standards go; even if your ABI requires "pass by reference" for everything (as long as the behaviour remains the same).
Actually, I just compiled this function using GCC:
int foo(int x)
{
goo(&x);
return x;
}
And it generated this code:
_foo:
pushl %ebp
movl %esp, %ebp
subl $24, %esp
leal 8(%ebp), %eax
movl %eax, (%esp)
call _goo
movl 8(%ebp), %eax
leave
ret
This is using GCC 4.9.2 (on 32-bit cygwin if it matters), no optimizations. So in fact, GCC did exactly what you thought it should do and used the argument directly from where the caller pushed it on the stack.
The C programming language mandates that arguments are passed by value. So any modification of an argument (like an x++; as the first statement of your foo) is local to the function and does not propagate to the caller.
Hence, a general calling convention should require copying of arguments at every call site. Calling conventions should be general enough for unknown calls, e.g. thru a function pointer!
Of course, if you pass an address to some memory zone, the called function is free to dereference that pointer, e.g. as in
int goo(int *x) {
static int count;
*x = count++;
return count % 3;
}
BTW, you might use link-time optimizations (by compiling and linking with clang -flto -O2 or gcc -flto -O2) to perhaps enable the compiler to improve or inline some calls between translation units.
Notice that both Clang/LLVM and GCC are free software compilers. Feel free to propose an improvement patch to them if you want to (but since both are very complex pieces of software, you'll need to work some months to make that patch).
NB. When looking into produced assembly code, pass -fverbose-asm to your compiler!

Why does GCC not optimise away the function prologue and epilogue (push ebp; mov ebp, esp; ...; pop ebp) [duplicate]

This question already has answers here:
Is the gcc insane optimisation level (-O3) not insane enough?
(2 answers)
Closed 9 years ago.
When compiling a simple function that does not even alter the ebp register GCC still saves the value at the start of the function and then restores the same value at the end:
#add.c
int add( int a, int b )
{
return ( a + b );
}
gcc -c -S -m32 -O3 add.c -o add.S
#add.S
.file "add.c"
.text
.p2align 4,,15
.globl add
.type add, #function
add:
pushl %ebp
movl %esp, %ebp
movl 12(%ebp), %eax
addl 8(%ebp), %eax
popl %ebp
ret
.size add, .-add
.ident "GCC: (GNU) 4.4.6"
.section .note.GNU-stack,"",#progbits
It would seem like a simple optimisation to leave ebp untouched, calculate offsets relative to esp and save 3 instructions.
Why does GCC not do this?
Thanks,
Andrew
Tools such as debuggers and stack walkers used to expect code to have a prologue that constructed a frame pointer, and couldn't understand code that didn't have it. Over time, the restriction has been removed.
The compiler itself has no difficulty generating code without a frame pointer, and you can ask for it to be removed with -fomit-frame-pointer. I believe that recent versions of gcc (~4.8) and gcc on x86-64 omit the frame pointer by default.

Understanding empty main()'s translation into assembly

Could somebody please explain what GCC is doing for this piece of code? What is it initializing? The original code is:
#include <stdio.h>
int main()
{
}
And it was translated to:
.file "test1.c"
.def ___main; .scl 2; .type 32; .endef
.text
.globl _main
.def _main; .scl 2; .type 32; .endef
_main:
pushl %ebp
movl %esp, %ebp
subl $8, %esp
andl $-16, %esp
movl $0, %eax
addl $15, %eax
addl $15, %eax
shrl $4, %eax
sall $4, %eax
movl %eax, -4(%ebp)
movl -4(%ebp), %eax
call __alloca
call ___main
leave
ret
I would be grateful if a compiler/assembly guru got me started by explaining the stack, register and the section initializations. I cant make head or tail out of the code.
EDIT:
I am using gcc 3.4.5. and the command line argument is gcc -S test1.c
Thank You,
kunjaan.
I should preface all my comments by saying, I am still learning assembly.
I will ignore the section initialization. A explanation for the section initialization and basically everything else I cover can be found here:
http://en.wikibooks.org/wiki/X86_Assembly/GAS_Syntax
The ebp register is the stack frame base pointer, hence the BP. It stores a pointer to the beginning of the current stack.
The esp register is the stack pointer. It holds the memory location of the top of the stack. Each time we push something on the stack esp is updated so that it always points to an address the top of the stack.
So ebp points to the base and esp points to the top. So the stack looks like:
esp -----> 000a3 fa
000a4 21
000a5 66
000a6 23
ebp -----> 000a7 54
If you push e4 on the stack this is what happens:
esp -----> 000a2 e4
000a3 fa
000a4 21
000a5 66
000a6 23
ebp -----> 000a7 54
Notice that the stack grows towards lower addresses, this fact will be important below.
The first two steps are known as the procedure prolog or more commonly as the function prolog. They prepare the stack for use by local variables (See procedure prolog quote at the bottom).
In step 1 we save the pointer to the old stack frame on the stack by calling
pushl %ebp. Since main is the first function called, I have no idea what the previous value of %ebp points too.
Step 2, We are entering a new stack frame because we are entering a new function (main). Therefore, we must set a new stack frame base pointer. We use the value in esp to be the beginning of our stack frame.
Step 3. Allocates 8 bytes of space on the stack. As we mentioned above, the stack grows toward lower addresses thus, subtracting by 8, moves the top of the stack by 8 bytes.
Step 4; Aligns the stack, I've found different opinions on this. I'm not really sure exactly what this is done. I suspect it is done to allow large instructions (SIMD) to be allocated on the stack,
http://gcc.gnu.org/ml/gcc/2008-01/msg00282.html
This code "and"s ESP with 0xFFFF0000,
aligning the stack with the next
lowest 16-byte boundary. An
examination of Mingw's source code
reveals that this may be for SIMD
instructions appearing in the "_main"
routine, which operate only on aligned
addresses. Since our routine doesn't
contain SIMD instructions, this line
is unnecessary.
http://en.wikibooks.org/wiki/X86_Assembly/GAS_Syntax
Steps 5 through 11 seem to have no purpose to me. I couldn't find any explanation on google. Could someone who really knows this stuff provide a deeper understanding. I've heard rumors that this stuff is used for C's exception handling.
Step 5, stores the return value of main 0, in eax.
Step 6 and 7 we add 15 in hex to eax for unknown reason. eax = 01111 + 01111 = 11110
Step 8 we shift the bits of eax 4 bits to the right. eax = 00001 because the last bits are shift off the end 00001 | 111.
Step 9 we shift the bits of eax 4 bits to the left, eax = 10000.
Steps 10 and 11 moves the value in the first 4 allocated bytes on the stack into eax and then moves it from eax back.
Steps 12 and 13 setup the c library.
We have reached the function epilogue. That is, the part of the function which returns the stack pointers, esp and ebp to the state they were in before this function was called.
Step 14, leave sets esp to the value of ebp, moving the top of stack to the address it was before main was called. Then it sets ebp to point to the address we saved on the top of the stack during step 1.
Leave can just be replaced with the following instructions:
mov %ebp, %esp
pop %ebp
Step 15, returns and exits the function.
1. pushl %ebp
2. movl %esp, %ebp
3. subl $8, %esp
4. andl $-16, %esp
5. movl $0, %eax
6. addl $15, %eax
7. addl $15, %eax
8. shrl $4, %eax
9. sall $4, %eax
10. movl %eax, -4(%ebp)
11. movl -4(%ebp), %eax
12. call __alloca
13. call ___main
14. leave
15. ret
Procedure Prolog:
The first thing a function has to do
is called the procedure prolog. It
first saves the current base pointer
(ebp) with the instruction pushl %ebp
(remember ebp is the register used for
accessing function parameters and
local variables). Now it copies the
stack pointer (esp) to the base
pointer (ebp) with the instruction
movl %esp, %ebp. This allows you to
access the function parameters as
indexes from the base pointer. Local
variables are always a subtraction
from ebp, such as -4(%ebp) or
(%ebp)-4 for the first local variable,
the return value is always at 4(%ebp)
or (%ebp)+4, each parameter or
argument is at N*4+4(%ebp) such as
8(%ebp) for the first argument while
the old ebp is at (%ebp).
http://www.milw0rm.com/papers/52
A really great stack overflow thread exists which answers much of this question.
Why are there extra instructions in my gcc output?
A good reference on x86 machine code instructions can be found here:
http://programminggroundup.blogspot.com/2007/01/appendix-b-common-x86-instructions.html
This a lecture which contains some of the ideas used below:
http://csc.colstate.edu/bosworth/cpsc5155/Y2006_TheFall/MySlides/CPSC5155_L23.htm
Here is another take on answering your question:
http://www.phiral.net/linuxasmone.htm
None of these sources explain everything.
Here's a good step-by step breakdown of a simple main() function as compiled by GCC, with lots of detailed info: GAS Syntax (Wikipedia)
For the code you pasted, the instructions break down as follows:
First four instructions (pushl through andl): set up a new stack frame
Next five instructions (movl through sall): generating a weird value for eax, which will become the return value (I have no idea how it decided to do this)
Next two instructions (both movl): store the computed return value in a temporary variable on the stack
Next two instructions (both call): invoke the C library init functions
leave instruction: tears down the stack frame
ret instruction: returns to caller (the outer runtime function, or perhaps the kernel function that invoked your program)
Well, dont know much about GAS, and i'm a little rusty on Intel assembly, but it looks like its initializing main's stack frame.
if you take a look, __main is some kind of macro, must be executing initializations.
Then, as main's body is empty, it calls leave instruction, to return to the function that called main.
From http://en.wikibooks.org/wiki/X86_Assembly/GAS_Syntax#.22hello.s.22_line-by-line:
This line declares the "_main" label, marking the place that is called from the startup code.
pushl %ebp
movl %esp, %ebp
subl $8, %esp
These lines save the value of EBP on the stack, then move the value of ESP into EBP, then subtract 8 from ESP. The "l" on the end of each opcode indicates that we want to use the version of the opcode that works with "long" (32-bit) operands;
andl $-16, %esp
This code "and"s ESP with 0xFFFF0000, aligning the stack with the next lowest 16-byte boundary. (neccesary when using simd instructions, not useful here)
movl $0, %eax
movl %eax, -4(%ebp)
movl -4(%ebp), %eax
This code moves zero into EAX, then moves EAX into the memory location EBP-4, which is in the temporary space we reserved on the stack at the beginning of the procedure. Then it moves the memory location EBP-4 back into EAX; clearly, this is not optimized code.
call __alloca
call ___main
These functions are part of the C library setup. Since we are calling functions in the C library, we probably need these. The exact operations they perform vary depending on the platform and the version of the GNU tools that are installed.
Here's a useful link.
http://unixwiz.net/techtips/win32-callconv-asm.html
It would really help to know what gcc version you are using and what libc. It looks like you have a very old gcc version or a strange platform or both. What's going on is some strangeness with calling conventions. I can tell you a few things:
Save the frame pointer on the stack according to convention:
pushl %ebp
movl %esp, %ebp
Make room for stuff at the old end of the frame, and round the stack pointer down to a multiple of 4 (why this is needed I don't know):
subl $8, %esp
andl $-16, %esp
Through an insane song and dance, get ready to return 1 from main:
movl $0, %eax
addl $15, %eax
addl $15, %eax
shrl $4, %eax
sall $4, %eax
movl %eax, -4(%ebp)
movl -4(%ebp), %eax
Recover any memory allocated with alloca (GNU-ism):
call __alloca
Announce to libc that main is exiting (more GNU-ism):
call ___main
Restore the frame and stack pointers:
leave
Return:
ret
Here's what happens when I compile the very same source code with gcc 4.3 on Debian Linux:
.file "main.c"
.text
.p2align 4,,15
.globl main
.type main, #function
main:
leal 4(%esp), %ecx
andl $-16, %esp
pushl -4(%ecx)
pushl %ebp
movl %esp, %ebp
pushl %ecx
popl %ecx
popl %ebp
leal -4(%ecx), %esp
ret
.size main, .-main
.ident "GCC: (Debian 4.3.2-1.1) 4.3.2"
.section .note.GNU-stack,"",#progbits
And I break it down this way:
Tell the debugger and other tools the source file:
.file "main.c"
Code goes in the text section:
.text
Beats me:
.p2align 4,,15
main is an exported function:
.globl main
.type main, #function
main's entry point:
main:
Grab the return address, align the stack on a 4-byte address, and save the return address again (why I can't say):
leal 4(%esp), %ecx
andl $-16, %esp
pushl -4(%ecx)
Save frame pointer using standard convention:
pushl %ebp
movl %esp, %ebp
Inscrutable madness:
pushl %ecx
popl %ecx
Restore the frame pointer and the stack pointer:
popl %ebp
leal -4(%ecx), %esp
Return:
ret
More info for the debugger?:
.size main, .-main
.ident "GCC: (Debian 4.3.2-1.1) 4.3.2"
.section .note.GNU-stack,"",#progbits
By the way, main is special and magical; when I compile
int f(void) {
return 17;
}
I get something slightly more sane:
.file "f.c"
.text
.p2align 4,,15
.globl f
.type f, #function
f:
pushl %ebp
movl $17, %eax
movl %esp, %ebp
popl %ebp
ret
.size f, .-f
.ident "GCC: (Debian 4.3.2-1.1) 4.3.2"
.section .note.GNU-stack,"",#progbits
There's still a ton of decoration, and we're still saving the frame pointer, moving it, and restoring it, which is utterly pointless, but the rest of the code make sense.
It looks like GCC is acting like it is ok to edit main() to include CRT initialization code. I just confirmed that I get the exact same assembly listing from MinGW GCC 3.4.5 here, with your source text.
The command line I used is:
gcc -S emptymain.c
Interestingly, if I change the name of the function to qqq() instead of main(), I get the following assembly:
.file "emptymain.c"
.text
.globl _qqq
.def _qqq; .scl 2; .type 32; .endef
_qqq:
pushl %ebp
movl %esp, %ebp
popl %ebp
ret
which makes much more sense for an empty function with no optimizations turned on.

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