Program to code zigzag matrix - c

Question

Recently, I encountered with a problem that asked me to write a dynamic code that print n x n matrix in a zigzag pattern. Please help me with the code to get the output stated below.
Output:
rows: 5
cols: 5
1 2 3 4 5
10 9 8 7 6
11 12 13 14 15
20 19 18 17 16
21 22 23 24 25
The Code that I've tried so far is in static:
#include <stdio.h>
int main(){
int arr[3][3]={1,2,3,
4,5,6,
7,8,9};
int i, j, k;
for(i=0; i<3; i++){
printf("%d",arr[0][i]);
}
printf("\n");
for(j=2; j>=0; j--){
printf("%d",arr[1][j]);
}
printf("\n");
for(k=0; k<3; k++){
printf("%d",arr[2][k]);
}
printf("\n");
return 0;
}
Now I want the same thing to be done with the user stating rows and columns of an array..

Answer 1

This should work for you:
#include <stdio.h>
int main() {
int rows, columns;
int rowCount, columnCount, count = 0;
printf("Please enter rows and columns:\n>");
scanf("%d %d", &rows, &columns);
for(rowCount = 0; rowCount < rows; rowCount++) {
for(columnCount = 1; columnCount <= columns; columnCount++) {
if(count % 2 == 0)
printf("%4d " , (columnCount+(rowCount*columns)));
else
printf("%4d " , ((rowCount+1)*columns)-columnCount+1);
}
count++;
printf("\n");
}
return 0;
}
Input:
5 5
Output:
1 2 3 4 5
10 9 8 7 6
11 12 13 14 15
20 19 18 17 16
21 22 23 24 25

Answer 2

Simple dynamic logic with k variable
#include <stdio.h>
int main() {
int i,j,k=1,row,col;
printf("Enter row and col \n>");
scanf("%d %d", &row, &col);
for (i = 1; i <=row; i++)
{
for (j = 1; j <=col; j++)
{
if(i%2==0) k--;
printf("%4d",k); // it have to be in center of both condition
if(i%2!=0) k++;
}
k=k+col;
printf("\n");
}
return 0;
}
Input :
7 7
Output :
1 2 3 4 5 6 7
14 13 12 11 10 9 8
15 16 17 18 19 20 21
28 27 26 25 24 23 22
29 30 31 32 33 34 35
42 41 40 39 38 37 36
43 44 45 46 47 48 49