I am trying to write a program that reads a string from the user and prints the string's characters in a diagonal pattern. I set the maximum length of the string as 50 characters. The program can print the characters in a diagonal pattern, but it doesn't print the characters correctly.
#include<stdio.h>
int main () {
int i = 0, j = 0, m;
char c[50];
printf("Enter a string: ");
scanf("%c", c);
m = sizeof(c) / sizeof(c[0]);
for (i = 1; i <= m; i++) {
for (j = 1; j <= i; j++) {
if (j == i) {
printf("%c", c[i-1]);
} else {
printf(" ");
}
}
printf("\n");
}
return 0;
}
Check the code below:
#include<stdio.h>
int main ()
{
int i=0,s=0;
char c[50];
printf("Enter a string: ");
scanf("%s",c);
while(c[i] != '\0')
{
s = i;
while(s--)
printf(" ");
printf("%c\n",c[i]);
i++;
}
return 0;
}
Related
I want to input an array of integers then print out the even numbers from the inputted numbers..
example is if I input 2466688992,
it will output 24666882;
I have a my code below:
#include<stdio.h>
int main()
{
int a[5],i;
printf("Enter array of numbers: ");
scanf("%d",&a);
for(i=0; i<sizeof(a); i++){
if(a[i]%2==0)
printf("%d",a[i]);
}
getch();
return 0;
}
It resulted into garbage : 2468000075416640419940000004225568000
This is the function that prints even numbers in an integer :
#include<stdio.h>
int main(){
int num,rem,even=0,digit;
printf(" Enter an integer number: ");
scanf("%d",&num);
printf("\n The even digits present in %d are \n",num);
while(num>0){
digit = num % 10;
num = num / 10;
rem = digit % 2;
if(rem == 0)
even++;
printf("\n %d.",digit);
}
return 0;
}
You should scan the array as a string (unless you want to impose the number of items in the array), and then parse the string to store the different numbers:
long a[50];
char buf[1024];
printf("Enter array of numbers: ");
scanf("%s",buf);
int len = strlen(buf);
int j = 0;
for (int i = 0; i < len; ) {
long sign = 1;
long n = 0;
if (buf[i] == '+') {
++i;
}
else if (buf[i] == '-') {
sign = -1;
++i;
}
if (isdigit(buf[i])) {
while (isdigit(buf[i])) {
n = 10 * n + buf[i++] - '0';
}
a[j] = n * sign;
}
else
i++;
}
for (int i = 0; i < j; i++)
if (!(a[i] ℅ 2)) // true if even
printf("%ld ", a[i]);
This will store all your digits in your array a of size j.
Edit: if you are talking about digits then its easier:
char buf[1024];
printf("Enter array of numbers: ");
scanf("%s",buf);
int len = strlen(buf);
for (int i = 0; i < len; i++)
if (isdigit(buf[i]) && !((buf[i] - '0') ℅ 2)) // true if even, note that '0' equals 0x30 so there is no need to sub it to check for odd/even in reality.
printf("%c ", buf[i]);
I'm trying to make a C program to insert elements into an array until user inputs a 0 or less number, as the title says. But when I print the array out, it doesn't show the numbers I inputted. I have tried using a while as well as do-while loops but without success.
#include <stdio.h>
int main() {
int data[100];
int i;
for (i = 0; i < 100; i++) {
printf("Input your number:\n");
scanf("%d", &data[i]);
if (data[i] <= 0) {
break;
}
}
printf("Your array：");
int n = sizeof(data[i]);
for (int i = 0; i < n; i++) {
printf("%d ", &data[i]);
}
}
Try this:
#include <stdio.h>
int main() {
int data[100];
int i;
int counter = 0;
for (i = 0; i < 100; i++) {
printf("Input your number:\n");
scanf("%d", &data[i]);
counter++;
if (data[i] <= 0) {
break;
}
}
printf("Your array：");
for (int j = 0; j < counter - 1; j++) {
printf("%d ", data[j]);
}
}
The problem was that you had printf("%d ", &data[i]); instead of printf("%d ", data[i]);.
And also you've trying to get the sizeof() of an element data[i], not the size of the whole array. That's why there's counter in my code.
int n = sizeof(data[i]);
this is wrong, you want
int n = i;
sizeof(data[i]) gives you the size of an int (4 on my machine)
On the other hand, you need to check the result of scanf, if a bad input is entered do not increment the counter, something like:
int i = 0;
while (i < 100)
{
int res = scanf("%d", &data[i]);
if (res == EOF)
{
break;
}
if (res == 1)
{
if (data[i] <= 0)
{
break;
}
i++;
}
else
{
// Sanitize stdin
int c;
while ((c = getchar()) != '\n');
}
}
Finally, scanf wants a pointer to the object, but this is not the case of printf:
printf("%d ", &data[i])
should be
printf("%d ", data[i])
I've got this homework assignment where we get the user to enter the amount of lines of strings they desire, they then proceed to enter them which gets stored in a 2D Array (thus creating an array of strings). Then a switch case menu will be displayed which should
Search a character entered by the user, returns the amount of times the character occurred in the array
Search a word entered by the user, returns the amount of times the word occurred in the array
Have the user enter a specified word length and return the amount of times words of the specified length occur.
I have a couple problems with my code. The program runs without errors from the compiler. The searchByCharacter function works fine but the searchByWord only returns a value of 0 regardless of any word inputted and nothing happens after I input a number for the searchByLength function. The program freezes after I enter a length once I select the searchByLength function. I've been at this for a while and I don't know where I'm going wrong.
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX_LINE_LENGTH 80
#define MAX_LINES 10
#define WORD_LENGTH 20
void readText(char text[][MAX_LINE_LENGTH], int n)
{
int i;
printf("Enter %d number of lines:\n", n);
for(i = 0; i < n; i++)
{
scanf(" %[^\n]s", text[i]);
}
}
int searchByCharacter(char text[][MAX_LINE_LENGTH], int n, char c)
{
int i, charCount = 0, j = 0;
for(i = 0; i < n; i++)
{
j = 0;
while(text[i][j] != '\0')
{
if(text[i][j] == c)
{
charCount++;
}
j++;
}
}
return charCount;
}
int searchByWord(char text[][MAX_LINE_LENGTH], int n, char * keyword)
{
int i, wordCount = 0;
for(i = 0; i < n; i++)
{
int j = 0;
int lengthOfWord = 0;
char wordCheck[WORD_LENGTH];
char * currentLine = text[i];
while(currentLine[j] != '\0')
{
if (currentLine[j] == ' ' || currentLine[j] == '\n' || currentLine[j] == ',' || currentLine[j] == '.' ||
currentLine[j] == ';')
{
wordCheck[lengthOfWord] = '\0';
int matchingWord = strcmp(wordCheck, keyword);
if(matchingWord == 0)
{
wordCount++;
}
lengthOfWord = 0;
j++;
continue;
}
wordCheck[lengthOfWord] = currentLine[n];
lengthOfWord++;
j++;
}
}
return wordCount;
}
int searchByLength(char text[][MAX_LINE_LENGTH], int n, int wordLen)
{
int i, lengthCount = 0;
for(i = 0; i < n; i++)
{
int lengthOfWord = 0;
int j = 0;
char * currentLine2 = text[i];
while(currentLine2[j] != '\0')
{
if (currentLine2[j] == ' ' || currentLine2[j] == '\n' || currentLine2[j] == ',' || currentLine2[j] == '.' ||
currentLine2[j] == ';')
{
if(lengthOfWord == wordLen)
{
lengthCount++;
}
lengthOfWord = 0;
n++;
continue;
}
lengthOfWord++;
n++;
}
}
return lengthCount;
}
int main(void)
{
char textInput[MAX_LINES][MAX_LINE_LENGTH];
printf("Enter number of lines (<10): ");
int textLines = 0;
scanf("%d", &textLines);
while(textLines < 1 || textLines > 10)
{
printf("Invalid Input.\n");
printf("Enter number of lines (<10): ");
scanf("%d", &textLines);
}
if(textLines >= 1 && textLines <= 10)
{
readText(textInput, textLines);
int menuActive = 1;
while(menuActive)
{
printf("\nText Analysis\n----\n");
printf("1-Search By Character\n2-Search By Word\n3-Search By Length\n0-Quit\nPlease enter a selection: ");
int selection;
scanf("%d", &selection);
switch(selection)
{
case 0:
menuActive = 0;
break;
case 1:
printf("Selected 1\n");
printf("Enter a character to search: ");
char characterSearch;
scanf(" %c", &characterSearch);
int characterwordCount = searchByCharacter(textInput, textLines, characterSearch);
printf("\nNumber of occurence of %c = %d", characterSearch, characterwordCount);
break;
case 2:
printf("Selected 2\n");
printf("Enter a word to search: ");
char wordSearch[MAX_LINE_LENGTH];
scanf(" %s", wordSearch);
int lengthwordCount = searchByWord(textInput, textLines, wordSearch);
printf("\nNumber of occurence of %s = %d", wordSearch, lengthwordCount);
break;
case 3:
printf("Selected 3\n");
printf("Enter search length: ");
int wordLength;
scanf(" %d", &wordLength);
int wordLengthwordCount = searchByLength(textInput, textLines, wordLength);
printf("Number of words with length %d = %d", wordLength, wordLengthwordCount);
break;
default:
printf("Invalid Input.\n");
}
}
printf("You Have Quit!\n");
}
return 0;
}
As stated in the title I am trying to find all lower-case letters that are not in a series of words. There are no upper-case letters, digits, punctuation, or special symbols.
I need help fixing my code. I am stuck and do not know where to go from here.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
int main(void){
int letters[26];
char words[50];
int i = 0, b = 0;
printf("Enter your input : ");
scanf("%s", words);
for(i = 0; i < 26; i++){
letters[i] = 0;
}
while(!feof(stdin)){
for(b = 0; b < strlen(words) - 1; b++){
letters[ words[b] - 'a']++;
scanf("%s", words);
}
}
printf("\nMissing letters : %c ", b + 97);
return 0;
}
My output is giving me some random letter that I do not know where it is coming from.
Here is a working first implementation.
As well as the comments that have already been made, you should use functions wherever possible to separate out the functionality of the program into logical steps. Your main function should then just call the appropriate functions in order to solve the problem. Each function should be something that is self contained and testable.
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#define MAX_INPUT 20 /* Max input to read from user. */
char *readinput(void);
void find_missing_lower_case(char *, int);
int main()
{
char *user_input = readinput();
int len_input = strlen(user_input);
printf("user input: %s\n", user_input);
printf("len input: %d\n", len_input);
find_missing_lower_case(user_input, len_input);
/* Free the memory allocated for 'user_input'. */
free(user_input);
return 0;
}
char *readinput()
{
char a;
char *result = (char *) malloc(MAX_INPUT);
int i;
for(i = 0; i < MAX_INPUT; ++i)
{
scanf("%c", &a);
if( a == '\n')
{
break;
}
*(result + i) = a;
}
*(result + i) = '\0';
return result;
}
void find_missing_lower_case(char *input, int len_input)
{
int a = 97; /* ASCII value of 'a' */
int z = 122; /* ASCII value of 'z' */
int lower_case_chars[26] = {0}; /* Initialise all to value of 0 */
/* Scan through input and if a lower case char is found, set the
* corresponding index of lower_case_chars to 1
*/
for(int i = 0; i < len_input; i++)
{
char c = *(input + i);
if(c >= a && c <= z)
{
lower_case_chars[c - a] = 1;
}
}
/* Iterate through lower_case_chars and print any values that were not set
* to 1 in the above for loop.
*/
printf("Missing lower case characters:\n");
for(int i = 0; i < 26; i++)
{
if(!lower_case_chars[i])
{
printf("%c ", i + a);
}
}
printf("\n");
}
I figured it out and this is the code I used.
int main(void)
{
int array[26];
char w;
int i=0;
for(i=0; i<26; i++) {
array[i]=0; }
printf("Enter your input: ");
scanf("%c", &w);
while(!feof(stdin)) {
array[w-97] = 1;
scanf("%c", &w); }
printf("Missing letters: ");
for(i=0; i<26; i++) {
if(array[i] == 0) {
printf("%c ", i+97); }
}
printf("\n");
return 0;
}
I am having trouble doing my homework.
I am doing an RSA application which can encrypt and decrypt.
The problem is that after I Input things to encrypt the results are weird and I can't decrypt anything. This is because when I copied the results of encryption which are symbols, I got more weird stuffs.
I'm guessing it has something to do with my formula getting negative ASCIIs as results.
Below is what I tried, and, in order to understand what I meant by weird, just compile and try it out(I have some unused stuffs which I haven't removed yet):
Output:
Code:
#include <stdio.h>
#include <string.h>
#include <stdlib.h>
#include <ctype.h>
#include <math.h>
#define boolean int
#define true 1
#define false 0
//===================================================//
int p = 0;
int q = 0;
int n = 0;
int m = 0;
int divider = 2;
int tempdivider = 2;
int initial = 0;
int x = 0;
int y = 0;
char msg[100];
char alphabet[27];
//===================================================//
void cls();
void menu();
void init();
void reinit();
void inputencrypt();
//int encrypt(int num);
void encrypt();
char decrypt(char text[]);
int fpb(int num);
int d(int num);
int primecheck(int a);
boolean checkdigit(char text[]);
//===================================================//
int main() {
frontpage();
init();
menu();
getchar();
return 0;
}
//===================================================//
void cls() {
for (int i = 0;i < 25;i++) {
printf("\n");
}
}
//===================================================//
boolean checkdigit(char text[]) {
int len = strlen(text);
for (int i = 0;i < len;++i) {
if (text[i]<'0' || text[i]>'9') {
return false;
}
}
return true;
}
int primecheck(int a) {
if (a == 1) {
return false;
}
for (int i = 2;i < a;i++) {
if (a%i == 0) {
return false;
}
}
return true;
}
//===================================================//
void reinit() {
for (int i = 1;i < 27;i++) {
alphabet[i] = 'a' + i - 1;
}
p = 0;
q = 0;
n = 0;
m = 0;
divider = 2;
tempdivider = 2;
initial = 120;
x = 0;
y = 0;
}
void init() {
reinit();
do {
printf("p = ");
scanf("%d", &p);fflush(stdin);
if (!primecheck(p)) {
printf("must be prime number! \n");
}
} while (!primecheck(p));
do {
printf("q = ");
scanf("%d", &q);fflush(stdin);
if (!primecheck(q)) {
printf("must be prime number! \n");
}
} while (!primecheck(q));
n = p*q;
m = (p - 1)*(q - 1);
initial = m;
x = fpb(m);
y = d(m);
printf("n = %d\n", n);
printf("m = %d\n", m);
printf("e = %d\n", x);
printf("d = %d\n", y);
system("pause");
}
//===================================================//
void menu() {
char input[2];
int input1 = 0;
do {
do {
cls();
printf("main menu\n");
printf("================\n");
printf("1. encrypt\n");
printf("2. decrypt\n");
printf("3. exit\n");
printf(">> ");
scanf("%s", input);fflush(stdin);
if (checkdigit(input)) {
input1 = atoi(input);
}
} while (!checkdigit(input));
switch (input1) {
case 1:
int c;
char encrypted[100];
char word[100];
printf("input word to encrypt : ");
scanf(" %[^\n]", word);fflush(stdin);
for (int i = 0;i < strlen(word);i++) {
if (word[i] == ' ') {
encrypted[i] = ' ';
//i++;
}
else {
for (int j = 1;j < 27;j++) {
if (word[i] == alphabet[j]) {
c = 0;
c = pow(j, x);
c = c%n;
encrypted[i] = c;
break;
}
}
}
}
printf("\n\nWord ASCII [ ");
for (int i = 0;i < strlen(word);i++) {
//printf("%d", c);
printf("%d ", word[i]);
}
printf(" ]\n");
printf("\n\nEncrypted ASCII [ ");
for (int i = 0;i < strlen(word);i++) {
//printf("%d", c);
printf("%d ", encrypted[i]);
}
printf(" ]\n");
printf("\n\nEncrypted [ ");
for (int i = 0;i < strlen(word);i++) {
//printf("%d", c);
printf("%c", encrypted[i]);
}
printf(" ]");
printf("\n\n\n");
system("pause");
break;
case 2:
int temp[100];
char decrypted[100];
char wordx[100];
int h;
printf("input word to decrypt : ");
scanf(" %[^\n]", wordx);fflush(stdin);
for (int i = 0;i < strlen(wordx);i++) {
temp[i] = wordx[i];
//temp[i] -= 97;
//printf("%d ::: %c\n", temp[i], temp[i]);
}
for (int i = 0;i < strlen(wordx);i++) {
if (wordx[i] == ' ') {
decrypted[i] = ' ';
}
else {
h = 0;
h = pow(temp[i], y);
h = h%n;
decrypted[i] = h;
for (int j = 1;j < 27;j++) {
if (decrypted[i] == j) {
decrypted[i] = alphabet[j];
}
}
}
}
printf("\n\nWord ASCII [ ");
for (int i = 0;i < strlen(wordx);i++) {
//printf("%d", c);
printf("%d ", wordx[i]);
}
printf(" ]\n");
printf("\n\nDecrypted ASCII [ ");
for (int i = 0;i < strlen(wordx);i++) {
//printf("%d", c);
printf("%d ", decrypted[i]);
}
printf(" ]\n");
printf("\n\nDecrypted [ ");
for (int i = 0;i < strlen(wordx);i++) {
//printf("%d", decrypted[i]);
printf("%c", decrypted[i]);
}
printf(" ]");
printf("\n\n\n");
system("pause");
break;
}
} while (input1 != 3);
}
//===================================================//
int fpb(int num) {
if (!primecheck(num)) {
if (num%divider == 0) {
num = num / divider;
divider = 2;
}
else {
divider++;
}
fpb(num);
}
else if (primecheck(num)) {
if (!primecheck(num + divider)) {
tempdivider++;
divider = tempdivider;
num = initial;
fpb(num);
}
else {
return num + divider;
}
}
}
int d(int num) {
for (int i = 1;i < num;i++) {
if ((x*i) % num == 1) {
return i;
}
}
}
You have a general comprehension problem. Your console is only able to represent 96 characters correctly (known as printable 7bit-ASCII characters, 0x20 to 0x7F), but a byte can hold 255 different values. Your encryption algorithm does not care about this limited range, it will encrypt any value in the range [0..255] into another value in the range [0..255]. So your ASCII input characters will most likely be encrypted into values that cannot be represented by your console correctly. Copy&Past will not work correctly for non-printable characters (like 0x0B, which is a tab).
But now you will wonder: Why does that work for e.g. E-Mails? Simply: Because those characters are converted into an ASCII representation. Please google a bit for Base64 encoding.
As an alternative, you can always stream your encrypted characters into a file and later read back from that. This way you will bypass the limitations of your console.
Btw: Please have a look at the documentation of printf() and you will know, why you get those negative values.
The encrypt option has these three statements consecutively
c = 0;
c = pow(j, x);
c = c%n;
and the last of those will leave c in the range 0..(n-1).
Apart from that, there is no else clause and int c; can remain uninitialised.
So all in all it is inevitable that when you print c values as characters you will get "weird" results.
As for negative values, char encrypted[100]; is probably signed char so any integer value in the range 128..255 assigned to that, although undefined behaviour, may possibly show up as a negative number because the signed char is promoted back to int when passed as format %d to printf.