Find intersection in 2d arrays - c

Question

I wrote a small code to find intersection of two 2d array, unfortunately it is not working, so maybe you can help me.. Intersection is, if both numbers on place (x,y) is a "1". Otherwise there should be "0"
void intersection(int *mat, int rows, int cols) {
int rows1 = 5, cols1 = 4; // secend matrix is in function because i just need it here
int ma2[] = { 0, 0, 1, 0, 1, // 1. Zeile
0, 0, 1, 0, 1, // 2. Zeile
0, 0, 1, 1, 0, // 3. Zeile
0, 0, 1, 0, 0 // 4. Zeile
};
int i = 0;
int j = 0;
int x = 0;
int y = 0;
while (j < cols && y < cols1) { // maybe it is better with a for loop ??
j += 1;
y += 1;
while (i < rows && x < rows1) {
i += 1;
x += 1;
if (mat[j*rows+i] == 1 && ma2[y*rows1+x] == 1) {
printf("%d ", mat[j*rows+i]);
break;
} else {
printf("%d ", mat[j*rows+i]);
break;
}
}
printf("\n");
}
}
int main (void) {
int rows = 5, cols = 4; //first matrix is in main, because i need it for other functions
int ma[] = { 0, 0, 1, 0, 0, // 1. Zeile
1, 0, 0, 0, 0, // 2. Zeile
1, 0, 1, 0, 0, // 3. Zeile
0, 0, 1, 0, 0 // 4. Zeile
};
intersection(ma, rows, cols);
return 0;
}
Output should be (in this case):
{ 0, 0, 1, 0, 0, // 1. Zeile
0, 0, 0, 0, 0, // 2. Zeile
0, 0, 1, 0, 0, // 3. Zeile
0, 0, 1, 0, 0 // 4. Zeile
};
but i just get a matrix with 1 row
Greets ;)

Answer 1

try this
#define min(x,y) ((x) < (y) ? (x) : (y))
void intersection(int *mat, int rows, int cols) {
rows = min(rows, 5);//rows <--> cols
cols = min(cols, 4);
int ma2[] = { 0, 0, 1, 0, 1, // 1. Zeile
0, 0, 1, 0, 1, // 2. Zeile
0, 0, 1, 1, 0, // 3. Zeile
0, 0, 1, 0, 0 // 4. Zeile
};
int i, j;
for(i = 0; i < cols; ++i){
for(j = 0; j < rows; ++j){
//printf("%d ", mat[i*rows + j] == ma2[i*rows + j] ? mat[i*rows + j] : 0);
printf("%d ", mat[i*rows + j] & ma2[i*rows + j]);
}
printf("\n");
}
}

Answer 2

I solved the problem with this solution ;) Thank you everyone for helping me ...
void intersection(int *mat, int rows, int cols) {
int ma2[4][5] = {{0, 1, 0, 0, 0},
{0, 1, 0, 0, 0},
{1, 1, 0, 1, 0},
{0, 1, 0, 0, 0}};
int i = 0;
int j = 0;
int t = 1;
int s = 0;
for(j = 0; j < cols; j++) {
for (i = 0; i < rows; i++) {
if (ma2[j][i] && mat[j*rows+i] == 1) {
printf("%d ", t);
} else {
printf("%d ", s);
}
}
printf("\n");
}
}