I am trying to use managed variable in a CUDA program and I am getting a segmentation fault when trying to set the managed variable on the host side. I am doing exactly the same as mentioned in the documentation here(http://docs.nvidia.com/cuda/cuda-c-programming-guide/#managed-qualifier). Why is this happening?
#include <cuda.h>
#define THREADS_PER_BLOCK 32
#define BLOCKS_PER_SM 1
#define MB(x) ((x) << 20)
__device__ __managed__ int val = 0;
__global__ void test_kernel(char *src)
{
src[0] = val;
}
int main(int argc, char *argv[])
{
char *data;
int size = 2; // 2 MB
val = 100; //<--- seg fault gone if I comment this line
cudaMallocManaged(&data, MB(size));
test_kernel<<<BLOCKS_PER_SM, THREADS_PER_BLOCK>>>(data);
cudaDeviceSynchronize();
cudaFree(data);
return 0;
}
Sorry for the noise guys. It was a big FAIL on my part. My device is a 3.0 capability device, but I was compiling for compute_50 which is not supported. Thanks for the suggestions!
Related
I'm relatively new to C and cannot figure out why this program seg faults.
It could be a stupid error on my behalf but cannot seem to figure it out.
I also know its unusual using the embedding method I am, but this was down for sheer familiarity with Python3 and the ease of use.
#define PY_SSIZE_T_CLEAN
#define PAM_SM_AUTH
#define PAM_SM_ACCOUNT
//#define PAM_SM_SESSION
#include <dlfcn.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <security/pam_appl.h>
#include <security/pam_modules.h>
#include </usr/include/python3.6m/Python.h>
/* expected hook */
/*
PAM_EXTERN int pam_sm_setcred( pam_handle_t *pamh, int flags, int argc, const char **argv ) {
return PAM_SUCCESS;
}
PAM_EXTERN int pam_sm_acct_mgmt(pam_handle_t *pamh, int flags, int argc, const char **argv) {
printf("Acct mgmt\n");
return PAM_SUCCESS;
}
*/
/* expected hook, this is where custom stuff happens */
PAM_EXTERN int pam_sm_authenticate( pam_handle_t *pamh, int flags,int argc, const char **argv )
{
chdir("../code/facial"); // this changes it to the correct directory to execute
dlopen("/usr/lib/x86_64-linux-gnu/libpython3.6m.so",RTLD_LAZY | RTLD_GLOBAL);
Py_Initialize(); // Starts python interpreter
PyRun_SimpleString("import os\nimport sys\nsys.path.append(os.getcwd())"); // lets python know where we are
PyObject *mymod, *func1, *ret1;
mymod = PyImport_ImportModule("pam_detect"); // This is the .py
if (mymod != 0){ // check if the file file was loaded
func1 = PyObject_GetAttrString(mymod, "detect"); // hel is the function name in the file you declared earlier
ret1 = PyObject_CallObject(func1, NULL); // Null because the function doesnt take an argument.
if (ret1 == 1){
Py_Finalize();
return PAM_SUCCESS;
}
else{
Py_Finalize();
return PAM_AUTH_ERR;
}
}
else{
//printf("Error: can't find file!\n");
return 1;
}
Py_Finalize();
return 0;
}
You have defined the pointers but haven't assigned them to a memory address.
PyObject *mymod, *func1, *ret1;
This line in your code makes a pointer named mymod which can point to a memory containing PyObject, but you haven't given the memory address to it yet.
I don't know if calling the functions will return pointers correctly or not, So when you try to put anything there, it gives segmentation fault if you are trying to assign a variable to a pointer without a memory address.
I can only say this much without knowing where the fault occurred. try putting printf statement before assigning of all 3 pointers and see.
I'm getting a segmentation error (core dump) when I try to run this. It compiles perfectly but I get the error, and I don't know why. There must be a problem with a file writing because without this works good. Any help would be great. Thanks!
#include <stdio.h>
#include <time.h>
#include <unistd.h>
#include <crypt.h>
#include <string.h>
int
main(void)
{
FILE *f=fopen("shadow1.txt","w");
if (f=NULL)
{
printf("ERROR");
}
unsigned long seed[2];
char salt[] = "$1$........";
const char *const seedchars =
"./0123456789ABCDEFGHIJKLMNOPQRST"
"UVWXYZabcdefghijklmnopqrstuvwxyz";
char *password;
int i;
/* Generate a (not very) random seed.
You should do it better than this... */
seed[0] = time(NULL);
seed[1] = getpid() ^ (seed[0] >> 14 & 0x30000);
/* Turn it into printable characters from ‘seedchars’. */
for (i = 0; i < 8; i++)
salt[3+i] = seedchars[(seed[i/5] >> (i%5)*6) & 0x3f];
/* Read in the user’s password and encrypt it. */
password = crypt(getpass("Password:"), salt);
/* Print the results. */
//fprintf(f,"%s $ %s",password);
printf("Success Registration to file !");
fclose(f);
return 0;
}
if (f=NULL)
{
printf("ERROR");
}
was the problem...
void Register(char u,char p) {
you probably want these to be char * because of the fprintf that treats them as strings:
fprintf(f,"%s $ %s",u,p);
and since you pass char *s in:
char *password,*username;
//...
Register(username,password);
This would most likely have been caught by compiler warnings. It is a lot faster to get your answer from the compiler than from here.
If you can't figure out why your program isn't working, you can enable all the warnings you should need with -Wall -Wextra and turn warnings into errors with -Werror.
You are not allocating space to hold username so it will segfault on the scanf.
I want to initialize an array of size 1MB. So my goal is finally write that 1MB to a file.
I am curious every time i use this formula it is giving less than 1mb.
int len = (1048576)/sizeof(int);
data = (int *) malloc(len);
What is correct way ?
Thank you
Edit - As per the comments I have changed the code .
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
#include <string.h>
int main(int argc, char *argv[]) {
int *data;
int bytes = (1024*1024);
data = (int *) malloc(bytes);
for(int i=0;i<bytes;i++){
data[i] = (int)rand();
printf("%d",data[i]);
}
return 0;
}
After compiling it and I tried dumping the data like below
mpicc -o a mpiFileSize.c
./a > dump.dat
Now I see the file size of dump.dat. Why its 2.5MB ?
Try this
#include <stdio.h>
#include <stdlib.h>
#include <mpi.h>
#include <string.h>
int main(int argc, char *argv[]) {
char *data;
int bytes = (1024*1024);
data = (char *) malloc(bytes);
for(int i=0;i<bytes;i++){
data[i] = (char) rand();
printf("%c",data[i]);
}
return 0;
}
You shoul use character instead of integer.
Although it was already properly answered.
Just a plus to the answer, if one wants to choose the amount of MBs to allocate would make something like:
#include <malloc.h>
#define Mebabyte (1024 * 1024)
int main(int argc, char** argv)
{
void* data = malloc(2 * Megabyte);
// Do your work here...
free(data);
return 0;
}
If you wanted to allocate more than 2 MBs just change the 2.
As already stated before do not use integers as it's going to have more than 1 byte of size. Instead use char or unsigned char. And as stated by another post, there's no need to cast the result of malloc since void* can be turned to a pointer to any type (and in fact it's done implicitly by the compiler).
see: Why does this code segfault on 64-bit architecture but work fine on 32-bit?
I've been trying to use the SHA_256 functions in sha256.h on a FreeBSD 9.1 system but it seems to be corrupting memory space of my program causing all kinds of manic behavior. I wrote up a quick program to just to play with those functions and still am having problems.
In the example below, int i is changed when I call SHA256_Init(), as shown by the output from the printf() statements surrounding it.
This is what I get running the code.
$ ./miner "hello world"
i = 0
i = 32
0000000032 9010a9cf81ce2c28a642fd03ddf6da5790c65c30cd4a148c4257d3fe488bacc7
Why is this value changing to 32? Am I missing something? The code is below...
#include <sha256.h>
#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#include <sys/types.h>
#define DIFFICULTY 0
int main(int argc, const char **argv) {
uint nonce, i, j;
SHA256_CTX ctx;
size_t arglen;
unsigned char digest[32];
char * data;
if(argc < 1) exit(1);
arglen = strlen(argv[1]);
data = malloc(arglen + 1);
char digestStr[65];
i = 0;
do {
nonce = i;
strncpy(data, argv[1], arglen + 1);
printf("i = %i\n", i);
SHA256_Init(&ctx);
printf("i = %i\n", i);
SHA256_Update(&ctx, data, arglen);
SHA256_Update(&ctx, (unsigned char *) &nonce, sizeof(nonce));
SHA256_Final(digest, &ctx);
SHA256_End(&ctx, digestStr);
printf("%010i\t%s\n", i, digestStr);
j = 0;
while(j < 32 && digest[j] == '\0') {
j++;
}
i++;
} while(j < DIFFICULTY);
free(data);
return 0;
}
I just had this exact same problem and solved it.
The issue is that your are including a different header in your code than the SHA2 library you linked into your application is using.
In my case the SHA256_CTX struct was a different size in the openSSL library. The openSSL library's struct was 8 bytes bigger than the struct length in the file.
The function SHA256_Init(&ctx) does a memset on the SHA256_CTX struct which then corrupts 8 extra random bytes after the struct. I say random because it will do different things in a release vs debug build because the optimizing compiler will move your variables around.
Why do I get segmentation fault in this function:
#include <stdio.h>
#include <stdlib.h>
#include "math.h"
vec_t mtrx_multiple (sparse_mat_t a, vec_t c) {
vec_t result;
int i;
result.n = a.n;
printf("result.n: %d\n", result.n);
result.vec = malloc(a.n * sizeof *result.vec);
for(i=0; i<a.n; i++)
result.vec[i] = c.vec[i] * a.a[a.ja[i]];
return result;
}
The structure is:
typedef struct {
int n;
int *vec;
} vec_t;
typedef struct {
int *a;
int *ia;
int *ja;
int n;
} sparse_mat_t;
Thanks for help
I suspect the problem is with a.a[a.ja[i]], you should try verifying the values a.ja[i] before using them to index a.a.
It would be useful to know how a is initialised, and also on which line the segfault occurs.
Malloc could be failing and returning null.
a.ja[i] might not be between 0 and n. What is the ja array supposed to represent, anyway?
Our speculating isn't going to produce the answer. Running your program under a debugger will.
I suspect this is the line where the trouble is:
result.vec = malloc(a.n * sizeof *result.vec);
for(i=0; i<a.n; i++)
result.vec[i] = c.vec[i] * a.a[a.ja[i]];
The reason is that you are not mallocing for each result.vec[i]..
Can you confirm this?
Edit:
Thanks Alok and Devel for informing me about my error...
What does sizeof *result.vec return? Admittedly it looks confusing as if the precedence between sizeof gets mixed with the *...
Hope this helps,
Best regards,
Tom.
typedef struct {
int n;
int *vec;
} vec_t;
int main(int argc, char **argv) {
vec_t result;
int i;
int size;
result.n = 5;
size = result.n * sizeof *result.vec;
result.vec = malloc(size);
for(i=0; i<result.n; i++) {
result.vec[i] = i;
}
return i;
}
I have to agree with Autopulated, this version of your code runs just fine, the only thing I left out in this refactoring is the a and c related stuff. I would check that a and c are being initialized properly.