I have input array {{1,4}, {1,3}, {1,4,7}}
Dim array1() As Long
ReDim array1(3, 3)
array1(1, 1) = 1
array1(1, 2) = 4
array1(2, 1) = 1
array1(2, 2) = 3
array1(3, 1) = 1
array1(3, 2) = 4
array1(3, 3) = 7
I would like to have output array (which is length of each subarray) {2,2,3}
I am thinking to use for loop as following
Dim i As Long
i = UBound(array1, 1)
Dim outputarray() As Long
ReDim outputarray(i) As Long
For j = 1 To i
outputarray(i) = UBound(array1(i), 2) 'ERROR APPEAR
Next j
i added Option Base 1
The length of each subarray stay the same, its always 3 in your case. Your redim has defined the number you want to get. So there's no point trying to retrieve it like you want to do.
The fact that you don't move any values in
array1(1, 3)
array1(2, 3)
doesn't affect the dimensions of your array. You'll find values in these what-you-think-empty array's cells, and it will be 0 because you declared your array as long. If you had declared it as string, you would find a blank string in them, neither null nor "nothing".
You have input array {{1,4,0}, {1,3,0}, {1,4,7}}
If your aim is to find which elements of your array are 0 because you didn't moved anything in them, that's another story not related to the length of your array.
I agree with Thomas' answer above.
If you do find yourself interested in knowing the number of populated array values in the array, you might consider the following:
Start with the first row, and the right-most value in that array. So your for loop would actually be two loops - one to go through the first dimension, and one to go through the second dimension.
Move left through the array until you run into a non-zero value. Keep a count of the total values that are zero. When you run into a non-zero value, subtract the total zero values from the second dimension of the array. This will give you the "length" that you were looking for before.
So for example:
Dim i As int
Dim j As int
Dim h As int
Dim w As int
h = UBound(array1, 1)
w = UBound(array1, 2)
Dim rowVals as int
Dim arrVals as int
For i = 0 To h
rowVals = 0
For j = w to 0 Step -1
if array1(i,j) = 0 Then
exit for
else
rowVals = rowVals + 1
end if
Next
arrVals = arrVals + rowVals
Next
Related
I have a array which have 1 or more columns and now I want to add one more column (consists only of 1), but I don't know how do do that. The situation looks like that:
My code:
Dim X() As Variant
X = Range("A1:C3").Value2
It's is important to put column with 1 as first. Probably I need to use ReDim Preserve but nothing works for me.
I think you have some options, but instead of extending the index of the array and transposing, trying to move the values etc which seems too much of a hassle, I would rather add 1 to the Excel range and then create the array:
Range("B1:D3").Value2 = Range("A1:C3").Value2
Range("A1:A3").Value2 = 1
X = Range("A1:D3").Value2
Resize the Array adding a column to the last dimension
Shift all the data to the right.
Assign 1 to the first position in each row
Sub AddColumnShiftData()
Dim X As Variant
Dim i As Long, j As Long
X = Range("A1:C3").Value2
ReDim Preserve X(1 To 3, 1 To 4)
For i = 1 To UBound(X)
For j = UBound(X, 2) To 2 Step -1
X(i, j) = X(i, j - 1)
Next
X(i, 1) = 1
Next
End Sub
Try matrix multiplication by the identify matrix....Well almost identity matrix. Then add 1 to every element in of the resulting matrix. You can use the Excel's Worksheet function for matrix multiplication.
Almost identity matrix
Dim X As Variant
X = Range("A1:C3").Value2
Dim Y As Variant
n = UBound(X, 2)
m = n + 1
Z = UBound(X, 1)
ReDim Y(1 To n, 1 To m)
'Set All values to zero
For i = 1 To n
For j = 1 To m
Y(i, j) = 0
Next j
Next i
' Set offset diagonal to 1
For i = 1 To n
Y(i, i + 1) = 1
Next i
' Matrix MMult
X = Application.WorksheetFunction.MMult(X, Y)
' Add 1 to the first column
For i = 1 To Z
X(i, 1) = 1
Next i
Alternative via Application.Index()
Just for fun (note that the resulting array is a 1-based 2-dim array):
Sub AddFirstIndexColumn()
Const FIXEDVALUE = 1 ' value to replace in new column 1
'[1] get data
Dim v: v = getExampleData()
'[2] define column array inserting first column (0 or 1) and preserving old values (1,2,3)
v = Application.Index(v, _
Application.Evaluate("row(1:" & UBound(v) & ")"), _
Array(1, 1, 2, 3)) ' columns array where 0 reinserts the first column
' [3] add an current number in the first column
Dim i As Long
For i = LBound(v) To UBound(v): v(i, 1) = FIXEDVALUE: Next i
End Sub
Function getExampleData()
' Method: just for fun a rather unusual way to create a 2-dim array
' Caveat: time-consuming for greater data sets; better to assign a range to a datafield array
Dim v
v = Array(Array(2, 3, 5), Array(3, 8, 9), Array(4, 2, 1))
v = Application.Index(v, 0, 0)
getExampleData = v
End Function
Related links
Some pecularities of `Application.Index()
Insert vertical slices into array
I need a function to extract 2 dimensions from a multidimesion array. which 2 dimensions to extract depending on the choise of the user. and the index in the discarded dimensions where those 2 dimensions are picked also depending on the user.
For example, i have a 3 dimension array v(1 to 100, 1 to 20, 1 to 10). i would like to extrat dimension 1 and dimension 3 from v. and the index in the discared dimension 2 is 11.
sub extract
dim i1 as integer 'for loop through dimension 1
dim i2 as integer 'for loop through dimension 3
dim d1 as integer 'index in dimension 2
d1=11
redim vn(1 to ubound(v,1),1 to ubound (v,3))
for i1 = 1 to ubound(v,1)
for i2= 1 to ubound(v,3)
vn(i1,i2)=v(i1,d1,i2)
next i2
next i1
end sub
I can extract dimensions from array, if i know which dimensions i need and the index (d1) in the discarded dimensions. however, i need to leave that to the users to decide. what i want is a function like that:
function extract(i1 as integer, i2 as intger, paramarray ov()) as variant
=extract(the_first_dimension_to_keep,the_second_dimension_to_keep,[index_in_the_first_discard_dimension,index_in_the_second_discard_dimension,...])
Keeping in mind that the origional array can have more than 3 dimensions, so list all the possibility in the code is not possible.
Any solution?
The quickest way would be to read the array with a pointer and increment the pointer value by an algorithmic value based on the number of dimensions and number of elements in each. This site has an excellent tutorial on managing pointers to arrays: http://bytecomb.com/vba-internals-getting-pointers. However, it'd be one mighty coding task - just dimensioning the rgabounds of your SAFEARRAY for the memory read would be a task - and if your array values were Strings, it'd be of an order of magnitude mightier.
An easier, though doubtless slower, option would be to exploit the For Each looping method, which can be applied to an array. Its looping sequence is like so:
arr(1,1)
arr(2,1)
arr(3,1)
arr(1,2)
arr(2,2)
arr(3,2)
etc.
So you'd only need a simple odometer-style index counter.
You could basically iterate every element in the array and if the combination of indexes matched what you wanted, you'd read the element into your extraction array. That would be a much easier task. The code below shows you how you could do this on a multi-dimensional array of unknown dimensions.
Option Explicit
Private Type ArrayBounds
Lower As Long
Upper As Long
Index As Long
WantedDimension As Boolean
DiscardIndex As Long
End Type
Public Sub RunMe()
Dim arr As Variant
Dim result As Variant
arr = CreateDummyArray
result = Extract(arr, 1, 3, 11)
End Sub
Private Function Extract(arr As Variant, i1 As Integer, i2 As Integer, ParamArray ov() As Variant) As Variant
Dim d As Long
Dim bounds() As ArrayBounds
Dim i As Long
Dim v As Variant
Dim ovIndex As Long
Dim doExtract As Boolean
Dim result() As Variant
'Dimension the output array
ReDim result(LBound(arr, i1) To UBound(arr, i1), LBound(arr, i2) To UBound(arr, i2))
'Get no. of dimensions in array
d = GetDimension(arr)
'Now we know the number of dimensions,
'we can check that the passed parameters are correct
If (i1 < 1 Or i1 > d) Or (i2 < 1 Or i2 > d) Then
MsgBox "i1/i2 - out of range"
Exit Function
End If
If UBound(ov) - LBound(ov) + 1 <> d - 2 Then
MsgBox "ov - wrong number of args"
Exit Function
End If
'Resise and populate the bounds type array
ReDim bounds(1 To d)
ovIndex = LBound(ov)
For i = 1 To d
With bounds(i)
.Lower = LBound(arr, i)
.Upper = UBound(arr, i)
.Index = .Lower
.WantedDimension = (i = i1) Or (i = i2)
If Not .WantedDimension Then
.DiscardIndex = ov(ovIndex)
ovIndex = ovIndex + 1
'Check index is in range
If .DiscardIndex < .Lower Or .DiscardIndex > .Upper Then
MsgBox "ov - out of range"
Exit Function
End If
End If
End With
Next
'Iterate each member of the multi-dimensional array with a For Each
For Each v In arr
'Check if this combination of indexes is wanted for extract
doExtract = True
For i = 1 To d
With bounds(i)
If Not .WantedDimension And .Index <> .DiscardIndex Then
doExtract = False
Exit For
End If
End With
Next
'Write value into output array
If doExtract Then
result(bounds(i1).Index, bounds(i2).Index) = v
End If
'Increment the dimension index
For i = 1 To d
With bounds(i)
.Index = .Index + 1
If .Index > .Upper Then .Index = .Lower Else Exit For
End With
Next
Next
Extract = result
End Function
Private Function GetDimension(arr As Variant) As Long
'Helper function to obtain number of dimensions
Dim i As Long
Dim test As Long
On Error GoTo GotIt
For i = 1 To 60000
test = LBound(arr, i)
Next
Exit Function
GotIt:
GetDimension = i - 1
End Function
I want to apply the WorksheetFunction.Small on another array as such:
ReDim ArrSmall(Iterations, 20)
For l = 1 To Iterations
For k = 1 To 20
ArrSmall(l, k) = WorksheetFunction.Small(ArrResult(l, k), l)
Next k
Next l
I know this part: ArrResult(l,k), is wrong because it asks for a range instead of a single number which I'm inputting. However, I am unsure how to define the range in the code.
Is this possible or do I have to output the values on a TempSheet, then back into an array? I think a solution is to call the whole column of the array but I do not know how.
EDIT:
I managed to write a dummy code which does exactly what I want but the weird part is when I apply the same to my original code, all the values get mixed up (it literally makes up values AFAIK). See below for code:
Sub test()
ReDim ArrTest(10, 1)
ReDim ArrSmall(10, 1)
ArrTest = Range("A1:A10")
For i = 1 To 10
ArrSmall(i, 1) = WorksheetFunction.Small(ArrTest, i)
Cells(i, 2) = ArrTest(i, 1)
Cells(i, 3) = ArrSmall(i, 1)
Next i
Trying to clear the whole array before a new loop. Maybe that fixes it...
If you were looking to take the smallest value of each column (which is the same as Min) from say A1:T20 then you could use TRANPOSE (to work with columns rather than rows) and then INDEX to separate each column, i.e.
The IF test is to avoid applying SMALL to an empty array (else an error results).
Sub B()
Dim ArrSmall(1 To 1, 1 To 20)
Dim lngCnt As Long
Dim ArrResult
ArrResult = Application.Transpose([a1:t20].Value2)
For lngCnt = 1 To UBound(ArrResult, 2)
If Application.Count(Application.Index(ArrResult, lngCnt)) > 0 Then _
ArrSmall(1, lngCnt) = WorksheetFunction.Small(Application.Index(ArrResult, lngCnt), 1)
Next
End Sub
I have a very large array in VBA which includes a lot of 0 values that I'd like to remove. Something like this:
A B C 12345
D E F 848349
G H I 0
J K L 0
M N O 0
P Q R 4352
S T U 0
V W X 0
I would like to be able to quickly/easily strip out all rows from this array that have a zero in the 4th column, resulting in something like this:
A B C 12345
D E F 848349
P Q R 4352
This array has 100,000 or so rows, that hopefully gets down to a number closer to 20,000 or 30,000 rows instead after processing.
I assume iterating through every entry will prove very time-consuming.
Is there another way that is faster?
I'm not aware of any other way in VBA than to loop through the array and write another array/list.
What makes it trickier is that your array looks to be two-dimensional and VBA will only allow you to redim the last dimension. From the look of your data, you'd want to redim the first dimension as you iterate through your array.
There are several solutions:
Iterate your data twice - once to get the array size (and probably to store the relevant row numbers) and a second time to transfer the raw data into your new data.
Iterate once and just reverse your dimensions (ie row is last).
Use an array of arrays, so that each array only has one dimension).
Use a Collection which doesn't need to be dimensioned - this would be my preferred option.
Option 4 would look like this (I've assumed your array is zero based):
Dim resultList As Collection
Dim r As Long
Set resultList = New Collection
For r = 0 To UBound(raw, 1)
If raw(r, 3) <> 0 Then
resultList.Add Array(raw(r, 0), raw(r, 1), raw(r, 2), raw(r, 3))
End If
Next
If you have to write to a new array, then here's an example of Option 1:
Dim rowList As Collection
Dim result() As Variant
Dim r As Long
Dim c As Long
Dim v As Variant
Set rowList = New Collection
For r = 0 To UBound(raw, 1)
If raw(r, 3) <> 0 Then
rowList.Add r
End If
Next
ReDim result(rowList.Count - 1, 3) As Variant
c = 0
For Each v In rowList
result(c, 0) = raw(v, 0)
result(c, 1) = raw(v, 1)
result(c, 2) = raw(v, 2)
result(c, 3) = raw(v, 3)
c = c + 1
Next
Okay, it's all off-sheet, so all the arrays are zero-based. To test this set-up, I created a worksheet with four columns, as per your data and using random numbers in the fourth column. I saved this to a text file (TestFile.txt), then read it in to be able to get a zero-based array (Excel ranges are 1-based when you take them into an array). I saved 150000 rows to the text file to properly stress the routine. Yes, I have an SSD and that would affect the 2s run time, but I'd still expect it to run in <10s on a spinning HDD, I think.
Anyway, here's the code (requires a VBA reference to Microsoft Scripting Runtime purely to read in the file):
Public Function ReturnFilteredArray(arrSource As Variant, _
strValueToFilterOut As String) As Variant
Dim arrDestination As Variant
Dim lngSrcCounter As Long
Dim lngDestCounter As Long
ReDim arrDestination(UBound(arrSource, 1) + 1, UBound(arrSource, 2) + 1)
lngDestCounter = 1
For lngSrcCounter = LBound(arrSource, 1) To UBound(arrSource, 1)
' Assuming the array dimensions are (100000, 3)
If CStr(arrSource(lngSrcCounter, 3)) <> strValueToFilterOut Then
' Hit an element we want to include
arrDestination(lngDestCounter, 1) = arrSource(lngSrcCounter, 0)
arrDestination(lngDestCounter, 2) = arrSource(lngSrcCounter, 1)
arrDestination(lngDestCounter, 3) = arrSource(lngSrcCounter, 2)
arrDestination(lngDestCounter, 4) = arrSource(lngSrcCounter, 3)
lngDestCounter = lngDestCounter + 1
End If
Next
ReturnFilteredArray = arrDestination
End Function
Sub TestRun()
Dim fso As FileSystemObject
Dim txs As TextStream
Dim arr As Variant
Dim arr2 As Variant
Dim lngCounter As Long
Debug.Print Now()
Set fso = New FileSystemObject
Set txs = fso.OpenTextFile("E:\Users\Thingy\Desktop\TestFile.txt", ForReading)
arr = Split(txs.ReadAll, vbNewLine)
ReDim arr2(UBound(arr), 3)
For lngCounter = 0 To UBound(arr) - 1
arr2(lngCounter, 0) = Split(arr(lngCounter), vbTab)(0)
arr2(lngCounter, 1) = Split(arr(lngCounter), vbTab)(1)
arr2(lngCounter, 2) = Split(arr(lngCounter), vbTab)(2)
arr2(lngCounter, 3) = Split(arr(lngCounter), vbTab)(3)
Next
arr2 = ReturnFilteredArray(arr2, "0")
Range("L2").Resize(UBound(arr2, 1), 5) = arr2
Debug.Print Now()
End Sub
There are a number of assumptions in there, not least the dimensions. Note the difference in the second dimension counter between arrDestination and arrSource. That's to do with Excel being 1-based and normal arrays being 0-based.
Also, when I'm writing out the array, I needed to bump up the second dimension to 5 in order to get all of the array out to the sheet. I wasn't able to trim off the empty elements since ReDim Preserve only works on the uppermost dimension (columns) and it's the first dimension (rows) that's changing here.
Anywho, this should serve as a reminder that despite its faults Excel is pretty amazing.
Here's what I'm trying to do:
Suppose that you have a dynamic array whose dimensions can be from 0x6 up to 10x6 (meaning we can have rows anywhere from 0 to 10, but columns are always 6). I have been desperately trying to create a function (and then bind it to a macro) that will use as argument this first array, and will create a second array as output, whose elements will be the returns of the first array. For example, if we have the simple case of 1x6, then the output array's elements are five and in each case are given by the formula (x_i+1 - x_i)/x_i, i=1, 2, ..., 6. Additionally, the function must be able to bypass any missing values from the input array and ignore the corresponding non-existent return values. The entire thing must be done in VBA script.
It's been two days since I have been searching frantically for some help, but the problem is that I have no idea whatsoever about programming in VBA (I usually use other languages like MATLAB or Mathematica) so this is extremely hard for me. Any solutions that I have found I wasn't able to put together and achieve my goal. Any help is greatly appreciated.
Because you provided no code, I cannot determine exactly what you want to do, but here is an example of passing an array and returning an array that you should be able to extrapolate.
Edit: Just for fun, updated this to work for up to 3 dimensional arrays.
Public Sub Test()
'Defines testArray as Variant 0 to 10
Dim testArray(0 To 1, 0 To 6) As Long
Dim returnArray() As Long
Dim i As Long
Debug.Print UBound(testArray, 2)
'Populates testArray with Longs
For i = 0 To UBound(testArray, 1)
For j = 0 To UBound(testArray, 2)
testArray(i, j) = (i + j) * 2
Next
Next
'Passes testArray and returns ParseArray
returnArray = addOne(testArray)
End Sub
Public Function addOne(arrValues() As Long) As Variant
Dim arrCopy() As Long
Dim dimensionNum As Long, ErrorCheck As Long
On Error Resume Next
For dimensionNum = 1 To 60000
ErrorCheck = LBound(arrValues, dimensionNum)
If Err.Number <> 0 Then
dimensionNum = dimensionNum - 1
Exit For
End If
Next
Dim i As Long, j As Long, k As Long
'Copies passed array to avoid updating passed array directly
arrCopy = arrValues
'Adds 1 to each element of the array.
If dimensionNum = 1 Then
For i = LBound(arrCopy) To UBound(arrCopy)
arrCopy(i) = arrCopy(i) + 1
Next
ElseIf dimensionNum = 2 Then
For i = LBound(arrCopy) To UBound(arrCopy)
For j = LBound(arrCopy, 2) To UBound(arrCopy, 2)
arrCopy(i, j) = arrCopy(i, j) + 1
Next
Next
ElseIf dimensionNum = 3 Then
For i = LBound(arrCopy) To UBound(arrCopy)
For j = LBound(arrCopy, 2) To UBound(arrCopy, 2)
For k = LBound(arrCopy, 3) To UBound(arrCopy, 3)
arrCopy(i, j, k) = arrCopy(i, j, k) + 1
Next
Next
Next
Else
MsgBox "Add function only works for three dimensions or fewer arrays"
End If
addOne = arrCopy
End Function