printing substrings in a file - c

Question

So I want to write a program which would print out a text line that contains a certain word from a file. e.g. if I was looking for a word 'linux' it would print out
2 computers called linux00, linux01 and linux02. 5 manager,"
said linux00. "Hello linux00," said 7 here to see us?" said
linux01. "Well," said the 10 linux02. "You're all going to be
unplugged," said 12 goooooooooooo..." said linux00.
from a story.txt:
Once upon a time, there were three little computers called
linux00, linux01 and linux02. One day, the nice computer manager
came into the Linux Laboratory. "Hello nice computer manager,"
said linux00. "Hello linux00," said the nice computer manager.
"What brings you here to see us?" said linux01. "Well," said the
nice computer manager, "I've got bad news and I've got good
news." "What's the bad news?" said linux02. "You're all going to be
unplugged," said the nice computer manager. "What's the
goooooooooooo..." said linux00.
Here's my code:
#include<stdio.h>
#include <stdlib.h>
#define ARR_LEN 100
int getLine(FILE * fin,char a[],int n)
{
int find = contains("linux", 5, a, ARR_LEN);
int count;
int i;
i = 0;
char c = getc(fin);
while(c != '\n')
{
a[i] = c;
// printf ("%c", a[i]);
//i = 0;
if (a[i] == EOF){
return EOF;
}
if (find == 1)
{
printf("%c", c);
c = getc(fin);
}
i = i + 1;
}
if(a[i]=='\n')
{
if ((i - 1) > ARR_LEN) {
printf("warning msg: length is over array bounds\n");
}
// printf("length of line is: %d\n", i - 1);
//printf("%c", a[i]);
i = i + 1;
//printf("\n");
return i - 1;
}
}
int contains(char target[], int m, char source[], int n) {
int flag = 0; // the source originally does not contain the target
int i;
for(i = 0; i < n; i++) { // go through each character of the source string
int targetIndex = 0;
int j;
/*check if the preceding characters of the source string are a substring
that matches the target string*/
for(j = i; j < n && targetIndex < m; j++) {
if(target[targetIndex] == source[j]) {
targetIndex += 1;
if(targetIndex == m) { // the 'target' has been fully found
flag = 1;
break;
}
}
else
{
break;
}
}
if(flag == 1) // 'target' is already found, no need to search further
{
break;
}
}
return flag;
}
main(int argc,char ** argv)
{
setbuf(stdout,NULL);
char a[ARR_LEN];
FILE * fin;
if(argc<2){
printf("wrong number of arguments\n");
exit(0);
}
fin = fopen(argv[1], "r");
if (fin == NULL) {
printf("Cannot open %s\n", fin);
exit(0);
}
int t = 0;
int j = 0;
int find = contains("linux", 5, a, ARR_LEN);
while (j != EOF)
{
t = t + 1;
printf("%d ", t);
j = getLine(fin,a,ARR_LEN);
printf("\n");
}
fclose(fin);
}
The getLine function is alright and it prints out a text with a line number in front all good. But the problem is with this
if (find == 1)
{
printf("%c", c);
c = getc(fin);
}
part, where I want the program to only print out the line if "contains" finds a match in that line.
Thanks for any help & sorry for a long post!!

Answer 1

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
int main()
{
char sentence[500];
char word[10] = "linux";
FILE* fp1 = fopen("strstr.txt","r");
if(fp1 == NULL)
{
printf("Failed to open file\n");
return 1;
}
while((fscanf(fp1,"%[^\n]\n",sentence)>0))
{
if(strstr(sentence,word)!=NULL)
printf("%s\n\n",sentence);
}
}