Trouble creating SQL Server 2012 trigger - sql-server

Question

I'm quite new at SQL Server 2012, and I'm having a strange problem.
I've developed an AFTER UPDATE trigger on a table in my database. I created the trigger in our development environment which is an express edition of SQL Server 2012, no problem.
Now I have to create the same trigger in our production environment which is SQL Server 2012 Enterprise edition, and the creation script never stops executing, and the trigger is not created.
Any ideas on what I need to do to create the trigger?
The script :
SET ANSI_NULLS ON
GO
SET QUOTED_IDENTIFIER ON
GO
alter TRIGGER [dbo].[til_aks_ved_betaling]
ON [dbo].[betalingsOplysningerbo]
AFTER UPDATE
AS
BEGIN
declare #snr uniqueidentifier
declare ##status varchar(1024)
SET NOCOUNT ON;
select
#snr = indmeldelse_snr
from
inserted
if UPDATE(betalingsDato)
begin
set ##status = 'Kalder med snr = ' + convert(varchar(38), #snr)
exec xp_logevent 60000, ##status , informational
exec overfoer_betalingsdato #snr
end
END

Answer 1

Try something like this....
ALTER TRIGGER [dbo].[til_aks_ved_betaling]
ON [dbo].[betalingsOplysningerbo]
AFTER UPDATE
AS
BEGIN
SET NOCOUNT ON;
declare #snr VARCHAR(1000);
declare #status varchar(1024);
DECLARE #Temp TABLE (indmeldelse_snr uniqueidentifier , [Status] varchar(1024))
INSERT INTO #Temp (indmeldelse_snr , [Status])
SELECT i.indmeldelse_snr , i.[Status]
FROM inserted i INNER JOIN deleted d
ON i.Snr = d.Snr AND i.betalingsDato <> d.betalingsDato
WHILE EXISTS(SELECT * FROM #Temp)
BEGIN
SELECT TOP 1 #snr = 'Kalder med snr = ' + convert(varchar(38),indmeldelse_snr )
,#status = [Status]
FROM #Temp
exec xp_logevent 60000, #status , informational
exec overfoer_betalingsdato #snr
DELETE FROM #Temp WHERE indmeldelse_snr = #snr
END
END

Answer 2

2 things here, common for new people, an UPDATE is a DELETE and an INSERT so make sure you have both before you assume it is an update. Second, these special tables will return all the rows affect by a single sql call. For example, Update Table SET This = 'That' will update every record in the table leaving INSERTED with MANY records.