Conditional cell template in ui-grid angularjs - angularjs

Question

How to add conditional when showing data in ui-grid cellTemplate below:
$scope.status = ['Active', 'Non Active', 'Deleted'];
$scope.gridOptions = {
columnDefs: [{
field: 'code'
}, {
field: 'name'
}, {
field: 'status',
cellTemplate: '<div>{{status[row.entity.status]}}</div>'
}]
};
The expected result should be row status show Active/NonActive/Deleted.
Here is the plunker
Thanks in advance.

Answer 1

You have to use externalScopes.
In your markup define the gridholder like this.
<div ui-grid="gridOptions" external-scopes="states" class="grid"></div>
And in your controller use this code:
var statusTxt = ['Active', 'Non Active', 'Deleted'];
$scope.states = {
showMe: function(val) {
return statusTxt[val];
}
};
var statusTemplate = '<div>{{getExternalScopes().showMe(row.entity.status)}}</div>';
$scope.gridOptions = {
columnDefs: [{
field: 'code'
}, {
field: 'name'
}, {
field: 'status',
cellTemplate: statusTemplate
}]
};
Or use an angular filter.
Note that this only renders text. The best approach would be to transform myData to have real text states before using it in ui-grid. Just in case you want to do some text based filtering later on.
Here is a Plunker

Answer 2

I would suggest to use ng-if solve this problem.
$scope.gridOptions = {
columnDefs: [{
field: 'code'
}, {
field: 'name'
}, {
field: 'status',
cellTemplate: '<div ng-if="row.entity.status == 0">Active</div><div ng-if="row.entity.status == 1">Non Active</div>'
}]
};

Answer 3

I have got another solution for you without using external scopes:
The Template looks like this:
var statusTemplate = '<div>{{COL_FIELD == 0 ? "Active" : (COL_FIELD == 1 ? "Non Active" : "Deleted")}}</div>';
Here is the plunker:
http://plnkr.co/edit/OZtU7GrOskdqwHW5FIVz?p=preview

Answer 4

Use a cellFilter.
columnDefs: [{
field: 'code'
}, {
field: 'name'
}, {
field: 'status',
cellFilter: 'mapStatus'
}]
app.filter('mapStatus', function() {
var statusMap = ['Active', 'Non Active', 'Deleted'];
return function(code) {
if (!angular.isDefined(code) || code < 0 || code > 2) {
return '';
} else {
return statusMap[code];
}
};
});
plunker

Answer 5

You must change your template. When you are referring to external scopes in angular-ui-grid you may use grid.appScope.
var statusTemplate = '<div>{{grid.appScope.status[row.entity.status]}}</div>';

Answer 6

Try below script. It is working for me.
app.controller('MainCtrl', ['$scope',
function($scope) {
var statusTxt = ['Active', 'Non Active', 'Deleted'];
$scope.showMe= function(val) {
return statusTxt[val];
};
var statusTemplate = '<div>{{grid.appScope.showMe(row.entity.status)}}</div>';
$scope.gridOptions = {
columnDefs: [{
field: 'code'
}, {
field: 'name'
}, {
field: 'status',
cellTemplate: statusTemplate
}]
};
$scope.gridOptions.data = [{
"code": "Cox",
"name": "Carney",
"status": 0
}, {
"code": "Lorraine",
"name": "Wise",
"status": 1
}, {
"code": "Nancy",
"name": "Waters",
"status": 2
}];
}
]);