How to format a bash array as a JSON array - arrays

Question

I have a bash array
X=("hello world" "goodnight moon")
That I want to turn into a json array
["hello world", "goodnight moon"]
Is there a good way for me to turn this into a json array of strings without looping over the keys in a subshell?
(for x in "${X[#]}"; do; echo $x | sed 's|.*|"&"|'; done) | jq -s '.'
This clearly doesn't work
echo "${X[#]}" | jq -s -R '.'

Answer 1

You can do this:
X=("hello world" "goodnight moon")
printf '%s\n' "${X[#]}" | jq -R . | jq -s .
output
[
"hello world",
"goodnight moon"
]

Answer 2

Since jq 1.6 you can do this:
jq --compact-output --null-input '$ARGS.positional' --args -- "${X[#]}"
giving:
["hello world","goodnight moon"]
This has the benefit that no escaping is required at all. It handles strings containing newlines, tabs, double quotes, backslashes and other control characters. (Well, it doesn't handle NUL characters but you can't have them in a bash array in the first place.)

Answer 3

This ...
X=("hello world" "goodnight moon" 'say "boo"' 'foo\bar')
json_array() {
echo -n '['
while [ $# -gt 0 ]; do
x=${1//\\/\\\\}
echo -n \"${x//\"/\\\"}\"
[ $# -gt 1 ] && echo -n ', '
shift
done
echo ']'
}
json_array "${X[#]}"
... yields:
["hello world", "goodnight moon", "say \"boo\"", "foo\\bar"]
If you are planning to do a lot of this (as your reluctance to use a subshell suggests) then something such as this that does not rely on any subprocess is likely to your advantage.

Answer 4

You can use:
X=("hello world" "goodnight moon")
sed 's/^/[/; s/,$/]/' <(printf '"%s",' "${X[#]}") | jq -s '.'
[
[
"hello world",
"goodnight moon"
]
]

Answer 5

If the values do not contain ASCII control characters, which have to be escaped in strings in valid JSON, you can also use sed:
$ X=("hello world" "goodnight moon")
$ printf %s\\n "${X[#]}"|sed 's/["\]/\\&/g;s/.*/"&"/;1s/^/[/;$s/$/]/;$!s/$/,/'
["hello world",
"goodnight moon"]
If the values contain ASCII control characters, you can do something like this:
X=($'a\ta' $'a\n\\\"')
for((i=0;i<${#X[#]};i++));do
[ $i = 0 ]&&printf \[
printf \"
e=${X[i]}
e=${e//\\/\\\\}
e=${e//\"/\\\"}
for((j=0;j<${#e};j++));do
c=${e:j:1}
if [[ $c = [[:cntrl:]] ]];then
printf '\\u%04x' "'$c"
else
printf %s "$c"
fi
done
printf \"
if((i<=${#X[#]}-2));then
printf ,
else
printf \]
fi
done

Answer 6

As improve of answer
https://stackoverflow.com/a/26809278/16566807
Script produce few formats which could be usefull when include. Script meets BASH spec, checked with shellcheck.
#!/bin/bash
#
#
X=("hello world" "goodnight moon" 'say "boo"' 'foo\bar')
#
# set parameter to define purpose: return_format
# php5 -> for 5.x
# -> https://stackoverflow.com/questions/7073672/how-to-load-return-array-from-a-php-file/7073686
# php -> for 7.x and greater
# json -> for $array=#file_get_contents($f); json_decode($array, true);
# /none/ -> for JS to JSON.Parse(myJSON);
# function call with array as parameter: return_array "${array[#]}"
return_array() {
rf="${return_format}"
if [[ $rf = "php5" ]]; then
q=("<?php return array(" ");")
elif [[ $rf = "php" ]];then
q=("<?php return [" "];")
elif [[ $rf = "json" ]];then
q=("{" "}")
else
q=("[" "]")
fi
echo -n "${q[0]}"
while [[ $# -gt 0 ]]; do
x=${1//\\/\\\\}
echo -n "\"${x//\"/\\\"}\""
[[ $# -gt 1 ]] && echo -n ', '
shift
done
echo "${q[1]}"
}
echo "PHP 5.x"
return_format="php5"
return_array "${X[#]}"
echo "PHP 7.x"
return_format="php"
return_array "${X[#]}"
echo "JSON for PHP"
return_format="json"
return_array "${X[#]}"
echo "JSON for JS"
return_format=
return_array "${X[#]}"
will produce output:
PHP 5.x
<?php return array("hello world", "goodnight moon", "say \"boo\"", "foo\\bar");
PHP 7.x
<?php return ["hello world", "goodnight moon", "say \"boo\"", "foo\\bar"];
JSON for PHP
{"hello world", "goodnight moon", "say \"boo\"", "foo\\bar"}
JSON for JS
["hello world", "goodnight moon", "say \"boo\"", "foo\\bar"]