how to make a christmas tree using loop in c program - c

Question

I'm a freshmen student and we have an activity in intro pro.. We were tasked to create a Christmas tree using a loop...
I have my code here:
#include<stdio.h>
int main ()
{
int rows,a,b,space;
clrscr();
printf("Enter a number of rows:");
scanf("%d",&rows);
space=rows-1
for(b=space;b>=1;b--)
{
for(a=rows;a>=1;a--)
space--;
printf("");
for(a=2*(rows-b)-1;a>=1;a--)
printf("*",a);
printf("\n");
space = space-1;
}
getche();
return 0;
}
This code was given to us by our professor... the program runs, but the output is wrong. Can you help me?
when i run this program, the output was like this:
*
***
*****
******
*******

Answer 1

You have to find a pattern. Say you want a tree with n rows. Last row is going to have 2n-1 stars. Row before it will have 2n-3 and so on. To print a row, first you print a number of spaces, then a number of stars. For last row, you print 0 spaces and 2n-1 stars. For row before it, you print 1 space and 2n-3 stars and so on.
for(int i = 0; i < n; i++)
{ for(int j = i + 1; j < n; j++)
printf(" ");
for(int j = 0; j <= 2*i; j++)
printf("*");
if(i < n - 1) puts("");
}

Answer 2

The Code is a little bit to messed up for me, but this should work:
#include<stdio.h>
int main() {
/*Variables*/
int rows, starNumber, spaceNumber;
int rowCount, spaceCount, starCount, treeTrunkCount, treeTrunkSpaceCount;
printf("Enter Rows:\n>");
scanf("%d",&rows);
for(rowCount = 1; rowCount <= rows; rowCount++) {
starNumber = rowCount * 2 - 1;
spaceNumber = rowCount + rows - starNumber;
for(spaceCount = 0; spaceCount < spaceNumber; spaceCount++)
printf(" ");
for(starCount = 0; starCount < starNumber; starCount++)
printf("%c",'*');
printf("\n");
}
for(treeTrunkCount = 0; treeTrunkCount < 3; treeTrunkCount++) {
for(treeTrunkSpaceCount = 0; treeTrunkSpaceCount < (rows * 2 + 1)/2; treeTrunkSpaceCount++)
printf(" ");
printf("%c\n",'*');
}
}

Answer 3

This is the simplest solution to your program..
#include <stdio.h>
int main()
{
int i=-1,j=0,rows;
printf("Enter Rows:\n");
scanf("%d",&rows);
while(j++<rows) // Moving pointer for the first '*'
{
printf(" ");
}
printf("*"); // This prints the first '*'
while(++i<rows)
{
for(j=-2;++j<rows-i;) // This loop will print Spaces before '*' on each row
printf(" ");
for(j=0;++j<2*i;) // This loop will print * on each row
{
printf("*");
}
printf("\n"); // This printf will take you to the next Line
}
}

Answer 4

This is the shortest and simplest solution for your question:
#include<stdio.h>
#include<conio.h>
void main(){
int count;
int i,j;
printf("enter the numbers of line");
scanf("%d",&count);
for(i=1;i<=count;i++){
for(j=1;j<=i;j++){
printf("*");
}
printf("\n");
}
getch();
}

Answer 5

You forgot a space between "".
for(a=rows;a>=1;a--)
space--;
printf("");
should be
for(a=rows;a>=1;a--)
space--;
printf(" ");

Answer 6

#include <stdio.h>
int main() {
int n = 50;
for (int i = 0; i <= n; ++i) {
for (int k = i; k < n; ++k)
printf(" ");
for (int j = 0; j < i; ++j)
printf("*");
for (int j = 1; j < i; ++j)
printf("*");
printf("\n");
}
for (int l = 1; l < n/2; ++l) {
for (int i = 1; i < n; ++i)
printf(" ");
printf("[|]\n");
}
return 0;
}

Answer 7

A simple tree can be made up with for loop, Christmas may need more symbol...
//Linux C program to print a tree
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#include <unistd.h>
#include <sys/ioctl.h>
#include <string.h>
int pcenter(char *s) {
struct winsize w;
ioctl(STDOUT_FILENO, TIOCGWINSZ, &w);
int ct = w.ws_col;
int sl = strlen(s) / 2;
printf("%*s%*s\n", ct / 2 + sl, s, ct / 2 - sl, "");
return 0;
}
int ptree(char s, char t, int l, int r) {
int i;
for (i = 1; i <= l; i++) {
int j = 2 * i - 1;
char *p = malloc(j);
memset(p, s, j);
pcenter(p);
free(p);
}
for (i = 1; i <= r; i++) {
int j = 1;
char *p = malloc(j);
memset(p, t, j);
pcenter(p);
free(p);
}
return 0;
}
int main() {
// system("clear");
ptree('*', '|', 10, 5);
return 0;
}

Answer 8

#include<stdio.h>
main()
{
int n,i, j, space=1;
printf("Enter the number of rows: ");
scanf("%d",&n);
space=n-1;
for(i=1;i<=n;i++)
{
for(j=1;j<=space;j++)
{
printf(" ");
}
space--;
for(j=1;j<=2*i-1;j++)
{
printf("*");
}
printf("\n");
}
for(i=1;i<=n-3;i++)
{
for(j=1;j<=10;j++)
{
printf(" ");
}
for(j=1;j<=1;j++)
{
printf("*");
}
for(j=1;j<=1;j++)
{
printf("*");
}
for(j=1;j<=1;j++)
{
printf("*");
}
printf("\n");
}
}

Answer 9

#include<stdio.h>
int main()
{
int i,j,k,l=1,a,b;
for(i=8;i>=0;i--)
{
for(j=0;j<=i;j++)
{
printf(" ");
}
k=0 ;
while(k<l)
{
printf("*");
k=k+1;
}
l=l+2;
printf("\n");
}
i=8;
for(b=0;b<=3;b++)
{
for(a=0;a<=i-1;a++)
{
printf(" ");
}
printf("***");
printf("\n");
}
}