C: Converting int to String [closed] - c

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In my code, I'd like to use string that denotes Will, Bob, Billy, Ryan or Ed instead of int. Specifically, using N strings S[1],S[2]...S[N] where S[I] the names above.
And also, input N is limited as following: (1 ≤ N ≤ 100,000)
#include <stdio.h>
int main(void)
{
int input_num=0;
int isWill = 0;
int isBob = 0;
int isBilly = 0;
int isRyan = 0;
int isEd = 0;
int n=0;
scanf("%d", input_num);
printf("%d", input_num);
for(n;n<input_num;n++)
{
char tmp[100,000];
scanf("%s", tmp);
if(tmp == "Will")
isWill = 1;
else if(tmp == "Bob")
isBob = 1;
else if(tmp == "Billy")
isBlue = 1;
else if(tmp == "Ryan")
isRyan = 1;
else if(tmp == "Ed")
isEd = 1;
}
//end of input
if(isWill == 0)
printf("Will\n");
if(isBob == 0)
printf("Bob\n");
if(isBilly == 0)
printf("Billy\n");
if(isRyan == 0)
printf("Ryan\n");
if(isEd == 0)
printf("Ed\n");
return 0;
}

Answer 1

To compare strings, you need to use the strcmp library function, which returns 0 if the two argument strings are equal:
if ( strcmp( tmp, "Will" ) == 0 )
// tmp contains the string "Will"
If you want an array of strings, you can do it one of two ways. You can declare a 2d array, where the first dimension is tne number of names, and the second dimension is the max length of a name:
char names[NUMBER_OF_NAMES][MAX_NAME_LENGTH+1];
To copy a string, use strcmp:
strcmp( names[0], "Will" );
strcmp( names[1], "Bob" );
// etc.
Or, you can declare a 1D array, where each element is a pointer to a string:
char *names[NUMBER_OF_NAMES];
names[0] = "Will";
names[1] = "Bob";
Note that you're assigning a pointer value to names[i]; you're not copying the string contents to names[i].
Finally, C doesn't recognize integer literals like 100,000; you'll want to declare your tmp buffer as
char tmp[100000];
although that's somewhat large for a string buffer.

Answer 2

Several things not quite as i would write them.
I had some minutes to spare and wrote a compiling example.
Maybe your problems can be solved by this.
char * colortext[] =
{
"unknown",
"white",
"black",
"blue",
"red",
"yellow"
};
typedef enum color {
unknown = 0,
white,
black,
blue,
red,
yellow
};
typedef struct
{
int number;
char name[200];
color team;
}Player;
typedef struct
{
char * name;
color team;
}Autoassign;
Autoassign autoassign[] =
{
{"Will", white},
{"Bob", black},
{"Billy", blue},
{"Ryan", red},
{"Ed", yellow}
};
int autoassignLength = sizeof(autoassign) / sizeof(autoassign[0]);
int Player_print(Player * player)
{
int e = 0;
printf("\n");
printf("Player %i Profile:\n", player->number);
printf("Name: '%s'\n", player->name);
printf("Team: '%s'\n", colortext[player->team]);
printf("\n");
return e;
}
int Player_scan(Player * player, int number)
{
int e = 0;
int i;
printf("Input Player Name: ");
scanf("%s", player->name);
player->number = number;
player->team = unknown;
for(i = 0; i < autoassignLength; ++i)
{
if(0 == strcmp(player->name,autoassign[i].name))
{
player->team = autoassign[i].team;
break;
}
}
return e;
}
int main(int argc, char ** argv)
{
int i;
int input_num, n;
Player players[10];
printf("How many Players? ");
scanf("%d", &input_num);
for(n = 0; n < input_num ; n++)
{
Player_scan(&players[n], n+1);
}
for(n = 0; n < input_num ; n++)
{
Player_print(&players[n]);
}
return 0;
}

Answer 3

If you want to make compare strings that's not the way to go.
Use string.h library to be able to use the function strcmp .
To use this functions type strcmp(string1, string2)
Just remember that strcmp will return 0 if the strings are equal.
So what you want to do is use if(!strcmp("Will", tmp)) to enter the if when the strings are the same.
You also need to change char tmp[100,000] to char tmp[100000], for this is the supported format in C.
Hope this helps.